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A total electric charge of 3.50 nC is distributed uniformly over the surface of a metal sphere with a radius of 24.0 cm. If the potential is zero at a point at infinity, find the value of the potential at the following distances from the center of the sphere: (a) 48.0 cm; (b) 24.0 cm; (c) 12.0 cm.

Short Answer

Expert verified
(a) 65.54 V; (b) 131.88 V; (c) 131.88 V.

Step by step solution

01

Formula for Electric Potential

To find the electric potential due to a charged sphere, we use the formula for electric potential at a distance \( r \) from the center of a charged sphere: \[ V = \frac{kQ}{r} \] where \( k = 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \) is the Coulomb's constant, \( Q = 3.50 \times 10^{-9} \, \text{C} \) is the charge, and \( r \) is the distance from the center of the sphere.
02

Electric Potential at 48.0 cm

For point (a) at a distance 48.0 cm (or 0.48 m):\[ V = \frac{8.99 \times 10^9 \times 3.50 \times 10^{-9}}{0.48} \] Calculating this gives us \( V \approx 65.54 \, \text{V} \).
03

Electric Potential on the Surface (24.0 cm)

For point (b) which is on the surface at a distance 24.0 cm (or 0.24 m):\[ V = \frac{8.99 \times 10^9 \times 3.50 \times 10^{-9}}{0.24} \] Calculating this gives us \( V \approx 131.88 \, \text{V} \).
04

Electric Potential Inside the Sphere (12.0 cm)

For point (c) inside the sphere at 12.0 cm (0.12 m). Since we are inside a conducting sphere, the potential remains constant and equal to the surface potential. So, \( V = 131.88 \, \text{V} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's constant
Coulomb's constant is a pivotal part of calculating the electric potential around charged objects. This constant, often denoted by \( k \), has a fixed value \( k = 8.99 \times 10^9 \text{ N m}^2/\text{C}^2 \). It helps to determine the force or potential generated by charges in a medium like air or vacuum.
Using this constant, you can effectively compute the interaction between point charges. This is done by incorporating it into formulas that relate distances and charges, like those used to find electric potential:
  • This constant simplifies calculations between electrostatic forces of point charges.
  • Ensures accuracy in the SI system of units.
  • Allows for comparisons across different equations involving electrostatics.
When dealing with spherical charge distributions, Coulomb's constant comes into play as it ties the charge and distance into the electric potential formula. Understanding this constant is crucial for solving problems where electric charge effects need quantification.
Charged Sphere
A charged sphere, especially a conducting one, influences the electric potential around and within it. In the context of electrostatics, a uniformly charged sphere has all its charge distributed over the surface. This is due to the nature of conductive materials where excess charges migrate to the outer surface.
When calculating the electric potential at a distance from the center of a charged sphere, it treats the entire charge as if it were concentrated at the center, thanks to the spherical symmetry.
This is key for two main scenarios:
  • Outside the Sphere: Electric potential, \( V \), decreases with increasing distance \( r \) and follows \( V = \frac{kQ}{r} \) where the point of interest is outside or on the surface.
  • Inside the Sphere: The potential remains constant and equals the potential at the surface since all charges reside on the surface.
Understanding how a charged sphere behaves aids in predicting voltages or potentials at various points relative to the sphere.
Electric Charge Distribution
Electric charge distribution can significantly affect electric potential and field generated by a structure such as a sphere. We often deal with uniform electric charge distributions, particularly for metal or conducting spheres, which means the charge is spread evenly over the sphere's surface.
In practice, steps involve understanding how this distribution affects calculations:
  • A uniform charge distribution allows simplification in calculations and predictions of electric potential and field lines.
  • Inside a conductor, charges rearrange themselves until equilibrium is reached, causing no electric field in the conductor's interior.
  • This phenomenon means the potential inside a conductor matches that of the surface.
For a charged sphere, this understanding is vital, especially when solving problems with internal and external points. It ensures you accurately predict potential values at given distances, hence resolving various electrostatic scenarios efficiently.

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Most popular questions from this chapter

A uniformly charged, thin ring has radius 15.0 cm and total charge \(+\)24.0 nC. An electron is placed on the ring's axis a distance 30.0 cm from the center of the ring and is constrained to stay on the axis of the ring. The electron is then released from rest. (a) Describe the subsequent motion of the electron. (b) Find the speed of the electron when it reaches the center of the ring.

A positive charge \(q\) is fixed at the point \(x = 0, y = 0\), and a negative charge \(-2_q\) is fixed at the point \(x = a, y = 0\). (a) Show the positions of the charges in a diagram. (b) Derive an expression for the potential \(V\) at points on the \(x\)-axis as a function of the coordinate \(x\). Take \(V\) to be zero at an infinite distance from the charges. (c) At which positions on the \(x\)-axis is \(V = 0\)? (d) Graph \(V\) at points on the \(x\)-axis as a function of \(x\) in the range from \(x = -2a\) to \(x = +2a\). (e) What does the answer to part (b) become when \(x \gg a\)? Explain why this result is obtained.

Identical charges \(q = +\)5.00 \(\mu\)C are placed at opposite corners of a square that has sides of length 8.00 cm. Point \(A\) is at one of the empty corners, and point \(B\) is at the center of the square. A charge \(q_0 = -\)3.00 \(\mu\)C is placed at point \(A\) and moves along the diagonal of the square to point \(B\). (a) What is the magnitude of the net electric force on \(q_0\) when it is at point \(A\)? Sketch the placement of the charges and the direction of the net force. (b) What is the magnitude of the net electric force on \(q_0\) when it is at point \(B\)? (c) How much work does the electric force do on \(q_0\) during its motion from \(A\) to \(B\)? Is this work positive or negative? When it goes from \(A\) to \(B\), does \(q_0\) move to higher potential or to lower potential?

A solid conducting sphere has net positive charge and radius \(R =\) 0.400 m. At a point 1.20 m from the center of the sphere, the electric potential due to the charge on the sphere is 24.0 V. Assume that \(V = 0\) at an infinite distance from the sphere. What is the electric potential at the center of the sphere?

An alpha particle with kinetic energy 9.50 MeV (when far away) collides head- on with a lead nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the lead nucleus remains stationary and may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.)

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