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Suppose you illuminate two thin slits by monochromatic coherent light in air and find that they produce their first interference \(minima\) at \(\pm35.20^\circ\) on either side of the central bright spot. You then immerse these slits in a transparent liquid and illuminate them with the same light. Now you find that the first minima occur at \(\pm19.46^\circ\) instead. What is the index of refraction of this liquid?

Short Answer

Expert verified
The index of refraction is approximately 1.73.

Step by step solution

01

Understanding the Problem

We have two thin slits giving interference minima at different angles in air and in a liquid. We need to find the index of refraction of the liquid.
02

Formula for Interference Minima

For interference minima, the path difference is an integral multiple of the wavelength. The formula is given by \(d \sin \theta = m \lambda\), where \(d\) is the slit separation, \(m\) is the order of minimum (1 for first minimum), and \(\theta\) is the angle.
03

Initial Condition in Air

Using the formula \(d \sin \theta = m \lambda\) for air where the first minima occur at \(\theta = 35.20^\circ\), we have \(d \sin 35.20^\circ = \lambda\).
04

Condition in Liquid

In the liquid, using the same formula, but now \(\theta = 19.46^\circ\), we have \(d \sin 19.46^\circ = \lambda'\).
05

Ratio of Wavelengths

The ratio of wavelengths \(\frac{\lambda'}{\lambda}\) is equal to the refractive index \( n \). So, we write \(n = \frac{\lambda}{\lambda'} = \frac{\sin 35.20^\circ}{\sin 19.46^\circ}\).
06

Calculation of Refractive Index

Calculate the sin values: \(\sin 35.20^\circ \approx 0.576\) and \(\sin 19.46^\circ \approx 0.333\). Therefore, \(n = \frac{0.576}{0.333} \approx 1.73\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Monochromatic Coherent Light
Monochromatic coherent light refers to light with a single wavelength and phase consistency. This type of light is essential in experiments involving thin slit interference, such as the one described in the exercise. A common source of monochromatic coherent light is a laser, as it provides narrow wavelength radiation.
  • Monochromatic: This term indicates that the light has one color or wavelength. Unlike sunlight, which consists of a spectrum of colors, monochromatic light ensures uniformity in experiments.

  • Coherent: Coherent light means all the waves are in phase with one another. This allows for predictable and stable interference patterns when the waves pass through slits.

Understanding these properties is crucial because the interference pattern’s structure, including the formation of bright and dark spots, depends on these characteristics of the light used.
Index of Refraction
The index of refraction, represented by the symbol \( n \), is a measure of how much light slows down as it enters a medium. It compares the speed of light in a vacuum to the speed of light in the given medium and is defined as \( n = \frac{c}{v} \), where \( c \) is the speed of light in a vacuum and \( v \) is the speed of light in the medium.

In the context of the exercise, the refractive index affects the angle at which interfence phenomena occur. When light enters a medium like a liquid from air, its velocity decreases, bending the light path. This bending alters the angle \( \theta \) at which interference minima and maxima occur, thus changing the interference pattern observed.
  • Bending of Light: The difference in velocity between mediums leads to the bending of beams, explained by Snell's Law \( n_1 \sin \theta_1 = n_2 \sin \theta_2 \).

  • Significance in Experiments: Knowing the refractive index allows scientists to predict how light will behave in different media, crucial for applications ranging from optical lenses to the design of entire optical systems.

Interference Minima
Interference minima occur when waves overlap in such a way that they cancel each other out. This phenomenon is crucial to understanding and calculating interference patterns in thin slit experiments.

The condition for interference minima in a double-slit experiment is when the path difference between the waves is an odd multiple of half wavelengths, described mathematically as \( d \sin \theta = m \lambda \) for minima, where \( m \) is the order of the minimum.
  • Path Difference: For a slit setup, the waves travel different distances before overlapping, leading to constructive (maximum) or destructive (minimum) interference.

  • Evaluating Angles: As described in the exercise, changes in medium (e.g., air to liquid) will shift these angles, providing a method to determine properties like refractive index.

Recognizing these conditions aids in interpreting experimental data, particularly in determining how light interacts with different materials.
Wavelength Ratio
The wavelength ratio, particularly \( \frac{\lambda'}{\lambda} \), is the comparative measure of the wavelength of light in different mediums. It directly relates to the refractive index of those mediums.

In the exercise, this ratio is crucial because it helps establish the refractive index of the liquid into which the slits are immersed. The equation \( n = \frac{\lambda}{\lambda'} = \frac{\sin 35.20^\circ}{\sin 19.46^\circ} \) is derived from understanding the relationship between the angle of minima and the wavelength in two different media.
  • Direct Reflection of Speed Change: Wavelength in a medium changes inversely with speed; thus, \( n \) reflects how much slower light travels in the medium compared to a vacuum.

  • Application: By using the measured angles and understanding the wavelength shift, one can determine unknown refractive indices, as demonstrated by the calculation yielding \( n \approx 1.73 \).

This concept illustrates the interplay between light's speed and wavelength, forming the foundation for analyzing optical systems and enhancing our understanding of light's behavior in different environments.

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Most popular questions from this chapter

In your research lab, a very thin, flat piece of glass with refractive index 1.40 and uniform thickness covers the opening of a chamber that holds a gas sample. The refractive indexes of the gases on either side of the glass are very close to unity. To determine the thickness of the glass, you shine coherent light of wavelength \(\lambda_0\) in vacuum at normal incidence onto the surface of the glass. When \(\lambda_0\) = 496 nm, constructive interference occurs for light that is reflected at the two surfaces of the glass. You find that the next shorter wavelength in vacuum for which there is constructive interference is 386 nm. (a) Use these measurements to calculate the thickness of the glass. (b) What is the longest wavelength in vacuum for which there is constructive interference for the reflected light?

Eyeglass lenses can be coated on the \(inner\) surfaces to reduce the reflection of stray light to the eye. If the lenses are medium flint glass of refractive index 1.62 and the coating is fluorite of refractive index 1.432, (a) what minimum thickness of film is needed on the lenses to cancel light of wavelength 550 nm reflected toward the eye at normal incidence? (b) Will any other wavelengths of visible light be cancelled or enhanced in the reflected light?

A researcher measures the thickness of a layer of benzene (\(n\) = 1.50) floating on water by shining monochromatic light onto the film and varying the wavelength of the light. She finds that light of wavelength 575 nm is reflected most strongly from the film. What does she calculate for the minimum thickness of the film?

Two speakers that are 15.0 m apart produce in-phase sound waves of frequency 250.0 Hz in a room where the speed of sound is 340.0 m/s. A woman starts out at the midpoint between the two speakers. The room's walls and ceiling are covered with absorbers to eliminate reflections, and she listens with only one ear for best precision. (a) What does she hear: constructive or destructive interference? Why? (b) She now walks slowly toward one of the speakers. How far from the center must she walk before she first hears the sound reach a minimum intensity? (c) How far from the center must she walk before she first hears the sound maximally enhanced?

Laser light of wavelength 510 nm is traveling in air and shines at normal incidence onto the flat end of a transparent plastic rod that has \(n\) = 1.30. The end of the rod has a thin coating of a transparent material that has refractive index 1.65. What is the minimum (nonzero) thickness of the coating (a) for which there is maximum transmission of the light into the rod; (b) for which transmission into the rod is minimized?

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