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Calculate the de Broglie wavelength of a 5.00-g bullet that is moving at 340 m/s. Will the bullet exhibit wavelike properties?

Short Answer

Expert verified
The wavelength is \( 3.90 \times 10^{-34} \, \text{m} \); the bullet does not exhibit wavelike properties.

Step by step solution

01

Understanding de Broglie Wavelength

The de Broglie wavelength formula is given by \( \lambda = \frac{h}{p} \), where \( \lambda \) is the wavelength, \( h \) is Planck's constant \( (6.626 \times 10^{-34} \, \text{m}^2\text{kg/s}) \), and \( p \) is the momentum of the object.
02

Calculate Momentum

Momentum \( p \) is calculated by the formula \( p = mv \), where \( m \) is the mass of the bullet (5.00 g = 0.005 kg) and \( v \) is the velocity (340 m/s). Thus, \( p = 0.005 \, \text{kg} \times 340 \, \text{m/s} = 1.7 \, \text{kg m/s} \).
03

Calculate de Broglie Wavelength

Substitute \( p = 1.7 \, \text{kg m/s} \) into the de Broglie wavelength formula: \( \lambda = \frac{6.626 \times 10^{-34} \, \text{m}^2\text{kg/s}}{1.7 \, \text{kg m/s}} = 3.90 \times 10^{-34} \, \text{m} \).
04

Evaluate Wavelike Properties

The wavelength calculated, \( 3.90 \times 10^{-34} \, \text{m} \), is extremely small, smaller than any known physical scale in which wave properties are significant. Therefore, the bullet will not exhibit wavelike properties.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

de Broglie Wavelength
The de Broglie wavelength is a fundamental concept in quantum mechanics which describes the wave-particle duality of matter. According to this principle, every particle possesses a wavelength that is inversely proportional to its momentum. This concept was introduced by Louis de Broglie in 1924 and revolutionized our understanding of physical matter.

The formula used to calculate the de Broglie wavelength is:
  • \( \lambda = \frac{h}{p} \)
Here,
  • \( \lambda \) is the de Broglie wavelength.
  • \( h \) is Planck's constant.
  • \( p \) is the momentum of the particle.
This framework implies that all moving objects have wavelike properties, although in practical terms, such effects are detectable only at the atomic or subatomic level.

For instance, the calculated de Broglie wavelength of a macroscopic object like a bullet is minuscule and hence unobservable in everyday situations, pointing to the quantum nature of this phenomenon.
Planck's Constant
Planck's constant is a pivotal numerical value in quantum mechanics that relates the energy of photons to their frequency. It is denoted by the symbol \( h \), and its value is approximately \( 6.626 \times 10^{-34} \, \text{m}^2 \text{kg/s} \).

This constant was introduced by Max Planck in 1900, during his exploration of black body radiation, marking the inception of quantum theory. Planck's constant has units of action (energy multiplied by time) and is essential in calculations involving the photoelectric effect, quantum tunneling, and energy-level transitions in atoms.

In the context of the de Broglie wavelength, Planck's constant is a crucial factor in determining the wavelength associated with a particle, as expressed in the equation \( \lambda = \frac{h}{p} \). This underlines the intrinsic linkage between quantum theory and classical mechanics through Planck's constant.
Momentum Calculation
Momentum is a vital concept in both classical and quantum physics, representing the quantity of motion an object possesses. It is a vector quantity, meaning it has both magnitude and direction, defined as the product of an object's mass and velocity. The formula to calculate momentum \( p \) is:
  • \( p = mv \)
Where,
  • \( m \) is the mass of the object in kilograms.
  • \( v \) is the velocity of the object in meters per second.
Momentum plays a fundamental role in analyzing systems and understanding interactions, such as collisions, where the total momentum is conserved.

In terms of quantum applications, the momentum of a particle helps in determining the de Broglie wavelength, bridging classical mechanics and quantum phenomena. As shown in our example with the bullet, a thorough understanding of momentum is crucial for applying de Broglie's formula effectively.

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Most popular questions from this chapter

(a) What accelerating potential is needed to produce electrons of wavelength 5.00 nm? (b) What would be the energy of photons having the same wavelength as these electrons? (c) What would be the wavelength of photons having the same energy as the electrons in part (a)?

Pulsed dye lasers emit light of wavelength 585 nm in 0.45-ms pulses to remove skin blemishes such as birthmarks. The beam is usually focused onto a circular spot 5.0 mm in diameter. Suppose that the output of one such laser is 20.0 W. (a) What is the energy of each photon, in eV? (b) How many photons per square millimeter are delivered to the blemish during each pulse?

Imagine another universe in which the value of Planck's constant is 0.0663 J \(\cdot\) s, but in which the physical laws and all other physical constants are the same as in our universe. In this universe, two physics students are playing catch. They are 12 m apart, and one throws a 0.25-kg ball directly toward the other with a speed of 6.0 m/s. (a) What is the uncertainty in the ball's horizontal momentum, in a direction perpendicular to that in which it is being thrown, if the student throwing the ball knows that it is located within a cube with volume 125 cm\(^3\) at the time she throws it? (b) By what horizontal distance could the ball miss the second student?

The negative muon has a charge equal to that of an electron but a mass that is 207 times as great. Consider a hydrogenlike atom consisting of a proton and a muon. (a) What is the reduced mass of the atom? (b) What is the ground-level energy (in electron volts)? (c) What is the wavelength of the radiation emitted in the transition from the \(n\) = 2 level to the \(n\) = 1 level?

(a) An atom initially in an energy level with \(E\) = -6.52 eV absorbs a photon that has wavelength 860 nm. What is the internal energy of the atom after it absorbs the photon? (b) An atom initially in an energy level with \(E\) = -2.68 eV emits a photon that has wavelength 420 nm. What is the internal energy of the atom after it emits the photon?

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