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The critical angle for total internal reflection at a liquid air interface is 42.5\(^\circ\). (a) If a ray of light traveling in the liquid has an angle of incidence at the interface of 35.0\(^\circ\), what angle does the refracted ray in the air make with the normal? (b) If a ray of light traveling in air has an angle of incidence at the interface of 35.0\(^\circ\), what angle does the refracted ray in the liquid make with the normal?

Short Answer

Expert verified
Apply Snell's Law to find the refraction angle.

Step by step solution

01

Understand Critical Angle

The critical angle is the angle of incidence above which total internal reflection occurs. It is given as 42.5° for the liquid-air interface.
02

Step 2a: Apply Snell's Law for (a)

In part (a), since the angle of incidence (35.0°) is less than the critical angle (42.5°), Snell's Law can be used. Snell's Law is: \( n_1 \sin \theta_1 = n_2 \sin \theta_2 \). The angle of refraction \( \theta_2 \) can be calculated using the known indices of refraction, with \( n_1 = n_{liquid} \) and \( n_2 = n_{air} \). However, solve for \( \theta_2 \):

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Angle
The critical angle is a key concept when studying total internal reflection. It is the specific angle of incidence at which light changes its behavior when moving from a denser medium to a less dense one, like from water to air. If the angle of incidence is greater than this critical angle, light will not refract into the second medium, but instead, reflect entirely within the first medium. This is what we call total internal reflection.

For a given pair of media, the critical angle can be determined using the formula:\[\text{Critical angle}, \theta_c = \arcsin\left(\frac{n_2}{n_1}\right)\]where:
  • \( n_1 \) is the refractive index of the initial medium (the liquid in our exercise).
  • \( n_2 \) is the refractive index of the second medium (the air).
If the angle of incidence is even slightly beyond this point, none of the light will pass through to the other side. In our exercise, the critical angle at a liquid-air interface is given as 42.5\(^\circ\). This information indicates that any incident angle greater than 42.5\(^\circ\) will cause the light to reflect back entirely.
Snell's Law
Snell's Law is a crucial principle in optics that describes how light bends when it passes through different media. It is mathematically represented as:\[ n_1 \sin \theta_1 = n_2 \sin \theta_2\]where:
  • \( n_1 \) and \( n_2 \) are indices of refraction for the first and second medium, respectively.
  • \( \theta_1 \) is the angle of incidence – the angle at which the light hits the interface initially.
  • \( \theta_2 \) is the angle of refraction – the angle between the refracted ray and the normal.
By applying Snell's Law, we can determine how much light will bend as it travels from one medium into another. If the angle of incidence is less than the critical angle, as in part (a) of our exercise, Snell's Law helps us calculate the angle of refraction: by rearranging the equation, we solve for \( \theta_2 \).

This law is fundamental in the sense that it helps in deriving the properties of lenses and understanding how we perceive images through glasses, cameras, and similar optical devices.
Angle of Incidence
The angle of incidence is the angle at which incoming light hits a barrier, measured with respect to a normal. It's crucial in understanding the behavior of light at interfaces, influencing whether it will reflect or refract.

Here's why it's important:
  • When light falls on an interface at an angle smaller than the critical angle, it partially refracts through the second medium, and partial reflection may occur at the boundary.
  • If the angle of incidence is exactly equal to the critical angle, the light will refract along the boundary without entering the second medium.
  • For angles exceeding the critical angle, total internal reflection ensures all the light reflects back within the first medium.
In our exercise, a 35.0\(^\circ\) angle of incidence is used for both parts (a) and (b). This small enough angle compared to the critical angle permits us to apply Snell's Law and results in different refractive behaviors dependent on the medium transition, indicating its relevance in determining how light will behave at various interfaces.

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Most popular questions from this chapter

A light beam is directed parallel to the axis of a hollow cylindrical tube. When the tube contains only air, the light takes 8.72 ns to travel the length of the tube, but when the tube is filled with a transparent jelly, the light takes 1.82 ns longer to travel its length. What is the refractive index of this jelly?

A flat piece of glass covers the top of a vertical cylinder that is completely filled with water. If a ray of light traveling in the glass is incident on the interface with the water at an angle of \(\theta_a = 36.2{^\circ}\), the ray refracted into the water makes an angle of 49.8\(^\circ\) with the normal to the interface. What is the smallest value of the incident angle \(\theta_a\) for which none of the ray refracts into the water?

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