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A solenoid that is 35 cm long and contains 450 circular coils 2.0 cm in diameter carries a 1.75-A current. (a) What is the magnetic field at the center of the solenoid, 1.0 cm from the coils? (b) Suppose we now stretch out the coils to make a very long wire carrying the same current as before. What is the magnetic field 1.0 cm from the wire's center? Is it the same as that in part (a)? Why or why not?

Short Answer

Expert verified
(a) 0.00283 T; (b) 0.000035 T. The fields are different because a solenoid confines the field while a wire does not.

Step by step solution

01

Understanding the Problem

We are given a solenoid with certain dimensions and properties, and we need to calculate the magnetic field at specific points. First, we calculate the magnetic field at the center of the solenoid. Second, we analyze the field when the solenoid is stretched into a straight wire.
02

Formula for Magnetic Field of a Solenoid

The magnetic field inside a solenoid is given by the formula \( B = \mu_0 n I \), where \( B \) is the magnetic field, \( \mu_0 \) is the permeability of free space (\(4\pi \times 10^{-7}\) Tm/A), \( n \) is the number of turns per unit length, and \( I \) is the current through the solenoid.
03

Calculate Number of Turns per Unit Length

The solenoid has 450 turns over a length of 35 cm. Convert the length into meters (0.35 m). Then, the number of turns per unit length \( n = \frac{450}{0.35} \approx 1285.71 \text{ turns/m} \).
04

Calculate Magnetic Field Inside the Solenoid

Using the formula \( B = \mu_0 n I \), substitute \( \mu_0 = 4\pi \times 10^{-7} \), \( n = 1285.71 \text{ turns/m} \), and \( I = 1.75 \text{ A} \). This gives \( B \approx (4\pi \times 10^{-7}) \times 1285.71 \times 1.75 \approx 0.00283 \text{ T} \).
05

Understanding Magnetic Field Near a Long Wire

The magnetic field near a long straight wire is given by \( B = \frac{\mu_0 I}{2\pi r} \), where \( r \) is the distance from the wire. We need to use this formula to calculate the field 1.0 cm away from the wire.
06

Calculate Magnetic Field Near the Wire

Substitute \( \mu_0 = 4\pi \times 10^{-7} \), \( I = 1.75 \text{ A} \), and \( r = 0.01 \text{ m} \) (1.0 cm) into \( B = \frac{\mu_0 I}{2\pi r} \). This results in \( B \approx \frac{(4\pi \times 10^{-7}) \times 1.75}{2\pi \times 0.01} \approx 0.000035 \text{ T} \).
07

Compare Magnetic Fields in Parts (a) and (b)

The magnetic field at the center of the solenoid \(0.00283 \text{ T}\) is much larger than the field near the straight wire \(0.000035 \text{ T}\). This is due to the difference in the configurations; solenoids concentrate magnetic field lines, while a straight wire disperses them.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solenoid
A solenoid is a coil of wire that is tightly wound in a helix. This arrangement is commonly used to generate a magnetic field when an electric current is passed through it. A basic characteristic of a solenoid is that its magnetic field is uniform and strong inside the coil compared to the field outside. The magnetic field in a solenoid can be calculated using the formula:
  • \( B = \mu_0 n I \)
Where:
  • \( B \) is the magnetic field,
  • \( \mu_0 \) is the permeability of free space, which is a constant value \(4\pi \times 10^{-7}\) Tm/A,
  • \( n \) is the number of turns per unit length of the solenoid,
  • \( I \) is the current passing through the wire.
The closer the coils, the stronger the magnetic field, as the term \( n \) represents the density of turns all along the solenoid's length.
Magnetic Field of a Wire
The magnetic field produced by a long, straight wire carrying a current is different than that of a solenoid. Instead of being concentrated, it extends in circular loops around the wire. The strength and direction of the field are given by the right-hand rule and the formula:
  • \( B = \frac{\mu_0 I}{2\pi r} \)
Where:
  • \( B \) is the magnetic field,
  • \( \mu_0 \) is the permeability of free space,
  • \( I \) is the current carried by the wire,
  • \( r \) is the radial distance from the wire.
This shows that the magnetic field decreases rapidly as you move away from the wire. Unlike solenoids, which concentrate the magnetic field internally, a single wire disperses its field more widely. This difference in field distribution is important when considering the design of electromagnets and other magnetic devices.
Electromagnetism
Electromagnetism is the branch of physics that studies the interaction between electric currents and magnetic fields. Within the realm of electromagnetism, solenoids and wires are crucial components due to their ability to generate magnetic fields. When a current travels through a wire or solenoid, a magnetic field is created, demonstrating the close link between electricity and magnetism. The fundamental principle here is captured by Ampère's Circuital Law, which relates the circulating magnetic field in a closed loop to the electric current passing through the loop. Thus, both solenoids and straight wires illustrate fundamental electromagnetism concepts. These components allow us to control and utilize magnetic fields by adjusting electrical currents, making applications like motors, transformers, and inductors possible.
Current and Magnetism
The close relationship between electric currents and magnetic fields is a cornerstone of physics. When an electric current passes through a wire, it generates a magnetic field perpendicular to the flow of current. This behavior is fundamental in creating electromagnets, which use coils of wire (like solenoids) to produce concentrated magnetic fields when energized with current. In solenoids, the magnetic field inside the coil is significantly stronger than outside because the multiple loops of wire help concentrate the magnetic field lines within. This used in various applications like electrical circuits, actuators, and magnetic resonance imaging machines. In contrast, a single wire will have magnetic fields that are dispersed concentrically around the wire, showing the versatile ways in which electricity can be used to manipulate magnetic effects for varied technological uses.

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Most popular questions from this chapter

A closed curve encircles several conductors. The line integral \(\oint\overrightarrow{B}\) \(\cdot\) \(\overrightarrow{dl}\) around this curve is 3.83 \(\times\) 10\(^{-4}\) T \(\cdot\) m. (a) What is the net current in the conductors? (b) If you were to integrate around the curve in the opposite direction, what would be the value of the line integral? Explain.

A single circular current loop 10.0 cm in diameter carries a 2.00-A current. (a) What is the magnetic field at the center of this loop? (b) Suppose that we now connect 1000 of these loops in series within a 500 cm length to make a solenoid 500 cm long. What is the magnetic field at the center of this solenoid? Is it 1000 times the field at the center of the loop in part (a)? Why or why not?

A toroidal solenoid has an inner radius of 12.0 cm and an outer radius of 15.0 cm. It carries a current of 1.50 A. How many equally spaced turns must it have so that it will produce a magnetic field of 3.75 mT at points within the coils 14.0 cm from its center?

A wide, long, insulating belt has a uniform positive charge per unit area \(\sigma\) on its upper surface. Rollers at each end move the belt to the right at a constant speed \(v\). Calculate the magnitude and direction of the magnetic field produced by the moving belt at a point just above its surface. (\(Hint:\) At points near the surface and far from its edges or ends, the moving belt can be considered to be an infinite current sheet like that in Problem 28.73.)

The solenoid is removed from the enclosure and then used in a location where the earth's magnetic field is 50 \(\mu\)T and points horizontally. A sample of bacteria is placed in the center of the solenoid, and the same current is applied that produced a magnetic field of 150 \(\mu\)T in the lab. Describe the field experienced by the bacteria: The field (a) is still 150 \(\mu\)T; (b) is now 200 \(\mu\)T; (c) is between 100 and 200 \(\mu\)T, depending on how the solenoid is oriented; (d) is between 50 and 150 \(\mu\)T, depending on how the solenoid is oriented.

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