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A 40.0-kg packing case is initially at rest on the floor of a 1500-kg pickup truck. The coefficient of static friction between the case and the truck floor is 0.30, and the coefficient of kinetic friction is 0.20. Before each acceleration given below, the truck is traveling due north at constant speed. Find the magnitude and direction of the friction force acting on the case (a) when the truck accelerates at 2.20 m/s\(^2\) northward and (b) when it accelerates at 3.40 m/s\(^2\) southward.

Short Answer

Expert verified
(a) 88 N northward, (b) 78.48 N northward.

Step by step solution

01

Understanding the Forces

We have a 40 kg packing case on the floor of a 1500 kg truck. The static friction coefficient is 0.30, and the kinetic friction coefficient is 0.20. A force is acting on the case to keep it stationary concerning the truck as the truck accelerates. Thus, the friction force would either be static or kinetic depending on the truck's acceleration.
02

Calculate Maximum Static Friction

The maximum static friction force is given by the formula: \[ f_{s, \, \text{max}} = \mu_s \cdot m \cdot g \]where \( \mu_s = 0.30 \) is the static friction coefficient, \( m = 40 \text{ kg} \) is the mass of the case, and \( g = 9.81 \text{ m/s}^2 \) is the acceleration due to gravity. \[ f_{s, \, \text{max}} = 0.30 \times 40 \times 9.81 = 117.72 \text{ N} \]
03

Determine Friction Needed for Northward Acceleration

To hold the case stationary relative to the truck when accelerating northwards at 2.20 m/s², the friction force required is: \[ f = m \cdot a = 40 \times 2.20 = 88 \text{ N} \]Since 88 N < 117.72 N, static friction is sufficient to prevent movement, and the friction force is 88 N northward.
04

Evaluate Friction for Southward Acceleration

When the truck accelerates southward at 3.40 m/s², calculate the force required to prevent sliding: \[ f = 40 \times 3.40 = 136 \text{ N} \]Since 136 N > 117.72 N, the static friction cannot prevent sliding, and the friction will become kinetic.
05

Calculate Kinetic Friction Force

The kinetic friction force is calculated as: \[ f_k = \mu_k \cdot m \cdot g \]where \( \mu_k = 0.20 \). Hence,\[ f_k = 0.20 \times 40 \times 9.81 = 78.48 \text{ N} \]The case will slide southward, and the frictional force is 78.48 N northward.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Static Friction
Static friction is the type of friction that stops an object from starting to move. It acts between surfaces that are at rest concerning one another.
In our scenario, as the truck accelerates northward, static friction must match any force trying to move the packing case. This means static friction applies up to its maximum limit, calculated using:
  • \(f_{s, \, \text{max}} = \mu_s \cdot m \cdot g\)- where \(\mu_s = 0.30\) is the static friction coefficient.
  • With our packing case of 40 kg, the maximum force before it starts moving with the truck is 117.72 N.
If required force (e.g., 88 N) is within this limit, the static friction succeeds, holding the case steady.
Static friction plays a crucial role when starting or stopping movements."Static friction aligns with Newton's law suggesting forces should balance for state of rest to continue."
Understanding static friction helps clarify why certain objects don’t slide around when a vehicle starts moving.
Kinetic Friction
Kinetic friction comes into play once surfaces begin sliding over each other. It is usually less than static friction, explaining why it’s often easier to keep an object moving rather than start moving it.
In the exercise, once the truck accelerates southward with 3.40 m/s², static friction reaches its limit. It transitions into kinetic friction, insufficient to hold the case, leading it to slide.
The kinetic force is calculated using:
  • \( f_k = \mu_k \cdot m \cdot g \) - where \( \mu_k = 0.20 \) is the kinetic friction coefficient.
  • This results in a friction force of 78.48 N while moving opposite to the motion (northward).
Identifying kinetic friction helps understand how continuous motion is maintained at different acceleration rates.
It aids in predicting behavior changes when accelerating forces exceed static limits, shifting to a constant resisting force.
Newton's Laws of Motion
Newton's Laws of Motion are fundamental in understanding frictional forces and object movements.
Newton's First Law, the law of inertia, tells us that an object will stay at rest or uniform motion unless acted upon by an external force. In the packing case, the static friction force aligns with this law by maintaining rest as long as it can overcome any applied forces.
When the force exceeds static friction, Newton's Second Law comes into effect, defining force as the product of mass and acceleration \(F = m \cdot a\). This formula helps in calculating how much force is needed for different accelerations and whether it surpasses friction thresholds.Newton's Third Law, for every action, there is an equal and opposite reaction, further explains how when the truck moves one way, friction acts oppositely to resist the movement, safeguarding the case.

The coverage of Newton's laws aids in effectively exploring forces involved, providing a foundation for determining when friction values switch states.

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