/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 The power of a certain CD player... [FREE SOLUTION] | 91Ó°ÊÓ

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The power of a certain CD player operating at 120 V rms is 20.0 W. Assuming that the CD player behaves like a pure resistor, find (a) the maximum instantaneous power; (b) the rms current; (c) the resistance of this player

Short Answer

Expert verified
(a) 40.0 W; (b) 0.167 A; (c) 718.56 Ω.

Step by step solution

01

Understand the Relationship Between Voltage, Current, and Power

The power in an AC circuit with voltage (V_rms) and current (I_rms) can be calculated using the formula for resistive loads: \( P = V_{rms} \times I_{rms} \). The given power is 20.0 W and the voltage is 120 V rms.
02

Calculate the RMS Current

Use the formula from Step 1 to find \(I_{rms}\). Rearrange the formula to solve for \(I_{rms}\): \(I_{rms} = \frac{P}{V_{rms}}\). Substituting the values, we get \(I_{rms} = \frac{20.0 \, \text{W}}{120 \, \text{V}} = 0.167 \, \text{A}\).
03

Calculate the Resistance

From Ohm's Law, we know \(R = \frac{V_{rms}}{I_{rms}}\). Use the \(I_{rms}\) from Step 2: \(R = \frac{120 \, \text{V}}{0.167 \, \text{A}} = 718.56 \, \text{Ω}\).
04

Calculate Maximum Instantaneous Power

The maximum instantaneous power in an AC circuit is \(P_{max} = V_{peak} \times I_{peak}\). Note that \(V_{peak} = \sqrt{2} \times V_{rms}\) and \(I_{peak} = \sqrt{2} \times I_{rms}\). Calculate \(V_{peak} = 120 \, \text{V} \times \sqrt{2} = 169.71 \, \text{V}\) and \(I_{peak} = 0.167 \, \text{A} \times \sqrt{2} = 0.236 \, \text{A}\). Thus, \(P_{max} = 169.71 \, \text{V} \times 0.236 \, \text{A} = 40.0 \, \text{W}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ohm's Law
Ohm's Law is a fundamental principle in electrical engineering, describing the relationship between voltage, current, and resistance in an electrical circuit. It can be expressed simply as:
  • \( V = I \times R \)
where \( V \) is the voltage across the circuit, \( I \) is the current through the circuit, and \( R \) is the resistance within the circuit. This relationship implies that if you know any two of these values, you can easily find the third.

In the context of AC circuits, where voltage and current can vary over time, Ohm's Law still applies, but often the root mean square (rms) values are used. Rms values are equivalent to the average values you would find in direct current (DC) settings, allowing for simpler calculations without losing accuracy.

Let's see how this works in our given problem: with a known power of 20.0 W and a known voltage of 120 V (rms), you can use Ohm's Law to find the resistance once the current is determined.
  • The rms current \( I_{rms} \) is calculated first.
  • Then, using \( R = \frac{V_{rms}}{I_{rms}} \), we find the resistance \( R \).

    • Remember, understanding Ohm's Law can help you solve numerous problems in both AC and DC circuits, making it a cornerstone in your study of electricity.
AC Circuits
AC circuits, unlike DC circuits, involve current and voltage that vary with time. The term 'AC' stands for alternating current, which means that the direction of flow of electricity alternates periodically. This fluctuation is typically sinusoidal, characterized by its frequency (measured in hertz) and amplitude (voltage peak).

A key feature of AC circuits is the use of rms (root mean square) values. Rms values are vital because they describe the equivalent DC value of an AC quantity, providing a means of simplifying power calculations. The equations involving rms values are more straightforward than those using peak values.

An interesting consideration in AC circuits is the calculation of maximum instantaneous power. This is the peak power that can be reached at any point in time. Using the rms values, you can find the peak voltage and current by multiplying the rms values by the square root of two \( \sqrt{2} \), which stems from the properties of a sinusoidal waveform.
  • \( V_{peak} = V_{rms} \times \sqrt{2} \)
  • \( I_{peak} = I_{rms} \times \sqrt{2} \)
This gives a clear picture of how powerful AC waveforms are despite their fluctuating nature.
Electrical Resistance
Electrical resistance is a measure of how much a component within a circuit opposes the current flow. Represented by \( R \) and measured in ohms (\( \Omega \)), resistance determines how easily current can move through a circuit.

In practical terms, every material has a certain level of resistance, with conductors having low resistance and insulators having high resistance. Devices such as resistors take advantage of these properties to control current flow in circuits.

In the context of our exercise, we treated the CD player as a pure resistor. This simplification means that we consider its impedance to not have reactive components like inductance or capacitance, only resistance.
  • With the voltage \( V_{rms} \) and current \( I_{rms} \) known, the resistance of the CD player was calculated using Ohm’s Law: \( R = \frac{V_{rms}}{I_{rms}} \).
This approach allows easy calculation and understanding of a CD player's electrical behavior under the assumption of the resistive element being dominant.

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Most popular questions from this chapter

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