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A radioactive isotope has a half-life of 43.0 min. At \(t\) = 0 its activity is 0.376 Ci. What is its activity at \(t\) = 2.00 h?

Short Answer

Expert verified
The activity at 2.00 h is approximately 0.0587 Ci.

Step by step solution

01

Understand the Concept of Half-Life

The half-life of a radioactive isotope is the time required for its activity to reduce to half its initial value. For this isotope, the half-life is given as 43.0 minutes.
02

Convert Time to Consistent Units

Given that the time at which we want to find the activity is 2.00 hours, we first convert hours to minutes to keep units consistent for all calculations: \[2.00 \text{ hours} = 2.00 \times 60 \text{ minutes} = 120 \text{ minutes}\]
03

Calculate the Number of Half-Lives

Determine how many half-lives have elapsed in 120 minutes:\[\text{Number of half-lives} = \frac{120 \text{ minutes}}{43.0 \text{ minutes/half-life}} \approx 2.79\]
04

Calculate Activity using Half-Life

Using the formula for exponential decay, where the activity decreases by a factor of 1/2 for each half-life:\[A(t) = A_0 \times \left(\frac{1}{2}\right)^{\frac{t}{T_{1/2}}}\]Substitute the values:\[A(120 \text{ min}) = 0.376 \text{ Ci} \times \left(\frac{1}{2}\right)^{2.79} \approx 0.376 \text{ Ci} \times 0.156 \approx 0.0587 \text{ Ci}\]
05

Review the Solution

Ensure the calculations consider the proper conversion and application of half-life principles. The calculated activity at 2.00 hours should be approximately 0.0587 Ci.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Half-Life
The concept of half-life is central in the study of radioactive decay. Half-life is the duration required for half of the radioactive isotopes in a sample to decay. For any radioactive substance, this period is unique and constant. In the given example, the half-life is 43.0 minutes. This means every 43.0 minutes, the isotope's activity reduces to half its previous value.
Understanding the half-life helps predict how much of the substance remains active over time, which is crucial for applications like nuclear medicine and carbon dating. Knowing how activity decreases in "half-lives" helps simplify complex decay processes, allowing us to handle decay calculations with confidence and precision.
  • Half-life processes are exponential, explaining why we use exponential decay equations.
  • Half-life does not change regardless of the amount of the isotope present.
Exponential Decay
Exponential decay describes a situation where a quantity decreases at a rate proportional to its current value. This concept is crucial in radioactive decay as the activity of isotopes reduces exponentially over time.
When dealing with radioactive decay, the formula for exponential decay is often used: \[ A(t) = A_0 \times \left(\frac{1}{2}\right)^{\frac{t}{T_{1/2}}} \]
Here, \( A(t) \) is the activity at time \( t \), \( A_0 \) is the initial activity, and \( T_{1/2} \) is the half-life of the material.
  • Each half-life results in the activity being halved.
  • The relationship is logarithmic, meaning that it follows a constant rate of decay over equal time intervals.
By adopting this formula, we can effectively predict the remaining activity of a sample at any given time, making it a powerful tool for understanding radioactive decay characteristics succinctly.
Activity of Radioactive Isotopes
Activity refers to the rate at which a radioactive isotope decays and is measured in units like Curies (Ci) or Becquerels (Bq). It indicates how many disintegrations occur per unit of time. In the explanatory exercise, the initial activity is given as 0.376 Ci. Over time, this activity reduces according to the isotope's half-life.
  • Measured activity assists in gauging potential exposure and ensuring safety protocols in various sectors.
  • Lower activity means fewer disintegrations per second, indicating lesser radiation emission.
The activity shows the isotope's potency and decay speed, making it fundamental in radiation applications like treatment of diseases and determining radioactive age in geology and archaeology.
Unit Conversion in Physics
Unit conversion is essential in solving physics problems accurately, particularly when dealing with time-based computations. In the provided exercise, converting 2.00 hours to 120 minutes is vital in aligning the time units with the half-life expressed in minutes.
Deploying consistent units guarantees the validity of the mathematical calculations, facilitating accurate results.
  • Always ensure all units are compatible when performing calculations. In this case, ensuring both half-life and the total elapsed time are in minutes.
  • Failure to convert units properly can result in significant errors in calculations and potentially flawed conclusions;
As a key skill in physics, unit conversion eliminates ambiguity and ensures clarity in the final interpretations of physical phenomena.

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Most popular questions from this chapter

As a health physicist, you are being consulted about a spill in a radiochemistry lab. The isotope spilled was 400 \(\mu\)Ci of \(^1$$^3$$^1\)Ba, which has a half-life of 12 days. (a) What mass of \(^1$$^3$$^1\)Ba was spilled? (b) Your recommendation is to clear the lab until the radiation level has fallen 1.00 \(\mu\)Ci. How long will the lab have to be closed?

\(\textbf{Radioactive Tracers}\). Radioactive isotopes are often introduced into the body through the bloodstream. Their spread through the body can then be monitored by detecting the appearance of radiation in different organs. One such tracer is \(^1$$^3$$^1\)I, a \(\beta$$^-\) emitter with a half-life of 8.0 d. Suppose a scientist introduces a sample with an activity of 325 Bq and watches it spread to the organs. (a) Assuming that all of the sample went to the thyroid gland, what will be the decay rate in that gland 24 d (about 3 \\(\frac{1}{2}\\) weeks) later? (b) If the decay rate in the thyroid 24 d later is measured to be 17.0 Bq, what percentage of the tracer went to that gland? (c) What isotope remains after the I-131 decays?

A nuclear chemist receives an accidental radiation dose of 5.0 Gy from slow neutrons (RBE \(=\) 4.0). What does she receive in rad, rem, and J/kg?

Consider the nuclear reaction \(^{28}_{14}Si\) + \(\gamma\) \(\rightarrow\) \(^{24}_{12}Mg\) + X where X is a nuclide. (a) What are Z and A for the nuclide X? (b) Ignoring the effects of recoil, what minimum energy must the photon have for this reaction to occur? The mass of a \(^{28}_{14}Si\) atom is 27.976927 u, and the mass of a \(^{24}_{12}Mg\) atom is 23.985042 u.

A person exposed to fast neutrons receives a radiation dose of 300 rem on part of his hand, affecting 25 g of tissue. The RBE of these neutrons is 10. (a) How many rad did he receive? (b) How many joules of energy did he receive? (c) Suppose the person received the same rad dosage, but from beta rays with an RBE of 1.0 instead of neutrons. How many rem would he have received?

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