/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Airplanes and trains move throug... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Airplanes and trains move through the earth's magnetic field at rather high speeds, so it is reasonable to wonder whether this field can have a substantial effect on them. We shall use a typical value of 0.50 G for the earth's field. (a) The French TGV train and the Japanese "bullet train" reach speeds of up to 180 mph moving on tracks about 1.5 m apart. At top speed moving perpendicular to the earth's magnetic field, what potential difference is induced across the tracks as the wheels roll? Does this seem large enough to produce noticeable effects? (b) The Boeing 747-400 aircraft has a wingspan of 64.4 m and a cruising speed of 565 mph. If there is no wind blowing (so that this is also their speed relative to the ground), what is the maximum potential difference that could be induced between the opposite tips of the wings? Does this seem large enough to cause problems with the plane?

Short Answer

Expert verified
The induced potential difference is 6.03 mV for the train and 0.814 V for the plane, both too small to cause noticeable effects.

Step by step solution

01

Convert the Speeds to Meters per Second

To convert mph (miles per hour) to m/s (meters per second), use the conversion factor 1 mile = 1609.34 meters and 1 hour = 3600 seconds.For the train: 180 mph = \(180 \times \frac{1609.34}{3600} \approx 80.47\) m/s.For the plane: 565 mph = \(565 \times \frac{1609.34}{3600} \approx 252.67\) m/s.
02

Calculate the Induced EMF for the Train

Use the formula for the electromotive force (EMF) induced in a conductor moving perpendicular to a magnetic field: \( E = B \cdot v \cdot L \), where:- \( B = 0.50 \) G = \(0.50 \times 10^{-4}\) T (since 1 G = 10^{-4} T is the conversion factor)- \( v = 80.47 \) m/s (train speed)- \( L = 1.5 \) m (distance between the tracks)Thus, \( E = 0.50 \times 10^{-4} \times 80.47 \times 1.5 \approx 6.03 \times 10^{-3} \) V or 6.03 mV.
03

Calculate the Induced EMF for the Plane

For the plane, using the same formula for EMF: \( E = B \cdot v \cdot L \), we have:- \( B = 0.50 \times 10^{-4} \) T- \( v = 252.67 \) m/s (plane speed)- \( L = 64.4 \) m (wingspan)Thus, \( E = 0.50 \times 10^{-4} \times 252.67 \times 64.4 \approx 0.814 \) V.
04

Assess the Potential Differences

For the train, the induced potential difference is 6.03 mV, which is very small and unlikely to have any noticeable effects on the train or its systems. For the plane, the induced potential difference is approximately 0.814 V, which is still relatively small compared to operating voltages in aircraft systems and is unlikely to cause any problems.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Earth's Magnetic Field
The Earth's magnetic field is an omnipresent force that we might not regularly notice, but it significantly affects our environment. It is a geomagnetic field that extends from the Earth's interior out into space, where it interacts with solar winds. For vehicles like planes and trains, the magnetic field can induce small electrical currents as they move.

This field is measured in units called gauss (G), and on average, it presents a value of approximately *0.50 G*. To put this into perspective, one gauss is equivalent to *10,000 teslas (T)*, the standard unit for magnetic fields used in physics. Therefore, the Earth's magnetic field at the surface is about *5 × 10^{-5} T*.

While vehicles move at high speeds through this field, it can create interesting effects like induced electomotive forces. Understanding how this field interacts with conductors (like the metal bodies of trains or planes) helps in analyzing potential effects, although in practice, these differences are often quite minimal.
Electromotive Force (EMF)
Electromotive force (EMF) is a fundamental concept in electromagnetism. It refers to the potential difference generated in a conductor when it moves through a magnetic field. When a conductor like a train or plane moves perpendicular to the Earth's magnetic field, a voltage is induced across it, which is calculated using the simple formula:

\[ E = B \cdot v \cdot L \] where *E* is the induced EMF, *B* is the magnetic field strength (in teslas), *v* is the speed of the conductor (in meters per second), and *L* is the length of the conductor (in meters) moving through the field.

For example, the French TGV train, moving at about 80.47 m/s with a track gauge of 1.5 m, experiences a small EMF of roughly 6.03 millivolts. This happens due to the relatively weak Earth's magnetic field and the short distance between the tracks.

