Chapter 30: Problem 33
A 7.50-nF capacitor is charged up to 12.0 V, then disconnected from the power supply and connected in series through a coil. The period of oscillation of the circuit is then measured to be 8.60 \(\times\) 10\(^{-5}\) s. Calculate: (a) the inductance of the coil; (b) the maximum charge on the capacitor; (c) the total energy of the circuit; (d) the maximum current in the circuit.
Short Answer
Step by step solution
Given Values
Find the Inductance (L)
Maximum Charge on the Capacitor (Q_max)
Total Energy of the Circuit (E)
Maximum Current in the Circuit (I_max)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Capacitance
The capacitance of a capacitor can be calculated using the formula:
- \( C = \frac{Q}{V} \)
- \( C \) is the capacitance in farads,
- \( Q \) is the charge in coulombs, and
- \( V \) is the voltage in volts.
Inductance
The unit of inductance is the henry (H), and it can be calculated using the formula derived from the LC circuit:
- \[ L = \frac{T^2}{4\pi^2C} \]
- \( L \) is the inductance,
- \( T \) is the period of oscillation, and
- \( C \) is the capacitance.
Resonance Frequency
The formula for the resonance frequency \( f_0 \) in an LC circuit is:
- \[ f_0 = \frac{1}{2\pi \sqrt{LC}} \]
- \( L \) is the inductance, and
- \( C \) is the capacitance.
Energy Storage in Capacitors
The energy \( E \) stored in a capacitor is given by the formula:
- \[ E = \frac{1}{2} C V^2 \]
- \( C \) is the capacitance, and
- \( V \) is the voltage across the capacitor.
Current in Inductors
The relationship between the maximum current \( I_{\text{max}} \) and the stored energy \( E \) in an inductor is:
- \[ I_{\text{max}} = \sqrt{\frac{2E}{L}} \]
- \( E \) is the total energy in the circuit, and
- \( L \) is the inductance.