/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 A sly 1.5-kg monkey and a jungle... [FREE SOLUTION] | 91Ó°ÊÓ

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A sly 1.5-kg monkey and a jungle veterinarian with a blow-gun loaded with a tranquilizer dart are 25 m above the ground in trees 70 m apart. Just as the veterinarian shoots horizontally at the monkey, the monkey drops from the tree in a vain attempt to escape being hit. What must the minimum muzzle velocity of the dart be for the dart to hit the monkey before the monkey reaches the ground?

Short Answer

Expert verified
The minimum muzzle velocity is approximately 31 m/s.

Step by step solution

01

Understand the Scenario

We have a monkey and a veterinarian both at 25 meters above the ground. The monkey drops from the tree at the same moment the veterinarian fires a dart horizontally at the monkey. The horizontal distance between them is 70 meters. We need to find the minimum muzzle velocity of the dart that will still hit the monkey before it hits the ground.
02

Analyze Vertical Motion

Both the monkey and the dart fall freely under gravity with the same vertical acceleration. The time it takes for the monkey to hit the ground can be calculated with the equation of motion: \[ h = \frac{1}{2} g t^2 \]where \( h = 25 \) meters and \( g = 9.8 \text{ m/s}^2 \). Solve for \( t \).
03

Calculate Time of Fall

Rearranging the previous equation, we have:\[ t^2 = \frac{2h}{g} = \frac{2 \times 25}{9.8} \approx 5.10 \]So,\[ t = \sqrt{5.10} \approx 2.26 \text{ s} \]This is the time both the dart and the monkey are in free fall before reaching the ground.
04

Determine Minimum Muzzle Velocity

The dart's horizontal motion must cover the 70-meter gap in the same time it takes to fall. Thus, the horizontal velocity \( v_x \) is given by:\[ v_x = \frac{d}{t} \]where \( d = 70 \) meters and \( t = 2.26 \) seconds:\[ v_x = \frac{70}{2.26} \approx 30.97 \text{ m/s} \].
05

Conclusion

The minimum muzzle velocity for the dart to hit the monkey before it reaches the ground is approximately \( 31 \text{ m/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Horizontal Velocity
Understanding horizontal velocity helps us solve problems like the monkey and dart scenario in projectile motion challenges. Here, the dart is fired horizontally towards the monkey immediately. This horizontal velocity, denoted as \( v_x \), is crucial for determining whether the dart can cover the horizontal gap of 70 meters in the same time it takes for the objects to fall. The movement is purely horizontal, meaning gravity doesn't directly influence \( v_x \).

To compute this, we use the formula:
  • \( v_x = \frac{d}{t} \)
Here, \( d \) is the horizontal distance to be traveled, which is 70 meters, and \( t \) is the time calculated based on vertical motion. The key takeaway is that horizontal velocity remains constant since there are no external horizontal forces acting within an ideal environment.
Vertical Motion
The concept of vertical motion in projectile exercises like this one involves understanding how objects fall under gravity's influence. Both the monkey and the dart experience free-fall motion vertically. Even if the dart is shot horizontally, it still begins to fall simultaneously with the monkey.

To find out how long both will fall before hitting the ground, we apply the basic equation of vertical motion:
  • \( h = \frac{1}{2} g t^2 \)
Where \( h \) is the height (25 meters), \( g \) is the acceleration due to gravity (approximately \( 9.8 \text{ m/s}^2 \)), and \( t \) is the time we want to determine. Solving this gives us insight into how long their vertical journey will take and is key for calculating the necessary horizontal velocity for the dart.
Free Fall
In physics, free fall describes what happens when the only force acting on an object is gravity. In our exercise, both the monkey and the dart experience free fall from the moment they're subjected to gravity's downward force. This means they'll have the same vertical acceleration \( g = 9.8 \text{ m/s}^2 \).

Free fall ensures that the vertical aspect of their motion is identical, simplifying our calculations. With free fall:
  • Each object, regardless of horizontal speed, falls at the same rate.
  • Time to hit the ground is the same for both objects.
Knowing this allows us to ignore any vertical motion differences when determining if the dart will hit the monkey, focusing solely on horizontal distance.
Equations of Motion
Equations of motion provide the mathematical tools to describe the movement of objects through time under certain conditions, such as uniform acceleration, seen in our projectile problem. These equations include both horizontal and vertical components of motion separately.

Vertical motion is governed by:
  • \( h = \frac{1}{2} g t^2 \)
Where we calculate the time of fall. For horizontal motion, we rely on:
  • \( v_x = \frac{d}{t} \)
In our exercise, by solving these equations, we determine the necessary horizontal velocity that ensures the dart reaches the monkey before both land. Understanding these equations is vital for breaking down each aspect of motion in similar physics scenarios.

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Most popular questions from this chapter

CALC The position of a squirrel running in a park is given by \(\vec{r}= [(0.280 m/s)t + (0.0360 m/s^2)t^2] \hat{\imath}+(0.0190 m/s^3)t^3\hat{\jmath}\). (a) What are \(v_x(t)\) and \(v_y(t)\), the \(x\)- and \(y\)-components of the velocity of the squirrel, as functions of time? (b) At \(t\) = 5.00 s, how far is the squirrel from its initial position? (c) At \(t\) = 5.00 s, what are the magnitude and direction of the squirrel's velocity?

The position of a dragonfly that is flying parallel to the ground is given as a function of time by \(\vec{r} = [2.90 m + (0.0900 m/s^2)t^2] \hat{\imath} - (0.0150 m/s^3)t^3\hat{\jmath}\). (a) At what value of \(t\) does the velocity vector of the dragonfly make an angle of 30.0\(^\circ\) clockwise from the \(+x\)-axis? (b) At the time calculated in part (a), what are the magnitude and direction of the dragonfly's acceleration vector?

In the middle of the night you are standing a horizontal distance of 14.0 m from the high fence that surrounds the estate of your rich uncle. The top of the fence is 5.00 m above the ground. You have taped an important message to a rock that you want to throw over the fence. The ground is level, and the width of the fence is small enough to be ignored. You throw the rock from a height of 1.60 m above the ground and at an angle of 56.0\(^\circ\) above the horizontal. (a) What minimum initial speed must the rock have as it leaves your hand to clear the top of the fence? (b) For the initial velocity calculated in part (a), what horizontal distance beyond the fence will the rock land on the ground?

Inside a starship at rest on the earth, a ball rolls off the top of a horizontal table and lands a distance \(D\) from the foot of the table. This starship now lands on the unexplored Planet \(X\). The commander, Captain Curious, rolls the same ball off the same table with the same initial speed as on earth and finds that it lands a distance 2.76\(D\) from the foot of the table. What is the acceleration due to gravity on Planet \(X\)?

An elevator is moving upward at a constant speed of 2.50 m/s. A bolt in the elevator ceiling 3.00 m above the elevator floor works loose and falls. (a) How long does it take for the bolt to fall to the elevator floor? What is the speed of the bolt just as it hits the elevator floor (b) according to an observer in the elevator? (c) According to an observer standing on one of the floor landings of the building? (d) According to the observer in part (c), what distance did the bolt travel between the ceiling and the floor of the elevator?

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