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In the Bohr model, what is the principal quantum number \(n\) at which the excited electron is at a radius of 1 \(\mu\)m? (a) 140; (b) 400; (c) 20; (d) 81.

Short Answer

Expert verified
(a) 140

Step by step solution

01

Understand the Bohr Model Formula for Orbit Radius

In the Bohr model, the radius of an electron's orbit in a hydrogen atom is given by the formula: \[ r_n = n^2 \cdot r_1\]where \( r_n \) is the radius of the orbit for the principal quantum number \( n \) and \( r_1 = 0.529 \times 10^{-10} \text{ m} \) is the radius of the smallest orbit (1st orbit). We must find \( n \) such that \( r_n = 1 \mu \text{m} = 1 \times 10^{-6} \text{ m} \).
02

Rearrange the Formula to Solve for \( n \)

First, set the equation given by the Bohr model equal to the target radius:\[ n^2 \cdot 0.529 \times 10^{-10} = 1 \times 10^{-6} \]Now solve for \( n^2 \):\[ n^2 = \frac{1 \times 10^{-6}}{0.529 \times 10^{-10}} \]
03

Calculate \( n^2 \)

Perform the division operation:\[ n^2 = \frac{1 \times 10^{-6}}{0.529 \times 10^{-10}} = 1.89 \times 10^4 \]
04

Take the Square Root to Find \( n \)

Now take the square root of \( n^2 \) to get \( n \):\[ n = \sqrt{1.89 \times 10^4} \approx 137.5 \]Since \( n \) must be an integer, we round 137.5 to the nearest whole number, which is 138.
05

Choose the Closest Answer Option

Compare the calculated \( n = 138 \) with the answer options provided: (a) 140, (b) 400, (c) 20, (d) 81. The closest option to 138 is (a) 140.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principal Quantum Number
The principal quantum number, usually denoted by \( n \), is a fundamental concept in the Bohr model of the atom. It represents the energy level or shell in which an electron resides within an atom. Each energy level can hold a certain number of electrons, and as \( n \) increases, the distance between the electron and the nucleus increases as well.

In the Bohr model, \( n \) is always a positive integer (\( n = 1, 2, 3, \dots \)), and it defines the size of the electron orbit. The larger the value of \( n \), the farther the electron is from the nucleus. This means the electron is in a higher energy state. As \( n \) increases, the electron's energy increases, and the radius of the orbit also becomes larger.

Understanding \( n \) is essential for knowing how electrons are arranged around a nucleus and how they transition between different energy levels.
Electron Orbit Radius
In the Bohr model, the electron orbit radius is the distance from the nucleus to the electron in a given energy level. This radius is directly influenced by the principal quantum number \( n \).

The formula for determining the radius of an electron orbit in a hydrogen atom is:
  • \( r_n = n^2 \cdot r_1 \)
where \( r_n \) is the radius of the orbit for the principal quantum number \( n \), and \( r_1 \) is the radius of the first orbit. For hydrogen, \( r_1 = 0.529 \times 10^{-10} \) meters, a very small size typical for atomic-scale measurements.

When calculating the electron orbit radius using this formula, it becomes clear that the radius is proportional to the square of \( n \). This means that a small change in \( n \) can lead to a significant change in the electron orbit radius.
Hydrogen Atom
The hydrogen atom is the simplest atom, with one proton in the nucleus and one electron orbiting around it. Due to this simplicity, it serves as the basis for the Bohr model, providing a straightforward way to examine atomic structures and behaviors.

In the Bohr model, the hydrogen atom is used to explain how energy levels work. The model suggests that electrons move in circular orbits around the nucleus, each orbit corresponding to a specific energy level defined by the principal quantum number \( n \). This model, while relatively simple, was one of the first to introduce quantization to explain atomic structure.

Understanding how the hydrogen atom operates within the Bohr model is crucial for grasping more complex principles in atomic physics. The model gives insights into how electrons are arranged and how they transition between energy levels, providing a foundation for more advanced theories in quantum mechanics.

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Most popular questions from this chapter

(a) Write out the ground-state electron configuration (\(1s^2, 2s^2,\dots\)) for the carbon atom. (b) What element of nextlarger \(Z\) has chemical properties similar to those of carbon? Give the ground-state electron configuration for this element.

(a) Show that the total number of atomic states (including different spin states) in a shell of principal quantum number \(n\) is \(2n^2\). \([Hint\): The sum of the first \(N\) integers 1 + 2 + 3 + \(\cdots\) + \(N\) is equal to \(N$$(N + 1)\)/2.] (b) Which shell has 50 states?

The normalized radial wave function for the \(2p\) state of the hydrogen atom is \(R_2{_p}\) = \(( 1/ \sqrt{24a^5}\))\(re$$^-{^r}{^/}{^2}{^a}\). After we average over the angular variables, the radial probability function becomes \(P$$(r)\) \(dr\) = \((R_2{_p}$$)^2\)r\(^2\) \(dr\). At what value of \(r\) is \(P$$(r)\) for the \(2p\) state a maximum? Compare your results to the radius of the \(n\) = 2 state in the Bohr model.

a) How many different 5\(g\) states does hydrogen have? (b) Which of the states in part (a) has the largest angle between \(\vec L\) and the z-axis, and what is that angle? (c) Which of the states in part (a) has the smallest angle between \(\vec L\) and the z-axis, and what is that angle?

Calculate, in units of \(\hslash\), the magnitude of the maximum orbital angular momentum for an electron in a hydrogen atom for states with a principal quantum number of 2, 20, and 200. Compare each with the value of n\(\hslash\) postulated in the Bohr model. What trend do you see?

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