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A diffraction grating has 650 slits>mm. What is the highest order that contains the entire visible spectrum? (The wavelength range of the visible spectrum is approximately 380-750 nm.)

Short Answer

Expert verified
The highest order is 2.

Step by step solution

01

Convert Slits per Millimeter to Line Spacing

The number of slits per millimeter is given as 650. To find the grating spacing (d), which is the distance between adjacent slits, we need to take the reciprocal. The slits per millimeter can be converted to slits per meter by multiplying by 1000, so d can be calculated as:\[ d = \frac{1}{650 \times 1000} \text{ m} \approx 1.54 \times 10^{-6} \text{ m} \]
02

Use the Diffraction Grating Equation

The diffraction grating equation is given by:\[ d \sin(\theta) = m \lambda \] where d is the grating spacing, \( \theta \) is the diffraction angle, m is the order, and \( \lambda \) is the wavelength. The highest order that contains the entire visible spectrum can be found by setting \( \theta = 90^\circ \) (since \( \sin(90^\circ) = 1 \)), hence the equation simplifies to:\[ m = \frac{d}{\lambda} \]
03

Calculate Orders for Boundary Wavelengths

Calculate the order number for the smallest and largest wavelengths in the visible spectrum, 380 nm and 750 nm:\[m_{380} = \frac{1.54 \times 10^{-6}}{380 \times 10^{-9}} \approx 4.05 \]\[m_{750} = \frac{1.54 \times 10^{-6}}{750 \times 10^{-9}} \approx 2.05 \]
04

Determine the Highest Order Containing the Entire Spectrum

The smallest whole number m that satisfies both conditions (and is common for the entire range of wavelengths) is the highest order that contains the entire spectrum. Since \( m_{750} \approx 2.05 \) allows only for orders \( m = 1 \) and \( m = 2 \) within the visible range, the highest order is 2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Visible Spectrum
The visible spectrum refers to the range of light wavelengths visible to the human eye. This spectrum is part of the electromagnetic spectrum and ranges approximately from 380 to 750 nanometers (nm).
The light we perceive as white is actually made up of these different wavelengths, each corresponding to a different color.
Within the visible spectrum:
  • Shorter wavelengths (around 380-450 nm) relate to violet and blue light.
  • Medium wavelengths (around 450-600 nm) appear as green to yellow light.
  • Longer wavelengths (around 600-750 nm) are perceived as orange to red light.
Understanding the visible spectrum is essential for analyzing how light behaves when it interacts with optical elements like a diffraction grating, allowing us to separate or analyze light of different colors.
Wavelengths
Wavelengths are a crucial concept in understanding light and its various properties. They denote the distance between consecutive peaks of a wave.
In the context of light, wavelengths determine the color perceived by human eyes.
For example:
  • Violet light has a wavelength of around 380-450 nm.
  • Green light has wavelengths roughly between 500-550 nm.
  • Red light typically has wavelengths ranging from 620-750 nm.
Wavelengths are fundamental in calculating diffraction patterns, as different wavelengths will diffract to different angles. This property allows diffraction gratings to separate light into its component colors, similar to how a prism works.
Diffraction Order
Diffraction order, represented by the variable 'm', refers to the interference pattern produced by a diffraction grating. It indicates the number of wavelengths by which different paths differ after passing through the grating.
The order determines the angle at which the waves constructively interfere, forming bright regions in the diffraction pattern.
  • The first order (m=1) is the primary set of diffracted light bands, appearing closest to the central zero-order maximum.
  • Higher orders provide additional sets of diffracted light bands, farther from the central maximum.
The exercise details explored how to calculate the highest order that accommodates light across all visible wavelengths (380-750 nm) while ensuring they remain within the visible spectrum. For the calculated scenario, the highest diffraction order allowing all wavelengths was found to be 2.
Slit Spacing
Slit spacing, denoted by 'd', is the distance between adjacent slits in a diffraction grating. It is crucial for determining the diffraction pattern produced.
The relation between slit spacing and light wavelength affects the diffraction order's angles and positions.
To find slit spacing, one needs the number of slits per unit length; in this exercise, 650 slits per millimeter were provided.
By converting this to meters and calculating the reciprocal, we find:
  • Slit spacing, d = 1/650,000 meters ≈ 1.54 x 10-6 meters.
This calculation is vital for applying the diffraction grating equation: \[ d \sin(\theta) = m \lambda \] Slit spacing determines how the entire visible spectrum is separated in this context, assisting in computing the diffraction order across the visible range.

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Most popular questions from this chapter

Why is visible light, which has much longer wavelengths than x rays do, used for Bragg reflection experiments on colloidal crystals? (a) The microspheres are suspended in a liquid, and it is more difficult for x rays to penetrate liquid than it is for visible light. (b) The irregular spacing of the microspheres allows the longerwavelength visible light to produce more destructive interference than can x rays. (c) The microspheres are much larger than atoms in a crystalline solid, and in order to get interference maxima at reasonably large angles, the wavelength must be much longer than the size of the individual scatterers. (d) The microspheres are spaced more widely than atoms in a crystalline solid, and in order to get interference maxima at reasonably large angles, the wavelength must be comparable to the spacing between scattering planes.

A single-slit diffraction pattern is formed by monochromatic electromagnetic radiation from a distant source passing through a slit 0.105 mm wide. At the point in the pattern 3.25\(^\circ\) from the center of the central maximum, the total phase difference between wavelets from the top and bottom of the slit is 56.0 rad. (a) What is the wavelength of the radiation? (b) What is the intensity at this point, if the intensity at the center of the central maximum is \(I_0\)?

If a diffraction grating produces its third-order bright band at an angle of 78.4\(^\circ\) for light of wavelength 681 nm, find (a) the number of slits per centimeter for the grating and (b) the angular location of the first-order and second-order bright bands. (c) Will there be a fourth-order bright band? Explain.

A wildlife photographer uses a moderate telephoto lens of focal length 135 mm and maximum aperture \(f/\)4.00 to photograph a bear that is 11.5 m away. Assume the wavelength is 550 nm. (a) What is the width of the smallest feature on the bear that this lens can resolve if it is opened to its maximum aperture? (b) If, to gain depth of field, the photographer stops the lens down to \(f/\)22.0, what would be the width of the smallest resolvable feature on the bear?

A thin slit illuminated by light of frequency \(f\) produces its first dark band at \(\pm\)38.2\(^\circ\) in air. When the entire apparatus (slit, screen, and space in between) is immersed in an unknown transparent liquid, the slit's first dark bands occur instead at \(\pm\)21.6\(^\circ\). Find the refractive index of the liquid.

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