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\(\textbf{Radiation Therapy with \)\pi^-\( Mesons.}\) Beams of \(\pi^-\) mesons are used in radiation therapy for certain cancers. The energy comes from the complete decay of the \(\pi^-\) to stable particles. (a) Write out the complete decay of a \(\pi^-\) meson to stable particles. What are these particles? (b) How much energy is released from the complete decay of a single \(\pi^-\) meson to stable particles? (You can ignore the very small masses of the neutrinos.) (c) How many \(\pi^-\) mesons need to decay to give a dose of 50.0 Gy to 10.0 g of tissue? (d) What would be the equivalent dose in part (c) in Sv and in rem? Consult Table 43.3 and use the largest appropriate RBE for the particles involved in this decay.

Short Answer

Expert verified
Decay produces an electron, a muon neutrino, and an electron antineutrino; 139.57 MeV per \(\pi^-\) meson; \(2.24 \times 10^{10}\) mesons for 50 Gy to 10 g; dose equivalent is 1000 Sv or 10鈦 rems.

Step by step solution

01

Decay of \(\pi^-\) Meson

The \(\pi^-\) meson decays into a muon \(\mu^-\) and a muon neutrino \(u_\mu\). The muon \(\mu^-\) further decays into a muon neutrino \(u_\mu\), an electron \(e^-\), and an electron antineutrino \(\overline{u}_e\). Therefore, the stable particles resulting from the complete decay of a \(\pi^-\) meson are an electron \(e^-\), a muon neutrino \(u_\mu\), and an electron antineutrino \(\overline{u}_e\).
02

Calculating Energy Released

The mass of a \(\pi^-\) meson is approximately 139.57 MeV/c虏. Since we can ignore the very small masses of the neutrinos, the energy released can be approximated using this mass. Thus, the energy released during the decay of a single \(\pi^-\) meson is approximately 139.57 MeV.
03

Calculate Number of \(\pi^-\) Mesons for 50.0 Gy Dose

Dose in Grays (Gy) is measured in joules per kilogram. We need to find out how much energy in joules is needed to deliver 50 Gy to 10 g of tissue (0.01 kg). First, calculate the total energy: 50 Gy \(\times\) 0.01 kg = 0.5 J. Convert the energy from MeV to joules: \(\frac{139.57 \text{ MeV}}{1.602 \times 10^{-13} \text{ J/MeV}} \approx 2.23 \times 10^{-11} \text{ J}\). Then, determine the number of \(\pi^-\) mesons: \(\frac{0.5 \text{ J}}{2.23 \times 10^{-11} \text{ J/meson}} \approx 2.24 \times 10^{10}\) mesons.
04

