Chapter 22: Problem 21
The electric field at a distance of 0.145 m from the surface of a solid insulating sphere with radius 0.355 m is 1750 N/C. (a) Assuming the sphere's charge is uniformly distributed, what is the charge density inside it? (b) Calculate the electric field inside the sphere at a distance of 0.200 m from the center.
Short Answer
Step by step solution
Understand the Problem
Apply Gauss's Law for External Electric Field
Solve for Total Charge Q
Calculate Total Charge Q
Find Volume of the Sphere
Compute the Charge Density \( \rho \)
Calculate Electric Field Inside the Sphere
Substitute Values to Find Internal Field
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electric Field Calculations
To find the electric field at a point outside the sphere, we use Gauss's Law. This law relates the electric field to the total charge enclosed by a closed surface. For a point outside a sphere, it is as if all the charge is concentrated at the center. The formula used here is:
- \( E = \frac{kQ}{r^2} \)
- \( k \) is Coulomb's constant \( (8.99 \times 10^9 \, \text{N m}^2/\text{C}^2) \)
- \( Q \) is the total charge
- \( r \) is the distance from the center of the sphere
- \( E = \frac{kQr}{R^3} \)
- \( R \) is the sphere's radius
Charge Density
The formula for charge density is:
- \( \rho = \frac{Q}{V} \)
- \( V = \frac{4}{3} \pi r^3 \)
Solid Insulating Sphere
When applying Gauss's Law, the insulating nature ensures a better-defined internal electric field, simplifying calculations both outside and inside the sphere.
Uniform Charge Distribution
- The external electric field is calculated as if all charge resides at the center.
- The internal field changes linearly with distance from the center.