/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} 43E. A uniform rectangular coil of to... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A uniform rectangular coil of total mass \(212\;{\rm{g}}\) and dimensions \(0.5\;{\rm{m}} \times {\rm{1}}\;{\rm{m}}\) is oriented with its plane parallel to a uniform \(3\;{\rm{T}}\) magnetic field (Fig. E27.43). A current of \(2\;{\rm{A}}\) is suddenly started in the coil.

(a) About which axis (\({A_1}\) or \({A_2}\)) will the coil begin to rotate? Why?

(b) Find the initial angular acceleration of the coil just after the current is started.

Short Answer

Expert verified

(a) The rotation axis of the coil is \({A_2}\).

Step by step solution

01

Given data

The mass of rectangular coil

\(m = 212\;{\rm{g}}\)

The length of the coil is

\(l = {\rm{1}}\;{\rm{m}}\)

The width of the coil is

\(w = 0.5\;{\rm{m}}\)

The current through the coil is

\(I = 2\;{\rm{A}}\)

The applied magnetic field is

\(B = 3\;{\rm{T}}\)

02

Direction of torque

The direction of torque applied by a magnetic field on a current carrying coil is the direction of the cross product of the magnetic moment of the coil and the magnetic field.

03

(a) Determination of the axis of rotation of the coil

The magnetic moment of the coil directed either out of the page or into the page, depending on the direction of the current. The magnetic field is directed upward. Thus, the cross product of the magnetic moment and the magnetic is directed either to the right or to the left. Hence, the rotation axis is \({A_2}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An idealized ammeter is connected to a battery as shown in Fig.

E25.28. Find (a) the reading of the ammeter, (b) the current through the4.00Ω

resistor, (c) the terminal voltage of the battery.

Fig. E25.28.

The battery for a certain cell phone is rated at3.70V.According to the manufacturer it can produce3.15×104Jof electrical energy, enough for 2.25hof operation, before needing to be recharged. Find the average current that this cell phone draws when turned on.

The text states that good thermal conductors are also good electrical conductors. If so, why don’t the cords used to connect toasters, irons, and similar heat-producing appliances get hot by conduction of heat from the heating element?

In the circuit shown in Fig. E25.30, the 16.0-V battery is removed and reinserted with the opposite polarity, so that its negative terminal is now next to point a. Find (a) the current in the circuit (magnitude anddirection); (b) the terminal voltage Vbaof the 16.0-V battery; (c) the potential difference Vacof point awith respect to point c. (d) Graph the potential rises and drops in this circuit (see Fig. 25.20).

A 12.4-µF capacitor is connected through a 0.895-MΩ resistor to a constant potential difference of 60.0 V. (a) Compute the charge on the capacitor at the following times after the connections are made: 0, 5.0 s, 10.0 s, 20.0 s, and 100.0 s. (b) Compute the charging currents at the same instants. (c) Graph the results of parts (a) and (b) for t between 0 and 20 s

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.