Calculating Dose in Sieverts and Rems

The equivalent dose (in Sv) is given by multiplying the absorbed dose (in Gy) by the radiation weighting factor (RBE). For high LET radiations like those from \(\pi^-\) decay, the RBE can be around 20. So, the equivalent dose in Sv is \(50 \text{ Gy} \times 20 = 1000 \text{ Sv}\). To convert to rems, use the conversion 1 Sv = 100 rems: \(1000 \text{ Sv} \times 100 = 10^5 \text{ rems}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pion Decay
Pion decay is a fundamental concept in particle physics and has practical applications in radiation therapy. Pions (\( \pi^ - \) mesons) are subatomic particles that can undergo decay to release energy. When a \( \pi^- \) meson decays, it breaks down into lighter, more stable particles. In the first step of its decay, a \( \pi^- \) meson is transformed into a muon \( \mu^- \) and a muon neutrino \( u_\mu \). Subsequently, the muon itself decays further into an electron \( e^- \), an electron antineutrino \( \overline{u}_e \), and another muon neutrino \( u_\mu \).
In summary, the decay process of the \( \pi^- \) meson results in the production of an electron and neutrinos. Understanding this decay process is crucial in evaluating the energy and particles involved in medical and research applications, particularly in cancer radiation therapy.
Energy Released
The energy released from the decay of a \( \pi^- \) meson is significant, as it plays an essential role in applications such as radiation therapy. The mass of a \( \pi^- \) meson is approximately 139.57 MeV/c虏, which equates to the energy released during its decay. Neutrinos are involved in the decay process, but since their masses are extremely small, their contribution to the energy release is negligible.
In practical terms, when a \( \pi^- \) meson decays, the energy is released in the form of kinetic energy imparted to the stable particles produced, such as electrons and neutrinos. This release of energy is harnessed in medical applications, providing the necessary dose for radiation therapy.
Dosimetry
Dosimetry is the science of measuring and assessing the dose of radiation absorbed by matter, particularly by human tissue in medical contexts. It is crucial in ensuring that patients receive the correct therapeutic dose. In the context of \( \pi^- \) meson decay used in radiation therapy, dosimetry calculations help determine how many mesons are required to achieve a desired dose.
For example, to administer a dose of 50 Gray (Gy) to 10 grams of tissue, the total energy required is calculated, which is then converted from energy units like MeV to joules. From there, one can determine the number of \( \pi^- \) mesons needed by dividing the total energy required by the energy released from a single meson decay. This precise calculation ensures the effectiveness and safety of the treatment.
Equivalent Dose
The concept of equivalent dose is pivotal in radiation therapy as it accounts for the type of radiation and its potential biological effect. While the absorbed dose measured in Gray (Gy) reflects the amount of energy deposited in tissue, the equivalent dose considers the relative biological effectiveness (RBE) of different types of radiation.
In the context of \( \pi^- \) meson therapy, high LET (Linear Energy Transfer) radiation implies a high RBE, often around 20. To translate the absorbed dose into an equivalent dose, the absorbed dose is multiplied by the RBE, giving a result in Sieverts (Sv). The equivalent dose helps standardize radiation types to assess risk and therapeutic potential accurately. Moreover, conversion to rems (where 1 Sv equals 100 rems) provides a familiar metric in regions utilizing customary units.
Meson Physics
Meson physics is a branch of particle physics that studies mesons, which are intermediate-mass subatomic particles composed of a quark and an antiquark. These particles, including \( \pi^- \) mesons, are crucial in understanding fundamental forces and interactions within atomic nuclei.
In medical applications like radiation therapy, mesons' properties are harnessed due to their ability to be targeted and deliver high-energy radiation precisely to tumor sites. The study of mesons contributes to broader scientific endeavors, enhancing our understanding of strong interactions and leading to innovations in practical technologies such as cancer treatment. Meson decay processes, like those of \( \pi^- \) mesons, showcase the intersection of particle physics and medicine in producing beneficial societal outcomes.

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Most popular questions from this chapter

One proposed proton decay is \(p^+ \rightarrow e^+ + \pi^0\), which violates both baryon and lepton number conservation, so the proton lifetime is expected to be very long. Suppose the proton half-life were \(1.0 \times 10^{18} y\). (a) Calculate the energy deposited per kilogram of body tissue (in rad) due to the decay of the protons in your body in one year. Model your body as consisting entirely of water. Only the two protons in the hydrogen atoms in each \(H_2O\) molecule would decay in the manner shown; do you see why? Assume that the \(\pi^0\) decays to two \(\gamma\) rays, that the positron annihilates with an electron, and that all the energy produced in the primary decay and these secondary decays remains in your body. (b) Calculate the equivalent dose (in rem) assuming an RBE of 1.0 for all the radiation products, and compare with the 0.1 rem due to the natural background and the 5.0-rem guideline for industrial workers. Based on your calculation, can the proton lifetime be as short as \(1.0 \times 10^{18} y\)?

A proton and an antiproton collide head-on with equal kinetic energies. Two \(\gamma\) rays with wavelengths of 0.720 fm are produced. Calculate the kinetic energy of the incident proton.

In which of the following decays are the three lepton numbers conserved? In each case, explain your reasoning. (a) \(\mu^-\rightarrow e^- + \nu_e + \overline{\nu}_\mu\); (b) \(\tau^-\rightarrow e^- + \overline{\nu}_e + \overline {\nu} _\tau\); (c) \(\pi^+ \rightarrow e^+ + \gamma\); (d) \(n \rightarrow p + e^- + \overline{\nu}_e\).

How much energy is released when a \(\mu^-\) muon at rest decays into an electron and two neutrinos? Neglect the small masses of the neutrinos.

The magnetic field in a cyclotron that accelerates protons is 1.70 T. (a) How many times per second should the potential across the dees reverse? (This is twice the frequency of the circulating protons.) (b) The maximum radius of the cyclotron is 0.250 m. What is the maximum speed of the proton? (c) Through what potential difference must the proton be accelerated from rest to give it the speed that you calculated in part (b)?

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