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An inductor, a capacitor, and a resistor are all connected in series across an ac source. If the resistance, inductance, and capacitance are all doubled, by what factor does each of the following quantities change? Indicate whether they increase or decrease: (a) the resonance angular frequency; (b) the inductive reactance; (c) the capacitive reactance. (d) Does the impedance double?

Short Answer

Expert verified

a) Resonance angular frequency is halved

b) The inductive reactance doubles

c) Capacitive reactance halves and

d) Z increases without doubling.

Step by step solution

01

Step-1: Formulas used  

Resonance angular frequency is given by Ó¬=1LC.The reactance are given by XL=Ó¬Lfor inductor and XC=1Ó¬Cfor capacitor.

Z=R2+(XL-XC))2, where Z is the impedance

02

Step-2: Calculations for resonance angular frequency

Ó¬1=1LC

Now, all the parameters are doubled

R2=2R1C2=2C1L2=2L1

Find the new resonance frequency

Ó¬=12L2C=14LC=12LC=Ó¬12

Therefore, resonance angular frequency is halved.

03

Step-3: Calculations of capacitive reactance, inductive reactance and impedance.

First calculate the inductive reactance;

XL2=Ó¬L2=Ó¬2L1=2XL1

And then the capacitive reactance;

XC2=1Ó¬C2=1Ó¬2C1=XC12

Then calculate the impedance;

Z=R2+XL-XC2Z=2R2+2XL-XC)22Z=2R2+XL-XC)42

Therefore, a) resonance angular frequency is halved, b) the inductive reactance doubles, c) capacitive reactance halves and d) Z increases without doubling.

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