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Chapter 4: Q15DQ (page 1044)

A circuit consists of a light bulb, a capacitor, and an inductor connected in series to an ac source. Is it possible for both the capacitor and the inductor to be removed and the brightness of the bulb to remain the same? Explain.

Short Answer

Expert verified

The brightness of the bulb will remain the same when the capacitor and the inductor are removed.

Step by step solution

01

Step-1: Formulas used  

The power dissipated in the bulb is given byP=irms2R.

Use impedance to get the current in the circuit byirms=VZ.

The impedance is given byZ=R2+(XL-XC))2.

02

Step-2: Calculations

When the capacitor and the inductor are removed,

XC=XL=0Z=R2+02+02=R2=R

As shown, the impedance is same for the resistance R and hence the resistance is same. Therefore, the power consumed by the bulb is the same, and hence, the brightness of the bulb will remain the same.

Therefore, the brightness of the bulb will remain the same.

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