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A space probe 2.0 \(\times\) 10\(^{10}\) m from a star measures the total intensity of electromagnetic radiation from the star to be 5.0 \(\times\) 103 W/m\(^2\). If the star radiates uniformly in all directions, what is its total average power output?

Short Answer

Expert verified
The total average power output of the star is approximately 1.0 × 10^27 W.

Step by step solution

01

Understand the Problem

We are tasked with finding the total average power output of a star, given that a space probe measures the intensity of electromagnetic radiation at a certain distance from the star. The key here is to understand the relationship between intensity and power.
02

Recall the Relationship Between Intensity and Power

The formula to connect intensity and power in a spherically symmetric radiation pattern is \( I = \frac{P}{4\pi r^2} \), where \( I \) is the intensity, \( P \) is the power output, and \( r \) is the distance from the star. We need to rearrange this formula to solve for \( P \).
03

Rearrange the Formula

Rearrange the formula to solve for power \( P \): \( P = I \times 4\pi r^2 \). This equation will allow us to calculate the total power output from the intensity and distance.
04

Plug in the Values

Substitute the given values into the rearranged formula: \( I = 5.0 \times 10^3 \) W/m\(^2\) and \( r = 2.0 \times 10^{10} \) m. So, \( P = 5.0 \times 10^3 \times 4\pi (2.0 \times 10^{10})^2 \).
05

Calculate the Expression

First, calculate \( (2.0 \times 10^{10})^2 = 4.0 \times 10^{20} \). Then compute \( 4\pi \times 4.0 \times 10^{20}\), and finally multiply by \( 5.0 \times 10^3 \). Perform these multiplications to compute \( P \).
06

Final Calculation

Calculate \( 4 \times 4.0 \times \pi = 16\pi \), and then multiply by the remaining terms. Thus, \( P = 5.0 \times 10^3 \times 16\pi \times 10^{20} \) which simplifies and solves to the total power output.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromagnetic Radiation
Electromagnetic radiation is a form of energy that travels through space at the speed of light. It includes a broad range of wavelengths and frequencies, from radio waves to gamma rays.
Everything we see and experience through vision is due to this phenomenon.
Electromagnetic radiation is characterized by its ability to travel through not only vacuum but also various media.
When studying stars, we observe their electromagnetic radiation, which allows us to gather valuable information about their properties and behavior.
Stars emit energy in this form across a wide spectrum, and the intensity of their radiation can tell us a lot about the star's energy output.
In astronomy, electromagnetic radiation provides critical data for understanding celestial objects.
  • It helps measure how far objects are by analyzing the shift in wavelengths, known as redshifts or blueshifts.
  • It determines surface composition and temperature through spectral analysis.
  • And importantly, it allows us to measure a star's luminosity and power output by analyzing the intensity of the radiation received at a specific distance.
Power Output Calculation
Calculating the power output of a star involves understanding the relationship between intensity and power.
Power output, often referred to as luminosity in stellar terms, is the total amount of energy a star emits per second.
The intensity of electromagnetic radiation is the power per unit area received at a distance.
By measuring the intensity at a known distance, we can calculate the total power of the star using the formula: \[ I = \frac{P}{4\pi r^2} \] where
  • \( I \) is the intensity,
  • \( P \) is the power,
  • \( r \) is the radius (distance from the star).
Rearranging the formula to solve for power gives \[ P = I \times 4\pi r^2 \].
For example, consider a star where the electromagnetic intensity measured at a distance of \( 2.0 \times 10^{10} \) m is \( 5.0 \times 10^3 \) W/m\(^2\).
Using the formula, the power output would be calculated by substituting these values into the equation to find the star's total average power output.
This method allows astrophysicists to estimate not only the energy output of distant stars but also contribute to understanding their life cycle and classification.
Spherically Symmetric Radiation
Spherically symmetric radiation is a model used to describe how energy is emitted equally in all directions from a spherical source, such as a star.
This concept simplifies calculations because it assumes that the radiation is distributed uniformly across the surface of an imaginary sphere centered on the star.Understanding this symmetry is crucial when dealing with astrophysical bodies.
  • It allows for simplified mathematical models to calculate energy dispersion and intensity at various distances.
  • The assumption of spherical symmetry eliminates complexities that would arise from uneven emission patterns.
  • It is key in using the intensity formula \( I = \frac{P}{4\pi r^2} \), which considers the area of a sphere (\( 4\pi r^2 \)) over which the energy from the star spreads.
By assuming spherically symmetric radiation, astronomers can focus on determining the star's power output at various distances, making it easier to monitor and compare energy outputs of different stars.This balance and even distribution further help in predicting the effects of radiation on surrounding celestial bodies and space environments.

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Most popular questions from this chapter

An electromagnetic wave has an electric field given by \(\vec{E} (y, t)\) = (3.10 \(\times\) 10\(^5\) V/m) \(\hat{k}\) cos [ky - (12.65 \(\times\) 10\(^{12}\) rad/s)t]. (a) In which direction is the wave traveling? (b) What is the wavelength of the wave? (c) Write the vector equation for \(\vec{B} (y, t)\).

The company where you work has obtained and stored five lasers in a supply room. You have been asked to determine the intensity of the electromagnetic radiation produced by each laser. The lasers are marked with specifications, but unfortunately different information is given for each laser: Laser A: power = 2.6 W; diameter of cylindrical beam = 2.6 mm Laser B: amplitude of electric field = 480 V/m Laser C: amplitude of magnetic field = 8.7 \(\times\) 10\(^{-6}\) T Laser D: diameter of cylindrical beam = 1.8 mm; force on totally reflecting surface = 6.0 \(\times\) 10\(^{-8}\) N Laser E: average energy density in beam = 3.0 \(\times\) 10-7 J/m\(^3\) Calculate the intensity for each laser, and rank the lasers in order of increasing intensity. Assume that the laser beams have uniform intensity distributions over their cross sections.

An electromagnetic wave with frequency 5.70 \(\times\) 10\(^{14}\) Hz propagates with a speed of 2.17 \(\times\) 10\(^8\) m/s in a certain piece of glass. Find (a) the wavelength of the wave in the glass; (b) the wavelength of a wave of the same frequency propagating in air; (c) the index of refraction \(n\) of the glass for an electromagnetic wave with this frequency; (d) the dielectric constant for glass at this frequency, assuming that the relative permeability is unity.

A sinusoidal electromagnetic wave having a magnetic field of amplitude 1.25 \(\mu\)T and a wavelength of 432 nm is traveling in the +\(x\)-direction through empty space. (a) What is the frequency of this wave? (b) What is the amplitude of the associated electric field? (c) Write the equations for the electric and magnetic fields as functions of \(x\) and t in the form of Eqs. (32.17).

An electromagnetic wave of wavelength 435 nm is traveling in vacuum in the -\(z\)-direction. The electric field has amplitude 2.70 \(\times\) 10\(^{-3}\) V/m and is parallel to the \(x\)-axis. What are (a) the frequency and (b) the magnetic-field amplitude? (c) Write the vector equations for \(\vec{E} (z, t)\) and \(\vec{B} (z, t)\).

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