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Point charges \(q_1 = -\)4.5 nC and \(q_2 = +\)4.5 nC are separated by 3.1 mm, forming an electric dipole. (a) Find the electric dipole moment (magnitude and direction). (b) The charges are in a uniform electric field whose direction makes an angle of 36.9\(^\circ\) with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude \(7.2 \times 10^{-9}\) N \(\cdot\) m ?

Short Answer

Expert verified
The dipole moment is \(1.395 \times 10^{-11}\) C·m, directed from \(q_1\) to \(q_2\). The electric field magnitude is \(8.6 \times 10^{2}\) N/C.

Step by step solution

01

Understanding the Electric Dipole Moment Formula

The electric dipole moment \( \mathbf{p} \) can be calculated using the formula \( \mathbf{p} = q \cdot \mathbf{d} \), where \( q \) is the magnitude of either charge and \( \mathbf{d} \) is the displacement vector pointing from the negative charge to the positive charge. In this case, \( q = 4.5 \times 10^{-9} \) C and \( d = 3.1 \times 10^{-3} \) m.
02

Calculating the Magnitude of the Dipole Moment

To find the magnitude of the electric dipole moment \( p \), we use the formula \( p = q \cdot d \), which gives:\[p = 4.5 \times 10^{-9} \text{ C} \times 3.1 \times 10^{-3} \text{ m} = 1.395 \times 10^{-11} \text{ C} \cdot \text{m}.\]
03

Determining the Direction of the Dipole Moment

The direction of the electric dipole moment is from the negative charge \( q_1 \) to the positive charge \( q_2 \). Thus, in this context, it points along the line connecting the two charges.
04

Understanding the Torque on a Dipole in an Electric Field

The torque \( \tau \) experienced by a dipole in an electric field \( \mathbf{E} \) is given by the formula \( \tau = pE\sin\theta \), where \( \theta \) is the angle between the dipole moment and the electric field.
05

Solving for the Electric Field Magnitude

Given the torque \( \tau = 7.2 \times 10^{-9} \) N·m and the angle \( \theta = 36.9^\circ \), we solve for \( E \) using the torque formula:\[E = \frac{\tau}{p\sin\theta} = \frac{7.2 \times 10^{-9}}{1.395 \times 10^{-11} \cdot \sin 36.9^\circ}.\]Substitute \( \sin 36.9^\circ \approx 0.6 \):\[E = \frac{7.2 \times 10^{-9}}{1.395 \times 10^{-11} \cdot 0.6} \approx 8.6 \times 10^{2} \text{ N/C}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Dipole Moment
The electric dipole moment is a significant physical quantity in the study of electric fields. It is a vector quantity and is defined as the product of the charge magnitude and the separation distance between two charges. Here, the dipole moment is represented by the symbol \( \mathbf{p} \).
To calculate the dipole moment, the formula \( \mathbf{p} = q \cdot d \) is used, where \( q \) refers to the magnitude of one of the charges (since they are equal in magnitude), and \( d \) is the distance between them. In this scenario, both charges are numerically equal at \( 4.5 \times 10^{-9} \) C, separated by 3.1 mm or \( 3.1 \times 10^{-3} \) m. The resulting dipole moment is calculated to be \( 1.395 \times 10^{-11} \) C·m.
The direction of the dipole moment is crucial; it is defined to be from the negative to the positive charge, following a convention that makes it useful in vector calculations.
Torque on a Dipole
Torque, in the context of electric dipoles, can be thought of as the rotational effect exerted by an electric field on the dipole. It causes the dipole to experience a twisting force, aligning it with the direction of the field. Torque is given by the expression \( \tau = pE\sin\theta \). Here, \( \tau \) is the torque, \( p \) is the dipole moment, \( E \) is the electric field strength, and \( \theta \) is the angle between the electric field and the dipole moment vector.
The practical implication of this is that the dipole will reach a stable orientation when it aligns itself such that this torque is minimized or nullified. The maximum torque occurs when the angle is at 90 degrees (since \( \sin 90^\circ = 1 \)). In this specific exercise, the torque is provided as \( 7.2 \times 10^{-9} \) N·m. This torque tells us about the interaction strength between the dipole and the field.
Uniform Electric Field
A uniform electric field is characterized by having a constant magnitude and direction throughout a given space. This simplicity allows for straightforward calculations and predictions about the behavior of charges in the field.
For an electric dipole in such a field, the torque experienced depends directly on both the dipole moment and the field strength. This uniformity means the same electric influence is applied along the entire path of the dipole, ensuring calculable and consistent results.
When an electric dipole is placed in this field, it undergoes a torque that tries to align the dipole with the field direction, highlighting how external electric fields can influence charged systems through torque.
Angle of Dipole with Electric Field
The angle between the dipole moment and the electric field is a crucial parameter when considering the torque. This angle, denoted as \( \theta \), determines how effectively the electric field exerts torque on the dipole.
The formula for torque incorporates this angle through the sine function: \( \tau = pE\sin\theta \). This implies that the torque is at its maximum when the angle is 90 degrees, and becomes zero when the dipole aligns perfectly with the field (0 or 180 degrees), meaning no rotational force is exerted.
In the exercise, the angle \( \theta = 36.9^\circ \) is a specific value that contributes to the calculation of the field strength when given the torque. By considering such angles, we better understand the dynamic equilibrium of dipoles in fields.

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Most popular questions from this chapter

A point charge \(q_1 = -\)4.00 nC is at the point \(x =\) 0.600 m, \(y =\) 0.800 m, and a second point charge \(q_2 = +\)6.00 nC is at the point \(x =\) 0.600 m, \(y =\) 0. Calculate the magnitude and direction of the net electric field at the origin due to these two point charges.

A negative point charge \(q_1 = -4.00\) nC is on the \(x\)-axis at \(x =\) 0.60 m. A second point charge \(q_2\) is on the \(x\)-axis at \(x = -\)1.20 m. What must the sign and magnitude of \(q_2\) be for the net electric field at the origin to be (a) 50.0 N\(/\)C in the \(+x\)-direction and (b) 50.0 N\(/\)C in the \(-\)x-direction?

Three point charges are arranged on a line. Charge \(q_3 = +\)5.00 nC and is at the origin. Charge \(q_2 = -\)3.00 nC and is at \(x = +\)4.00 cm. Charge \(q_1\) is at \(x = +\)2.00 cm. What is \(q_1\) (magnitude and sign) if the net force on \(q_3\) is zero?

Point charge \(q_1 = -6.00 \times \space 10^{-6}\) C is on the \(x\)-axis at \(x = -0.200\space \mathrm{m}\). Point charge \(q_2\) is on the \(x\)-axis at \(x = +0.400 \space \mathrm{m}\). Point charge \(q_3 = +3.00 \times \space 10^{-6}\) C is at the origin. What is \(q_2\) (magnitude and sign) (a) if the net force on \(q_3\) is \(6.00 \mathrm{N}\) in the \(+x-\mathrm{direction}\); (b) if the net force on \(q_3\) is \(6.00 \mathrm{N}\) in the \(-x-\mathrm{direction}\)?

Two point charges are placed on the \(x\)-axis as follows: Charge \(q_1 = +\)4.00 nC is located at \(x =\) 0.200 m, and charge \(q_2 = +\)5.00 nC is at \(x = -\)0.300 m . What are the magnitude and direction of the total force exerted by these two charges on a negative point charge \(q_3 = -\)6.00 nC that is placed at the origin?

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