Chapter 23: Problem 48
A positive point charge \(q_1 = +5.00 \times 10^{-4}\) C is held at a fixed position. A small object with mass 4.00 \(\times 10^{-3}\) kg and charge \(q_2 = -3.00 \times 10^{-4}\) C is projected directly at \(q_1\) . Ignore gravity. When \(q_2\) is 0.400 m away, its speed is 800 m\(/\)s. What is its speed when it is 0.200 m from \(q_1\) ?
Short Answer
Step by step solution
Understanding Given Information
Applying Conservation of Energy
Substitute Known Values
Solve for Unknown Speed
Conclusion About the Speed
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coulomb's Law
- \( F \) is the magnitude of the force between the charges.
- \( k \) is Coulomb's constant, approximately \( 8.99 \times 10^9 \) N m²/C².
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges, in Coulombs.
- \( r \) is the distance between the charges, in meters.
Electric Potential Energy
- \( U \) is the electric potential energy in joules (J).
- \( k \) is Coulomb's constant, \( 8.99 \times 10^9 \) N m²/C².
- \( q_1 \) and \( q_2 \) are the charges.
- \( r \) is the distance between the charges.
Kinetic Energy Calculation
- \( KE \) is the kinetic energy in joules (J).
- \( m \) is the mass of the object in kilograms (kg).
- \( v \) is the velocity of the object in meters per second (m/s).