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A hydrogen atom in a particular orbital angular momentum state is found to have \(j\) quantum numbers \({7\over2}\) and \({9\over2}\) . (a) What is the letter that labels the value of \(l\) for the state? (b) If \(n = 5\), what is the energy difference between the \(j = {7\over2}\) and \(j = {9\over2}\) levels?

Short Answer

Expert verified
(a) The letter is "g". (b) The energy difference is approximately 0.00004 eV.

Step by step solution

01

Quantum Number Definitions

The quantum numbers for hydrogen atoms include the principal quantum number \(n\), the orbital angular momentum quantum number \(l\), and the total angular momentum quantum number \(j\). The \(j\) quantum number can be given by \(j = l + s\) or \(j = l - s\), where \(s\) is the spin quantum number which is \(\pm \frac{1}{2}\).
02

Determine Orbital Quantum Number \(l\)

Given \(j = \frac{7}{2}\) and \(j = \frac{9}{2}\), for a hydrogen atom, \(s = \frac{1}{2}\). Thus, if \(j = \frac{7}{2}\), it could be \(l - \frac{1}{2} = \frac{7}{2}\), yielding \(l = 4\). Similarly, if \(j = \frac{9}{2}\), it could be \(l + \frac{1}{2} = \frac{9}{2}\), and thus \(l = 4\) as well. The letter for \(l = 4\) is \(g\).
03

Energy Level Difference Formula

The energy for a hydrogen atom with principal quantum number \(n\) is given by \(E_n = - \frac{13.6}{n^2} \text{ eV}\). However, different \(j\) levels can introduce a small difference due to fine structure splitting from the Sommerfeld formula: \(E_{n,j} = - \frac{13.6}{n^2} \left( 1 + \frac{\alpha^2}{n^2}\left(\frac{n}{j + \frac{1}{2}} - \frac{3}{4} \right) \right)\), where \(\alpha \approx 1/137\) is the fine structure constant.
04

Calculate Energy for \(n = 5, j = \frac{7}{2}\)

Substituting: \(E_{5,7/2} = - \frac{13.6}{5^2} \left( 1 + \frac{1}{137^2 \times 5^2}\left(\frac{5}{\frac{7}{2} + \frac{1}{2}} - \frac{3}{4} \right) \right) \approx -0.54506 \text{ eV} \).
05

Calculate Energy for \(n = 5, j = \frac{9}{2}\)

Substituting: \(E_{5,9/2} = - \frac{13.6}{5^2} \left( 1 + \frac{1}{137^2 \times 5^2}\left(\frac{5}{\frac{9}{2} + \frac{1}{2}} - \frac{3}{4} \right) \right) \approx -0.54502 \text{ eV} \).
06

Calculate the Energy Difference

The energy difference between the two levels is \(\Delta E = E_{5,7/2} - E_{5,9/2} \approx -0.54506 + 0.54502 = 0.00004 \text{ eV}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrogen Atom
The hydrogen atom serves as a foundational example in the study of quantum mechanics. Its simplicity stems from having only one electron orbiting its nucleus, allowing scientists to explore complex quantum behaviors succinctly. In the context of quantum numbers, the hydrogen atom provides a clear illustration of how electrons occupy energy levels that are defined by these numbers.
  • Principal Quantum Number ( ): Determines the energy level of the electron.
  • Orbital Quantum Number (l): Defines the shape of the electron's orbital.
  • Total Angular Momentum Quantum Number (j): Given by the combination of orbital and spin angular momentum.
The hydrogen atom's spectra and the quantized energy levels form the bedrock upon which more complex atomic interactions are understood.
Angular Momentum
Angular momentum in quantum mechanics is a measure of the amount of rotation an electron has in an atom. For the hydrogen atom, angular momentum is crucial in defining the electron's orbitals. The orbital angular momentum quantum number, denoted as \(l\), indicates the shape of these orbitals.
The total angular momentum \(j\) is a key player when considering the electron’s spin. As electrons have a property known as spin, marked by \(s\), the total angular momentum combines both \(l\) and \(s\). The formula that relates them is \(j = l \pm s\). For hydrogen, this total angular momentum can take values like \(\frac{7}{2}\) or \(\frac{9}{2}\) based on states classified by these quantum numbers.
  • \(l\) defines the electron's orbital shape and is tied to angular momentum \(L = \sqrt{l(l + 1)}\hbar\).
  • The combination of spin \(s = \frac{1}{2}\) and \(l\) results in total angular momentum values \(j\).
Energy Levels
In atomic physics, energy levels represent the various states where an electron may exist, each specific state having a distinct energy. For hydrogen atoms, these levels are defined by the principal quantum number \(n\).
The energy of an electron in a hydrogen atom is determined using a formula: \(E_n = - \frac{13.6}{n^2} \text{ eV}\). This binds the electron to quantized states or levels, each characterized by an integer \(n\). An increase in \(n\) means the electron is farther from the nucleus and thus in a state of higher energy. However, small variations in these levels may arise because of a quantum effect known as fine structure.
  • Higher \(n\) values mean higher energy levels.
  • Fine structure results in slight variations of these energy levels.
Fine Structure Splitting
Fine structure splitting refers to slight differences in energy levels within the same principal quantum number \(n\) for a hydrogen atom. It's due to the interaction of the electron spin with its orbital motion, such interactions modifying energy levels slightly.
The fine structure is captured in the modified energy formula: \[E_{n,j} = - \frac{13.6}{n^2} \left( 1 + \frac{\alpha^2}{n^2}\left(\frac{n}{j + \frac{1}{2}} - \frac{3}{4} \right) \right)\]where \(\alpha\) is the fine structure constant, approximately \(\frac{1}{137}\). This formula accounts for the subtleties in energy levels based on different \(j\) values, explaining why levels with \(j = \frac{7}{2}\) and \(j = \frac{9}{2}\) show slight energy differences even within the same \(n\). In the hydrogen atom, these fine structure differences can lead to incredibly small energy shifts like \(0.00004\) eV.

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Most popular questions from this chapter

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