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The expanding gases that leave the muzzle of a rifle also contribute to the recoil. A .30-caliber bullet has mass 0.00720 kg and a speed of 601 m/s relative to the muzzle when fired from a rifle that has mass 2.80 kg. The loosely held rifle recoils at a speed of 1.85 m/s relative to the earth. Find the momentum of the propellant gases in a coordinate system attached to the earth as they leave the muzzle of the rifle.

Short Answer

Expert verified
The momentum of the propellant gases is approximately 0.8528 kg·m/s.

Step by step solution

01

Understand the Conservation of Momentum

The law of conservation of momentum states that the total momentum before firing is equal to the total momentum after firing. Initially, both bullet and rifle are stationary, so their momentum is zero. After the shot, the total momentum of bullet, rifle, and gases should equal the initial momentum.
02

Calculate the Momentum of the Bullet

The momentum of an object is calculated using the formula \( p = mv \), where \( m \) is the mass and \( v \) is the velocity. Thus, the bullet's momentum is \( p_{bullet} = 0.00720 \times 601 \). Compute this to find the momentum of the bullet.
03

Calculate the Momentum of the Rifle

Using the momentum formula, calculate the rifle's momentum as \( p_{rifle} = 2.80 \times 1.85 \). This gives the momentum of the rifle moving in the opposite direction after firing.
04

Apply Conservation of Momentum

According to the conservation of momentum, the sum of the bullet, rifle, and gases' momentum must be zero as initial momentum is zero: \( p_{bullet} + p_{rifle} + p_{gases} = 0 \). Rearrange to solve for \( p_{gases} \): \( p_{gases} = -(p_{bullet} + p_{rifle}) \).
05

Calculate the Momentum of the Gases

Substitute the previously calculated values of bullet and rifle momentum into the equation: \( p_{gases} = -(4.3272 + (-5.18)) \). Compute this value to find the momentum of the gases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum Calculation
Understanding momentum is key to solving many physics problems, including those involving bullets and rifles. Momentum is the product of an object's mass and velocity, given by the formula \( p = mv \), where \( p \) is momentum, \( m \) is mass, and \( v \) is velocity. It is a vector quantity, meaning it has both magnitude and direction.
In our exercise, the bullet has a mass of 0.00720 kg and a velocity of 601 m/s. Using the formula, you can calculate the bullet's momentum: \( p_{bullet} = 0.00720 \times 601 \). Solving this gives a momentum of 4.3272 kg·m/s.
The same formula is used to calculate the rifle's momentum: \( p_{rifle} = 2.80 \times 1.85 \). This results in a momentum of 5.18 kg·m/s.
These momentum values help us understand how objects move and interact in closed systems, crucial for applying conservation laws.
Newton's Laws
Newton's laws of motion help us describe the movement and interaction of objects. The first law, often called the law of inertia, states that an object will remain at rest, or in uniform motion in a straight line, unless acted upon by a force.
The second law provides the foundation for calculating momentum changes, stating that the force applied to an object equals its mass multiplied by its acceleration (\( F = ma \)).
The third law, which is particularly relevant to our exercise, asserts that for every action there is an equal and opposite reaction. This principle explains why the rifle recoils backward when the bullet is fired forward. As the bullet gains forward momentum, the rifle gains an equal amount of backward momentum, maintaining the system's overall momentum balance.
Rifle Recoil
The topic of rifle recoil is closely linked to conservation of momentum and Newton's third law. When a bullet is fired, gases rapidly expand and push the bullet forward, causing the rifle to recoil or move in the opposite direction.
This recoil is a direct result of the conservation of momentum. Before firing, both the bullet and the rifle are stationary, having zero momentum. After firing, the forward momentum of the bullet must be balanced by the backward recoil of the rifle. This backward motion is what we feel as "kick" when shooting.
With the rifle's mass being significantly greater than that of the bullet, its velocity is much smaller. Yet, despite this smaller velocity, the momentum imparted on the rifle is significant enough to be felt by the shooter.
Bullet Dynamics
Bullet dynamics involve studying how a bullet behaves when fired, including its speed, trajectory, and the forces acting on it. When fired, a bullet is rapidly accelerated by the forces generated by the expanding gases in the gun's chamber.
The bullet's speed is dependent on several factors, including the type of gunpowder, the bullet's mass, and the rifle barrel's length and design. In our exercise, the .30-caliber bullet reaches a speed of 601 m/s.
The consideration of bullet dynamics is essential not only for understanding the bullet's flight path but also for ensuring accuracy and effectiveness in hitting the target. These dynamics showcase the interplay of physics principles at work, such as momentum conservation and force application, illustrating the complex physics involved in firearms.

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