/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 You have just landed on Planet X... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

You have just landed on Planet X. You release a 100-g ball from rest from a height of 10.0 m and measure that it takes 3.40 s to reach the ground. Ignore any force on the ball from the atmosphere of the planet. How much does the 100-g ball weigh on the surface of Planet X?

Short Answer

Expert verified
The ball weighs 0.173 N on Planet X.

Step by step solution

01

Identify Known Values

We are given the initial height of the ball as 10 m, the time it takes to fall as 3.4 s, and the mass of the ball as 100 g (or 0.1 kg). We need to find the weight of the ball, which depends on the gravitational acceleration on Planet X.
02

Use the Kinematic Equation

To find the gravitational acceleration, use the kinematic equation: \[ h = \frac{1}{2} g t^2 \]Here, \( h = 10 \text{ m} \) and \( t = 3.4 \text{ s} \). Substitute these values into the equation to solve for \( g \).
03

Solve for Gravitational Acceleration

Rearrange the equation to solve for \( g \):\[ g = \frac{2h}{t^2} \]Substitute the known values: \[ g = \frac{2 \times 10}{(3.4)^2} \approx \frac{20}{11.56} \approx 1.73 \text{ m/s}^2 \]
04

Calculate the Weight of the Ball

The weight of the ball \( W \) is given by \( W = mg \), where \( m = 0.1 \text{ kg} \) and \( g = 1.73 \text{ m/s}^2 \).Substitute these values into the equation:\[ W = 0.1 \times 1.73 = 0.173 \text{ N} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematic Equations
Kinematic equations are powerful tools in physics, especially when analyzing motion without regard to the causes of the motion. These equations relate variables like displacement, velocity, acceleration, and time, which can help us solve problems involving projectile motion, free fall, and much more.
In the context of our original exercise on Planet X, the kinematic equation helps us determine how fast things accelerate due to gravity.
When an object falls under gravity from rest, the equation \( h = \frac{1}{2} g t^2 \) comes in handy to find gravitational acceleration, denoted as \( g \). Here, \( h \) is the height from which the object falls, \( t \) is the time taken, and \( g \) is the gravitational acceleration.
To effectively use these equations:
  • Identify the known variables.
  • Plug them into the equation.
  • Solve for the unknown.
By rearranging the equation to \( g = \frac{2h}{t^2} \), calculating \( g \) becomes straightforward once \( h \) and \( t \) are known.
This equation's simplicity is what makes it so useful in both classroom exercises and real-world physics problems!
Weight Calculation
Understanding weight calculation is crucial, as weight is often confused with mass.
While mass is the amount of matter in an object, weight is the force with which it is pulled towards a celestial body, like a planet.
Thus, weight depends on both the mass of the object and the gravity of the place it resides.
Mathematically, weight \( W \) is found using the equation:\[ W = mg \]where \( m \) is the mass in kilograms and \( g \) is the gravitational acceleration in \( \text{m/s}^2 \).
For example, on Earth, \( g \approx 9.8 \text{ m/s}^2 \), but on Planet X, we found \( g \approx 1.73 \text{ m/s}^2 \).
Once \( g \) is known, you simply multiply it by the mass to get the weight.
Since weight is a force, its unit is the Newton (N).
This calculation is critical for understanding how different planetary environments affect how heavy or light objects feel. Always remember, even if the mass does not change, the weight can vary greatly from planet to planet!
Planetary Physics
Planetary physics is a fascinating field that explores the physical characteristics and phenomena of planets and other celestial bodies.
It encompasses the study of gravity, atmospheres, magnetic fields, and more.
For instance, the exercise on Planet X illustrates how gravitational acceleration differs from one planet to another.
These differences arise mainly due to the mass and radius of the planet.
Gravitational acceleration \( g \) is influenced by the planet’s mass \( M \) and the distance from its center \( r \), according to the formula:\[ g = \frac{GM}{r^2} \]where \( G \) is the universal gravitational constant.
Understanding such concepts can help us predict and explore how conditions vary across planets:
  • How much does a space probe weigh on different planets?
  • Would a human feel lighter or heavier?
  • What would be the flight path of a projectile?
Such knowledge is not only vital for space exploration but also helps deepen our understanding of Earth and its place in the universe!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A box rests on a frozen pond, which serves as a frictionless horizontal surface. If a fisherman applies a horizontal force with magnitude 48.0 N to the box and produces an acceleration of magnitude 2.20 m/s\(^2\), what is the mass of the box?

A chair of mass 12.0 kg is sitting on the horizontal floor; the floor is not frictionless. You push on the chair with a force \(F =\) 40.0 N that is directed at an angle of 37.0\(^\circ\) below the horizontal, and the chair slides along the floor. (a) Draw a clearly labeled free-body diagram for the chair. (b) Use your diagram and Newton's laws to calculate the normal force that the floor exerts on the chair.

Forces \(\vec{F_1}\) and \(\vec{F_2}\)act at a point. The magnitude of \(\vec{F_1}\) is 9.00 N, and its direction is 60.0\(^\circ\) above the \(x\)-axis in the second quadrant. The magnitude of \(\vec{F_2}\) is 6.00 N, and its direction is 53.1\(^\circ\) below the \(x\)-axis in the third quadrant. (a) What are the \(x\)- and \(y\)-components of the resultant force? (b) What is the magnitude of the resultant force?

At the surface of Jupiter's moon Io, the acceleration due to gravity is g = 1.81 m/s\(^2\). A watermelon weighs 44.0 N at the surface of the earth. (a) What is the watermelon's mass on the earth's surface? (b) What would be its mass and weight on the surface of Io?

A mysterious rocket-propelled object of mass 45.0 kg is initially at rest in the middle of the horizontal, frictionless surface of an ice-covered lake. Then a force directed east and with magnitude \(F(t) =\) (16.8 N/s)\(t\) is applied. How far does the object travel in the first 5.00 s after the force is applied?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.