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At time \(t\) = 0 a 2150-kg rocket in outer space fires an engine that exerts an increasing force on it in the \(+x\)-direction. This force obeys the equation \(F_x = At^2\), where \(t\) is time, and has a magnitude of 781.25 N when \(t\) = 1.25 s. (a) Find the SI value of the constant \(A\), including its units. (b) What impulse does the engine exert on the rocket during the 1.50-s interval starting 2.00 s after the engine is fired? (c) By how much does the rocket's velocity change during this interval? Assume constant mass.

Short Answer

Expert verified
(a) A = 500 N/s²; (b) Impulse = 5812.5 Ns; (c) Δv = 2.70 m/s.

Step by step solution

01

Find the Constant A

Given that when \( t = 1.25 \text{ s} \), the force \( F_x = 781.25 \text{ N} \). Using the equation \( F_x = At^2 \), substitute the given values to find \( A \):\[781.25 = A (1.25)^2\]Solve for \( A \):\[A = \frac{781.25}{1.25^2} = \frac{781.25}{1.5625} = 500 \text{ N/s}^2\]Thus, \( A = 500 \text{ N/s}^2 \).
02

Calculate the Impulse

Impulse \( I \) is the integral of force over time. The force \( F_x = At^2 \) changes over time from 2.00 s to 3.50 s:\[I = \int_{2.00}^{3.50} 500t^2 \, dt\]Calculate the integral:\[I = 500 \left[ \frac{t^3}{3} \right]_{2.00}^{3.50} = 500 \left( \frac{(3.50)^3}{3} - \frac{(2.00)^3}{3} \right)\]\[= 500 \left( \frac{42.875}{3} - \frac{8}{3} \right) = 500 \left( 14.2917 - 2.6667 \right)\]\[= 500 \times 11.625 = 5812.5 \text{ Ns}\]Thus, the impulse is 5812.5 Ns.
03

Calculate the Change in Velocity

The change in velocity \( \Delta v \) is given by the impulse \( I \) divided by the mass \( m \) of the rocket:\[\Delta v = \frac{I}{m} = \frac{5812.5}{2150}\]Calculate:\[\Delta v = 2.7035 \text{ m/s}\]Thus, the change in velocity is approximately 2.70 m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law of Motion is a fundamental principle that describes how an object will accelerate if acted upon by an unbalanced force. Simply put, the force applied to an object is equal to the mass of the object multiplied by its acceleration: \( F = ma \). In other words, when a force is exerted on an object, it changes the object’s velocity, causing it to accelerate.

For example, when the rocket in our exercise fires its engine, it creates a force. The equation used was \( F_x = At^2 \), where \( F_x \) is the force, \( A \) is a constant, and \( t \) is time. This shows how the applied force varies with time to influence the rocket’s acceleration.

In the problem, you were tasked with finding the value of the constant \( A \) by rearranging the equation to \( A = \frac{F_x}{t^2} \). By substituting the given numerical values, you were able to determine how strongly the force was acting over time and apply this to understand the rocket's motion.
Rocket Propulsion
Rocket propulsion is based on Newton's Third Law of Motion, but it heavily intersects with the concept in Newton's Second Law because force directly affects acceleration. As the engines of a rocket burn fuel, they expel gas in one direction, driving the rocket in the opposite direction. This action-reaction principle is key in providing thrust.

In the problem, the rocket was considered to be in outer space, meaning that there's no air resistance, and the only forces acting are those of the rocket itself. This makes it a prime example of isolated propulsion dynamics.

As fuel is burned and gases are expelled, the thrust produced causes changes in velocity. The force produced by the rocket’s engine increases over time, as calculated in the problem through the integral of force to find impulse. This force increases because \( F_x \) follows the formula \( At^2 \), meaning it grows quadratically with time. This analysis helps show how different propulsion systems can be designed depending on how forces are structured over the duration of a rocket's flight.
Integration in Physics
Integration is a key mathematical concept used extensively in physics to calculate quantities that result from rates of change, such as impulse. Impulse, a product of force and time, provides insights into changes in momentum of the object being studied.

In the exercise, integration was used to calculate the impulse exerted by a force that changes over time, following the equation \( F_x = At^2 \). This required solving an integral over a specific time interval (from 2.00 s to 3.50 s): \[ I = \int_{2.00}^{3.50} 500t^2 \, dt \]
  • This involves calculating the antiderivative of the function \( 500t^2 \)
  • And then evaluating it over the given limits.


This application shows how physicists use integration not just to solve textbook exercises, but to determine real-world changes in states, like how much a rocket's speed changes as a result of fired engines during specific time periods. Such calculations are crucial for designing and understanding various dynamic systems.

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