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Two objects, with masses 5.00 kg and 2.00 kg, hang 0.600 m above the floor from the ends of a cord that is 6.00 m long and passes over a frictionless pulley. Both objects start from rest. Find the maximum height reached by the 2.00-kg object.

Short Answer

Expert verified
The maximum height reached by the 2.00-kg object is 1.50 m.

Step by step solution

01

Identify Forces and Energy Conservation

Begin by identifying the forces acting on both objects and note the system is frictionless. Since the pulley is frictionless, mechanical energy is conserved in the system. The heavier object (5.00 kg) will accelerate downward, causing the lighter object (2.00 kg) to accelerate upward.
02

Determine Initial and Final Energies

The initial mechanical energy of the system consists solely of gravitational potential energy because both objects start from rest. Let the reference level for gravitational potential energy be the height where the objects first start (0.600 m above the ground for the 5.00 kg mass and its initial height for the 2.00 kg mass).
03

Write the Energy Conservation Equation

The initial energy for the 5.00 kg mass is given by \( E_{i} = m_{1}gh_{1} = 5.00 \, \text{kg} \times 9.81 \, \text{m/s}^2 \times 0.600 \, \text{m} \). The initial energy for the 2.00 kg mass is similarly defined. The final energy of the system will be entirely potential energy at the moment when the 2.00 kg object reaches its maximum height.
04

Set Up Equations for Energies Involving Maximum Height

As the 5.00 kg object hits the floor, all potential energy is transferred to the 2.00 kg object. At maximum height, the 2 kg object has a potential energy of \( m_{2}gh_{max} \). Set the initial energy equal to the final potential energy of the 2 kg object.
05

Solve for Maximum Height

Substitute the known values and solve the energy equation for the maximum height \( h_{max} \). The maximum height is reached when all initial potential energy of the 5 kg block is converted into the potential energy of the 2 kg object. Solve:\[ 5.00 \times 9.81 \times 0.600 = 2.00 \times 9.81 \times h_{max} \]Simplify to find\[ h_{max} = \frac{5.00 \times 0.600}{2.00} = 1.50 \text{ m} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mechanical Energy
Mechanical energy is an important concept in physics as it combines two fundamental forms of energy: kinetic and potential energy.
In a system where there are no external forces such as friction, mechanical energy remains constant because of the law of conservation of energy.
- **Kinetic Energy** is the energy of motion. Whenever an object moves, it possesses kinetic energy. The formula used to calculate kinetic energy is: \( KE = \frac{1}{2}mv^2 \) where \( m \) is the mass of the object and \( v \) is its velocity. In our exercise, initially both masses are at rest, so the kinetic energy is zero.- **Potential Energy** is the energy stored due to position. In the context of gravitational potential energy, it depends on the height of the object in a gravitational field. In systems like the frictionless pulley, mechanical energy is transferred between these two forms. A critical insight is that the total mechanical energy stays the same; it just changes from one form to another as objects move in the system.
Gravitational Potential Energy
Gravitational potential energy (GPE) is a type of potential energy related to the height and mass of an object in a gravitational field.
The formula to calculate GPE is:\[ PE = mgh \]where \( m \) is the mass, \( g \) is the acceleration due to gravity (approximately \(9.81 \, \text{m/s}^2\) on Earth), and \( h \) is the height above the reference point.
In the pulley system exercise, this reference point is the initial height of the two masses above the ground:
- The heavier mass of 5.00 kg initially has a gravitational potential energy calculated using its starting height of 0.600 m above the floor.- As this mass moves downward, its potential energy decreases while that of the lighter 2.00 kg mass increases proportionately as it moves upward.

When the 5 kg object reaches the ground, its potential energy is zero, and all this energy has transferred to the 2 kg mass, raising it to its maximum height.
Frictionless Pulley System
In physics problems, a frictionless pulley system is often used to simplify the analysis of forces and motions. This assumption makes sure there is no energy loss due to friction, meaning you can apply the conservation of mechanical energy seamlessly.
Key things to keep in mind about a frictionless pulley system are: - The pulley's role is to redirect the tension force in the cord. It does not lose energy, which means any initial energy in the system is converted fully as the objects move. - Since the pulley is frictionless, all energy is conserved and depending on the situation, is either stored as gravitational potential energy or converted to kinetic energy. - In our exercise, the masses start from rest with stored gravitational potential energy. Because the pulley is frictionless, this energy transforms entirely into raising the 2 kg mass to its peak without losses to kinetic friction or air resistance. Understanding this concept helps students appreciate the simplification in energy calculations, focusing on gravitational energy changes without needing to account for non-conservative forces.

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Most popular questions from this chapter

While a person is walking, his arms swing through approximately a 45\(^\circ\) angle in \(\frac{1}{2}\) s. As a reasonable approximation, assume that the arm moves with constant speed during each swing. A typical arm is 70.0 cm long, measured from the shoulder joint. (a) What is the acceleration of a 1.0-g drop of blood in the fingertips at the bottom of the swing? (b) Draw a free-body diagram of the drop of blood in part (a). (c) Find the force that the blood vessel must exert on the drop of blood in part (a). Which way does this force point? (d) What force would the blood vessel exert if the arm were not swinging?

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