/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 Suppose that to repel electrons ... [FREE SOLUTION] | 91Ó°ÊÓ

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Suppose that to repel electrons in the radiation from a solar flare, each sphere must produce an electric field \(\overrightarrow{E}\) of magnitude 1 \(\times\) 10\(^6\) N/C at 25 m from the center of the sphere. What net charge on each sphere is needed? (a) -0.07 C; (b) -8 mC; (c) -80 \(\mu\)C; (d) -1 \(\times\) 10\(^{-20}\) C.

Short Answer

Expert verified
The net charge on each sphere needs to be -0.07 C.

Step by step solution

01

Understand the Problem

We are tasked with finding the net charge on a sphere that produces an electric field of a specific magnitude at a certain distance. The electric field magnitude (\(\overrightarrow{E}\)) required is 1 \(\times\) 10\(^6\) N/C at a distance of 25 m from the center of the sphere.
02

Recall the Formula for Electric Field Due to a Point Charge

The formula for the electric field \(E\) due to a point charge \(q\) at a distance \(r\) from the charge is given by:\[ E = \frac{k \cdot |q|}{r^2} \]where \(k\) is Coulomb's constant, approximately 8.99 \(\times\) 10\(^9\) N·m²/C².
03

Substitute Given Values

Substitute the known values into the electric field formula. Given, \(E = 1 \times 10^6\) N/C and \(r = 25\) m:\[ 1 \times 10^6 = \frac{8.99 \times 10^9 \cdot |q|}{(25)^2} \]
04

Solve for the Charge \(q\)

Rearrange the equation to solve for \(|q|\):\[ |q| = \frac{1 \times 10^6 \times (25)^2}{8.99 \times 10^9} \]Calculate \(q\):\[ |q| = \frac{1 \times 10^6 \times 625}{8.99 \times 10^9} \approx 6.95 \times 10^{-2} \text{ C} \]
05

Determine the Correct Answer

The calculated magnitude of charge \(|q|\) is approximately 0.07 C. Since we need to repel electrons, the charge should be negative.Thus, the closest option is (a) -0.07 C.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is a fundamental principle in physics that describes the force between two charged objects. This law tells us that like charges repel each other, while opposite charges attract. The force's magnitude between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula for Coulomb's Law is:\[ F = \frac{k \cdot |q_1| \cdot |q_2|}{r^2} \]where \( F \) is the force between the charges, \( q_1 \) and \( q_2 \) are the amounts of charge, \( r \) is the distance between the centers of the two charges, and \( k \) is Coulomb's constant, approximately \( 8.99 \times 10^9 \) N·m²/C². Coulomb's Law helps us understand the nature of electrical interactions in various phenomena, such as the behavior of electrons in atoms or charges on surfaces.Understanding Coulomb's Law is essential for calculations involving electric fields, as it lays the foundation for understanding how charges influence one another.
Point Charge
A point charge refers to an idealized charge that is considered to be concentrated at a single point in space. This simplification is very helpful for theoretical calculations, as it allows for the application of mathematical formulas to determine electric forces and fields more easily. In practice, no charge is truly a point, but they can be approximated as point charges when the size of the charged body is much smaller than the distances involved in the problem. Point charges are often used in problems involving electric fields and forces because they allow for straightforward application of formulas like those from Coulomb's Law and for calculating the electric field at a certain distance from the charge. By treating charges as if they were points, one can easily solve problems involving the interaction of multiple charges or the calculation of electric fields at a distance.
Electric Field Calculations
Electric field calculations are essential for understanding how charged objects influence their surroundings. An electric field indicates the force a charge would experience at a point in space. The direction of the field is the direction that a positive test charge would move.To calculate the electric field \( E \) created by a point charge \( q \) at a distance \( r \), you use the formula:\[ E = \frac{k \cdot |q|}{r^2} \]where \( k \) is Coulomb's constant. This formula highlights that the electric field is stronger when nearer to the charge and weaker further away. Note that the force experienced by another charge in this field can be computed by multiplying the electric field by the charge.By calculating electric fields around charges, you can predict how other charges will behave when placed within these fields. It's a critical concept in both theoretical and practical applications, including electrical engineering and physics.
Distance in Electric Fields
The distance in electric fields is a crucial factor when considering how electric fields behave and how strong they are. Since electric fields emanate from charges and diminish in strength with distance, the relationship between distance and field strength is quite significant.According to the formula for electric field:\[ E = \frac{k \cdot |q|}{r^2} \]it is clear that as the distance \( r \) increases, the electric field \( E \) decreases by the square of the distance. This means if you double the distance from the charge, the electric field becomes four times weaker.Understanding this inverse square relationship is essential for predicting how electric fields will behave over different distances and is a key factor in designing systems that rely on electric fields, such as capacitors, electric circuits, and various electronic components.

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Most popular questions from this chapter

A nonuniform, but spherically symmetric, distribution of charge has a charge density \(\rho(r)\) given as follows: $$\rho(r) = \rho_0 \bigg(1 - \frac{4r}{3R}\bigg) \space \space \space \mathrm{for} \space r \leq R$$ $$\rho(r) = 0 \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \mathrm{for} \space r \leq R$$ where \(\rho_0\) is a positive constant. (a) Find the total charge contained in the charge distribution. Obtain an expression for the electric field in the region (b) \(r \geq R; (c) r \leq R\). (d) Graph the electricfield magnitude \(E\) as a function of \(r\). (e) Find the value of \(r\) at which the electric field is maximum, and find the value of that maximum field.

A long line carrying a uniform linear charge density +50.0 \(\mu\)C/m runs parallel to and 10.0 cm from the surface of a large, flat plastic sheet that has a uniform surface charge density of -100 \(\mu\)C/m2 on one side. Find the location of all points where an \(a\) particle would feel no force due to this arrangement of charged objects.

A solid conducting sphere carrying charge \(q\) has radius \(a\). It is inside a concentric hollow conducting sphere with inner radius \(b\) and outer radius \(c\). The hollow sphere has no net charge. (a) Derive expressions for the electricfield magnitude in terms of the distance \(r\) from the center for the regions \(r < a, a < r < b, b < r < c\), and \(r > c\). (b) Graph the magnitude of the electric field as a function of \(r\) from \(r =\) 0 to \(r =\) 2c. (c) What is the charge on the inner surface of the hollow sphere? (d) On the outer surface? (e) Represent the charge of the small sphere by four plus signs. Sketch the field lines of the system within a spherical volume of radius 2\(c\).

The nuclei of large atoms, such as uranium, with 92 protons, can be modeled as spherically symmetric spheres of charge. The radius of the uranium nucleus is approximately 7.4 \(\times\) 10\(^{-15}\) m. (a) What is the electric field this nucleus produces just outside its surface? (b) What magnitude of electric field does it produce at the distance of the electrons, which is about 1.0 \(\times\) 10\(^{-10}\) m? (c) The electrons can be modeled as forming a uniform shell of negative charge. What net electric field do they produce at the location of the nucleus?

In a region of space there is an electric field \(\overrightarrow{E}\) that is in the z-direction and that has magnitude \(E =\) [964 N/(C \(\cdot\) m)]\(x\). Find the flux for this field through a square in the \(xy\)-plane at \(z =\) 0 and with side length 0.350 m. One side of the square is along the \(+x\)-axis and another side is along the \(+y\)-axis.

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