Similarly, high-speed planes like the Boeing 747, with a much longer wingspan of 64.4 m, experience a larger EMF—approximately 0.814 volts—due to their higher speed and longer conductive pathway through the magnetic field. Nonetheless, this induced EMF is minor enough not to interfere with electronic systems onboard.
Potential Difference
Potential difference, often known as voltage, is the measure of electric potential energy per unit charge between two points. It provides the "push" needed for electrical current to flow through a circuit. When dealing with high-speed vehicles and the Earth's magnetic field, the term "induced potential difference" becomes relevant.

As in the context of a train moving across train tracks, or the wings of an aircraft in motion, the potential difference can be induced by the magnetic field as the conductor (or parts of the vehicle) moves through it. However, whether this induced potential results in significant effects depends on the magnitude of the potential difference generated.

For example, a potential difference of 6.03 mV induced across a train's tracks is negligible compared to operating voltages used in railway systems, which usually range from 20V to several hundreds of volts.

Similarly, for aircraft like the Boeing 747, an induced potential difference of 0.814 V is quite small relative to voltages encountered during standard operating conditions of aircraft systems. This means that the induced potential difference is unlikely to affect normal technological operations or safety of such vehicles.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In many magnetic resonance imaging (MRI) systems, the magnetic field is produced by a superconducting magnet that must be kept cooled below the superconducting transition temperature. If the cryogenic cooling system fails, the magnet coils may lose their superconductivity and the strength of the magnetic field will rapidly decrease, or \(quench\). The dissipation of energy as heat in the now-nonsuperconducting magnet coils can cause a rapid boil-off of the cryogenic liquid (usually liquid helium) that is used for cooling. Consider a superconducting MRI magnet for which the magnetic field decreases from 8.0 T to nearly 0 in 20 s. What is the average emf induced in a circular wedding ring of diameter 2.2 cm if the ring is at the center of the MRI magnet coils and the original magnetic field is perpendicular to the plane that is encircled by the ring?

A circular conducting ring with radius \(r_0 =\) 0.0420 m lies in the xy-plane in a region of uniform magnetic field \(\overrightarrow{B} = B_0 [1 - 3(t/t_0)^2 + 2(t/t_0)^3]\hat{k}\). In this expression, \(t_0 =\) 0.0100 s and is constant, \(t\) is time, \(\hat{k}\) is the unit vector in the +\(z\)-direction, and \(B_0\) = 0.0800 T and is constant. At points \(a\) and \(b\) (Fig. P29.58) there is a small gap in the ring with wires leading to an external circuit of resistance \(R =\) 12.0 \(\Omega\). There is no magnetic field at the location of the external circuit. (a) Derive an expression, as a function of time, for the total magnetic flux \(\Phi_B\) through the ring. (b) Determine the emf induced in the ring at time \(t =\) 5.00 \(\times\) 10\(^{-3}\) s. What is the polarity of the emf? (c) Because of the internal resistance of the ring, the current through \(R\) at the time given in part (b) is only 3.00 mA. Determine the internal resistance of the ring. (d) Determine the emf in the ring at a time \(t =\) 1.21 \(\times\) 10\(^{-2}\) s. What is the polarity of the emf? (e) Determine the time at which the current through \(R\) reverses its direction.

A closely wound search coil (see Exercise 29.3) has an area of 3.20 cm\(^2\), 120 turns, and a resistance of 60.0 \(\Omega\). It is connected to a charge- measuring instrument whose resistance is 45.0 \(\Omega\). When the coil is rotated quickly from a position parallel to a uniform magnetic field to a position perpendicular to the field, the instrument indicates a charge of 3.56 \(\times\) 10\(^{-5}\) C. What is the magnitude of the field?

The armature of a small generator consists of a flat, square coil with 120 turns and sides with a length of 1.60 cm. The coil rotates in a magnetic field of 0.0750 T. What is the angular speed of the coil if the maximum emf produced is 24.0 mV?

A very long, straight solenoid with a crosssectional area of 2.00 cm\(^2\) is wound with 90.0 turns of wire per centimeter. Starting at t = 0, the current in the solenoid is increasing according to \(i(t) = (0.160 A/s^2)t^2\). A secondary winding of 5 turns encircles the solenoid at its center, such that the secondary winding has the same cross-sectional area as the solenoid. What is the magnitude of the emf induced in the secondary winding at the instant that the current in the solenoid is 3.20 A?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.