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If a muon is traveling at 0.999c, what are its momentum and kinetic energy? (The mass of such a muon at rest in the laboratory is 207 times the electron mass.)

Short Answer

Expert verified
Momentum is \(1.26 \times 10^{-18}\, \text{kg}\cdot \text{m/s}\); Kinetic energy is \(1.88 \times 10^{-10}\, \text{J}\).

Step by step solution

01

Determine the Rest Mass of the Muon

Given that the rest mass of the muon is 207 times the electron rest mass, calculate the rest mass of the muon. The rest mass of an electron is approximately \( 9.11 \times 10^{-31} \) kg. Therefore, the rest mass of the muon, \( m_0 \), is: \[ m_0 = 207 \times 9.11 \times 10^{-31} \text{ kg} \approx 1.88 \times 10^{-28} \text{ kg}. \]
02

Calculate the Lorentz Factor (Gamma)

The Lorentz factor \( \gamma \) is calculated using the formula: \[ \gamma = \frac{1}{\sqrt{1 - \left(\frac{v}{c}\right)^2}}. \] Here, \( v = 0.999c \). Substituting the value we have: \[ \gamma = \frac{1}{\sqrt{1 - (0.999)^2}}. \] This simplifies to \( \gamma \approx 22.366 \).
03

Calculate the Relativistic Momentum

The relativistic momentum \( p \) is given by the formula: \[ p = \gamma m_0 v. \] Substituting the values we have: \[ p = 22.366 \times 1.88 \times 10^{-28} \text{ kg} \times 0.999c, \] where \( c = 3 \times 10^8 \text{ m/s} \). Thus, \[ p \approx 1.26 \times 10^{-18} \text{ kg} \cdot \text{m/s}. \]
04

Calculate the Kinetic Energy

The relativistic kinetic energy \( KE \) is calculated using: \[ KE = (\gamma - 1)m_0 c^2. \] Substituting the values: \[ KE = (22.366 - 1) \times 1.88 \times 10^{-28} \text{ kg} \times (3 \times 10^8 \text{ m/s})^2. \] Calculating this gives: \[ KE \approx 1.88 \times 10^{-10} \text{ Joules}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Muon
Muons are fascinating subatomic particles that belong to the family of leptons. They are similar to electrons but are approximately 207 times heavier. Unlike electrons, which are quite stable, muons are unstable and have a short lifespan of only about 2.2 microseconds. Due to their heavier mass, they have interesting applications in high-energy physics experiments. For instance, studying muons helps scientists understand more about fundamental particles and forces. In the context of relativistic physics, because muons can travel at relativistic speeds near that of light, they provide wonderful practical examples to learn about special relativity concepts, such as time dilation and length contraction.
Lorentz factor
The Lorentz factor, often denoted as \(\gamma\), is pivotal in relativistic physics. It accounts for the effects that occur when objects travel at speeds close to the speed of light. Calculated using the formula: \[ \gamma = \frac{1}{\sqrt{1 - \left(\frac{v}{c}\right)^2}} \]where \( v \) is the velocity of the object and \( c \) is the speed of light, the factor explains how time, length, and relativistic mass change with speed.
  • Time Dilation: Time appears to move slower from the perspective of the moving object.
  • Length Contraction: Objects appear shorter in the direction of motion as they approach the speed of light.
  • Mass Increase: The relativistic mass increases as speed increases.
In this exercise, the muon travels at 0.999c, resulting in a Lorentz factor of around 22.366, meaning these relativistic effects are highly pronounced.
Relativistic Momentum
Momentum in the realms of relativity differs from classical interpretations. The momentum at relativistic speeds incorporates the Lorentz factor \(\gamma\) and is given by the formula: \[ p = \gamma m_0 v \]where \( m_0 \) is the rest mass of the particle. This formula recognizes that as an object's speed approaches the speed of light, its momentum doesn't just depend on velocity and mass but also significantly on the Lorentz factor.
The presence of \(\gamma\) illustrates how momentum increases dramatically at high velocities. For the muon in our exercise, with a speed of 0.999c, relativistic momentum measures approximately \(1.26 \times 10^{-18}\) kgâ‹…m/s, showcasing the substantial impact of the Lorentz factor when speed nears light speed.
Kinetic Energy
In classical physics, kinetic energy is straightforward to compute using the formula \( KE = \frac{1}{2}mv^2 \). However, under relativistic conditions, where speeds approach the speed of light, this formula is inadequate. Instead, the relativistic kinetic energy is determined by: \[ KE = (\gamma - 1)m_0 c^2 \]Here, \(\gamma\) again plays a crucial role, compensating for the speed's nearness to light speed. As objects reach higher velocities, \(\gamma\) results in a massive increase in kinetic energy, diverging from classical predictions.
For our muon, traveling at 0.999c, this formula calculates the kinetic energy to be about \(1.88 \times 10^{-10}\) Joules, which is a substantial amount due to the relativistic speeds achieved. Understanding this shift from classical to relativistic kinetic energy helps in grasping how energy scales differently at high velocities.

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Most popular questions from this chapter

A space probe is sent to the vicinity of the star Capella, which is 42.2 light-years from the earth. (A light-year is the distance light travels in a year.) The probe travels with a speed of 0.9930c. An astronaut recruit on board is 19 years old when the probe leaves the earth. What is her biological age when the probe reaches Capella?

An electron is acted upon by a force of 5.00 \(\times\) 10\(^{-15}\) N due to an electric field. Find the acceleration this force produces in each case: (a) The electron's speed is 1.00 km/s. (b) The electron's speed is 2.50 \(\times\) 10\(^8\) m/s and the force is parallel to the velocity.

A spacecraft flies away from the earth with a speed of 4.80 \(\times\) 10\(^6\) m/s relative to the earth and then returns at the same speed. The spacecraft carries an atomic clock that has been carefully synchronized with an identical clock that remains at rest on earth. The spacecraft returns to its starting point 365 days (1 year) later, as measured by the clock that remained on earth. What is the difference in the elapsed times on the two clocks, measured in hours? Which clock, the one in the spacecraft or the one on earth, shows the shorter elapsed time?

An imperial spaceship, moving at high speed relative to the planet Arrakis, fires a rocket toward the planet with a speed of 0.920c relative to the spaceship. An observer on Arrakis measures that the rocket is approaching with a speed of 0.360c. What is the speed of the spaceship relative to Arrakis? Is the spaceship moving toward or away from Arrakis?

An observer in frame \(S'\) is moving to the right (+\(x\)-direction) at speed \(u\) = 0.600c away from a stationary observer in frame S. The observer in \(S'\) measures the speed \(v'\) of a particle moving to the right away from her. What speed \(v'\) does the observer in S measure for the particle if (a) \(v'\) = 0.400c; (b) \(v'\) = 0.900c; (c) \(v'\) = 0.990c?

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