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In beta decay, a nucleus emits an electron. A \(^{210}\)Bi (bismuth) nucleus at rest undergoes beta decay to \(^{210}\)Po (polonium). Suppose the emitted electron moves to the right with a momentum of \(5.60 \times 10^{-22} kg \cdot m/s\). The \(^{210}\)Po nucleus, with mass \(3.50 \times 10^{-25}\) kg, recoils to the left at a speed of \(1.14 \times10^3 m/s\). Momentum conservation requires that a second particle, called an antineutrino, must also be emitted. Calculate the magnitude and direction of the momentum of the antineutrino that is emitted in this decay.

Short Answer

Expert verified
The antineutrino has a momentum of \(1.61 \times 10^{-22} \text{ kg} \cdot \text{ m/s}\) to the left.

Step by step solution

01

Understand Momentum Conservation

According to the law of momentum conservation, the total momentum before an event must be equal to the total momentum after the event. In this case, before the decay, the momentum is zero since the nucleus is at rest.
02

Express Total Momentum Equation

For the decay, the total momentum of the system after the decay must also be zero. Therefore, the sum of the momentum of the emitted electron, the recoiling polonium nucleus, and the antineutrino must be zero:\[p_{electron} + p_{Po} + p_{antineutrino} = 0\]
03

Substitue Known Values

Given values: - Momentum of the electron: \((5.60 \times 10^{-22} \text{ kg} \cdot \text{m/s}\) to the right means \(+5.60 \times 10^{-22} \text{ kg} \cdot \text{m/s}\)).- Momentum of Po: calculated using \(p_{Po} = m_{Po} imes v_{Po} = (3.50 \times 10^{-25} \text{ kg})(1.14 \times 10^3 \text{ m/s}) = -3.99 \times 10^{-22} \text{ kg} \cdot \text{ m/s}\) (to the left, thus negative).
04

Rearrange for Antineutrino Momentum

Rearrange the equation to solve for \(p_{antineutrino}\):\[p_{antineutrino} = -(p_{electron} + p_{Po})\]
05

Calculate Antineutrino Momentum

Substitute the known values into the rearranged equation:\[p_{antineutrino} = -((5.60 \times 10^{-22}) + (-3.99 \times 10^{-22}))\]Solve to find:\[p_{antineutrino} = - (5.60 \times 10^{-22} - 3.99 \times 10^{-22})\]\[p_{antineutrino} = - (1.61 \times 10^{-22} \text{ kg} \cdot \text{ m/s})\]
06

Determine Direction of Antineutrino Momentum

Given that \(p_{antineutrino} = -1.61 \times 10^{-22} \text{ kg} \cdot \text{ m/s}\), the negative sign indicates that the antineutrino is moving in the opposite direction to that assigned as positive, i.e., to the left.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum Conservation
Momentum conservation is a fundamental principle in physics. It tells us that the total momentum of a closed system remains constant over time, provided that no external forces act on it. In simple terms, this means that the momentum before an event (like a collision or decay) is equal to the momentum after the event.

In the context of beta decay, let's explore how momentum gets conserved. Initially, our bismuth nucleus is at rest, so its momentum is zero. When the nucleus undergoes beta decay, it emits an electron, and a recoil polonium nucleus, plus an antineutrino, are produced. All these particles share the total momentum that was initially present, which was zero.

The momentum of the system after decay must also be zero. This translates into an equation involving the momentum of the electron, the recoiling nucleus, and the antineutrino. Each has a momentum (product of mass and velocity) that adds up mathematically to keep the total at zero:
  • Momentum of the electron is +5.60 × 10^{-22} kg·m/s (to the right).
  • Momentum of the polonium is −3.99 × 10^{-22} kg·m/s (to the left).
  • Momentum of the antineutrino must counterbalance these to maintain zero total momentum.
Nucleus Recoil
In beta decay, the newly formed polonium nucleus recoils in response to the emission of the electron and the antineutrino. This phenomenon, known as recoil, is a result of Newton's third law of motion—every action has an equal and opposite reaction.

When the electron is emitted to the right, it exerts a force on the nucleus. As a result, the nucleus must move in the opposite direction to conserve momentum. Let's visualize it this way:
  • Imagine firing a bullet from a gun; the bullet's forward momentum is balanced by the recoil of the gun in the opposite direction.
  • Similarly, after the emission, the polonium nucleus moves to the left.
  • This leftward momentum ( −3.99 × 10^{-22} kg·m/s) is an essential part of maintaining overall momentum balance.
In our example, the velocity of the polonium nucleus is calculated using its mass and the recoil momentum. The result is a velocity of 1.14 × 10^3 m/s to the left. The recoil mechanism beautifully illustrates the conservation of momentum principle in action.
Antineutrino Emission
In beta decay, an antineutrino is emitted alongside an electron. This tiny particle plays a crucial role in maintaining the overall balance of energy and momentum in the decay process. However, unlike the electron or the nucleus, antineutrinos are incredibly elusive and hardly interact with matter, making them challenging to detect.

So, what's the purpose of the antineutrino?
  • It ensures that the energy and momentum equations for the decay hold true.
  • In this exercise, it's clear that the antineutrino absorbs the leftover momentum to satisfy the equation of conservation.
  • The calculated momentum for the antineutrino ends up being −1.61 × 10^{-22} kg·m/s.
The negative sign indicates its direction is opposite to the electron's direction, moving to the left. This motion perfectly balances the equation so that the sum of momenta remains zero, adhering to the conservation principle.

Understanding antineutrino emission is pivotal because it reinforces how subtle, yet critically important, particles are in conserving fundamental physical laws.

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