/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 A person swimming 0.80 m below t... [FREE SOLUTION] | 91Ó°ÊÓ

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A person swimming 0.80 m below the surface of the water in a swimming pool looks at the diving board that is directly overhead and sees the image of the board that is formed by refraction at the surface of the water. This image is a height of 5.20 m above the swimmer. What is the actual height of the diving board above the surface of the water?

Short Answer

Expert verified
The actual height of the diving board above the water's surface is 4.71 m.

Step by step solution

01

Consider the Refraction Index

The refractive index of water is approximately 1.33. We use this value to understand how light bends when moving from water to air.
02

Understand Apparent Height

When light travels from water to air, it bends away from the normal due to refraction. This causes the apparent height of objects viewed underwater to be different from the actual height. The apparent depth (\(d_a\)) and actual depth (\(d_r\)) are related by the equation:\[ \frac{d_a}{d_r} = n \]where \(n\) is the refractive index of water.
03

Calculate Actual Height of Image

Let's isolate \(d_r\) in the formula to find the actual height:\[ d_r = \frac{d_a}{n} \]Given the apparent height of the image above the swimmer is 5.20 m, substitute in the values:\[ d_r = \frac{5.20}{1.33} = 3.91\, \text{m} \]Therefore, the apparent height seen by the swimmer corresponds to an actual height of 3.91 m above the swimmer.
04

Calculate Actual Height of Diving Board

The swimmer is positioned 0.80 m below the surface. To find the actual height of the diving board from the water's surface, we add the swimmer's depth to the actual height calculated:\[ \text{Actual height of the diving board} = 3.91 + 0.80 = 4.71\, \text{m} \]This value represents the actual height of the diving board above the water's surface.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

The Magic of Refractive Index
The refractive index is a measure that tells us how much light bends when it travels between two different materials. In simple words, it is a value that shows how fast light travels in one medium compared to another. For water, the refractive index is about 1.33. This means light slows down and bends as it moves from air into water.

Why is it important? Because the bending of light affects how we see things underwater. When light hits the surface between air and water, it changes speed and direction. This "bending" causes underwater objects to appear changed in position. This idea of bending is crux to understanding how refraction affects our perception.

  • Key Value for Water: 1.33
  • Affects how objects appear under water surfaces
  • Impacts many aspects of optics and vision
Understanding refractive index helps us know why things aren’t always where we think they are when viewed across water surfaces.
Exploring Apparent Depth
When you dip a stick into the water, it looks bent at the point where air and water meet. This happens because of the difference between apparent and actual depth. Apparent depth is how deep an object seems under water due to light bending. But wait, the actual depth is different! That's where the water's refractive index changes things.

We use the formula: \[ \frac{d_a}{d_r} = n \] where \(d_a\) is apparent depth, \(d_r\) is the actual depth, and \(n\) is the refractive index. This equation helps compare what we see with reality. The apparent depth is often less than the actual depth because of the light's journey.
  • Apparent depth is the "seen" depth
  • Understanding it needs the refractive index
  • Helps explain why things look shifted
Apparent depth can make underwater objects seem closer to the surface than they are.
The Phenomenon of Light Bending
Light bending is another way to say refraction in simpler terms. When light passes from one medium to another, like from air to water, it changes speed. This speed change causes light to "bend" or change its path. The greater the difference in speed between the two media, the more the light will bend.

Why does this happen? Flight paths change due to different optical densities of materials. Water is denser than air, slowing the light down and bending it as it crosses the boundary. This bending explains the apparent shift in position of both close and far objects when seen through water.
  • Light changes direction and speed
  • Caused by different mediums with different speeds
  • Important in optics and everyday phenomena
Light bending is why we often misjudge the location of objects submerged in water.
Precise Actual Height Calculation
Calculating the actual height of submerged objects needs a systematic approach. When dealing with situations like a swimmer observing a diving board, knowing how to find the true height is essential. Here's how we do it using our optical toolkit!

First, use the given apparent height and the refractive index of water to calculate the actual height. The formula: \[ d_r = \frac{d_a}{n} \] helps us determine the actual height, \(d_r\), using the apparent height, \(d_a\), and the water's refractive index, \(n\).
For instance, in our exercise, the image height above the swimmer might appear 5.20 m. Plugging the numbers in:\[ d_r = \frac{5.20}{1.33} \approx 3.91\, \text{m}\]This value places the actual height above the swimmer accurately. But wait, remember the swimmer's depth under the surface?

To get the diving board's complete height, add the swimmer's depth (0.80 m in this case) to the actual image height:\[ \text{Actual height of diving board} = 3.91 + 0.80 = 4.71\, \text{m}\]
  • Starts with finding actual image height
  • Ends with adding swimmer's depth
  • Crucial for accurate measurements
This method ensures the final measurement is true to life, not just what one perceives!

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Most popular questions from this chapter

The left end of a long glass rod 8.00 cm in diameter, with an index of refraction of 1.60, is ground and polished to a convex hemispherical surface with a radius of 4.00 cm. An object in the form of an arrow 1.50 mm tall, at right angles to the axis of the rod, is located on the axis 24.0 cm to the left of the vertex of the convex surface. Find the position and height of the image of the arrow formed by paraxial rays incident on the convex surface. Is the image erect or inverted?

Given that frogs are nearsighted in air, which statement is most likely to be true about their vision in water? (a) They are even more nearsighted; because water has a higher index of refraction than air, a frog's ability to focus light increases in water. (b) They are less nearsighted, because the cornea is less effective at refracting light in water than in air. (c) Their vision is no different, because only structures that are internal to the eye can affect the eye's ability to focus. (d) The images projected on the retina are no longer inverted, because the eye in water functions as a diverging lens rather than a converging lens.

In one form of cataract surgery the person's natural lens, which has become cloudy, is replaced by an artificial lens. The refracting properties of the replacement lens can be chosen so that the person's eye focuses on distant objects. But there is no accommodation, and glasses or contact lenses are needed for close vision. What is the power, in diopters, of the corrective contact lenses that will enable a person who has had such surgery to focus on the page of a book at a distance of 24 cm?

An object to the left of a lens is imaged by the lens on a screen 30.0 cm to the right of the lens. When the lens is moved 4.00 cm to the right, the screen must be moved 4.00 cm to the left to refocus the image. Determine the focal length of the lens.

The left end of a long glass rod 6.00 cm in diameter has a convex hemispherical surface 3.00 cm in radius. The refractive index of the glass is 1.60. Determine the position of the image if an object is placed in air on the axis of the rod at the following distances to the left of the vertex of the curved end: (a) infinitely far, (b) 12.0 cm; (c) 2.00 cm.

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