/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 A nerve signal is transmitted th... [FREE SOLUTION] | 91Ó°ÊÓ

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A nerve signal is transmitted through a neuron when an excess of \(Na^+\) ions suddenly enters the axon, a long cylindrical part of the neuron. Axons are approximately 10.0 \(\mu\)m in diameter, and measurements show that about 5.6 \(\times \space 10^{11} \space Na^+\)ions per meter (each of charge \(+e\)) enter during this process. Although the axon is a long cylinder, the charge does not all enter everywhere at the same time. A plausible model would be a series of point charges moving along the axon. Consider a 0.10-mm length of the axon and model it as a point charge. (a) If the charge that enters each meter of the axon gets distributed uniformly along it, how many coulombs of charge enter a 0.10-mm length of the axon? (b) What electric field (magnitude and direction) does the sudden influx of charge produce at the surface of the body if the axon is 5.00 cm below the skin? (c) Certain sharks can respond to electric fields as weak as 1.0 \(\mu N/C\). How far from this segment of axon could a shark be and still detect its electric field?

Short Answer

Expert verified
(a) 8.96 pC; (b) 0.322 N/C towards axon; (c) 8.97 cm away.

Step by step solution

01

Determine Charge Density per Meter

Given that there are \(5.6 \times 10^{11} \ Na^+\) ions per meter and each ion has a charge of \(+e = 1.6 \times 10^{-19} \ C\), the charge per meter is calculated as:\[\lambda = (5.6 \times 10^{11} \ ions/m) \times (1.6 \times 10^{-19} \ C/ion) = 8.96 \times 10^{-8} \ C/m\]
02

Calculate Charge in a 0.10-mm Segment

A 0.10-mm length is equivalent to \(0.10 \times 10^{-3} \ m = 1.0 \times 10^{-4} \ m\). Use the charge density to find the charge in this segment:\[Q = \lambda \times \text{length} = (8.96 \times 10^{-8} \ C/m) \times (1.0 \times 10^{-4} \ m) = 8.96 \times 10^{-12} \ C\]
03

Calculate Electric Field at the Surface of the Body

The electric field due to this point charge at a distance \(r = 5.00 \times 10^{-2} \ m\) is given by Coulomb's law:\[E = \frac{k \cdot Q}{r^2}\]where \(k = 8.99 \times 10^9 \ N \cdot m^2/C^2\). Substitute the values:\[E = \frac{(8.99 \times 10^9) \cdot (8.96 \times 10^{-12})}{(5.00 \times 10^{-2})^2} \approx 3.22 \times 10^{-1} \ N/C\]
04

Determine Maximum Detection Distance for Sharks

Sharks can detect electric fields as weak as \(1.0 \times 10^{-6} \ N/C\). Set this as the electric field and solve for the distance \(r\):\[1.0 \times 10^{-6} = \frac{(8.99 \times 10^9) \cdot (8.96 \times 10^{-12})}{r^2}\]Rearrange and solve for \(r\):\[r^2 = \frac{(8.99 \times 10^9) \cdot (8.96 \times 10^{-12})}{1.0 \times 10^{-6}}\]\[r = \sqrt{80.54 \times 10^{-3}} \approx 8.97 \times 10^{-2} \ m\]Thus, the shark can detect fields up to about 0.0897 meters, or 8.97 cm, away.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is a fundamental principle that quantifies the electric force between two charged objects. The law states that the force between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as:
\[ F = k \frac{{q_1 q_2}}{{r^2}} \]
where \( F \) is the force between the charges, \( q_1 \) and \( q_2 \) are the magnitudes of the charges, \( r \) is the distance between the charges, and \( k \) is Coulomb's constant, approximately equal to \( 8.99 \times 10^9 \, N \cdot m^2/C^2 \).
The law serves as a cornerstone for understanding how electric fields interact, making it crucial when analyzing scenarios such as the electric field produced by charged ions entering a neuron during signal transmission.
Charge Density
Charge density is a measure of the distribution of electric charge per unit length, area, or volume. In this exercise, we focus on linear charge density, represented as \( \lambda \), which describes how charge is distributed along a line, such as an axon.
The linear charge density can be calculated using the formula:
\[ \lambda = \frac{Q}{L} \]
where \( Q \) is the total charge and \( L \) is the length over which the charge is distributed. For example, if there are \( 5.6 \times 10^{11} \) ions per meter, each carrying a charge of \( +e = 1.6 \times 10^{-19} \ C \), the linear charge density becomes essential for finding the charge in any specific segment of the axon.
By understanding charge density, one can better visualize how electric fields are influenced by the continuous flow of charges, especially in biological systems like neurons.
Neuron Electrophysiology
Neuron electrophysiology explores how neurons use electric signals to perform their functions. Neurons, being long and thin cells, transmit information using changes in electric potential across their membranes.
The influx of \( Na^+ \) ions is a crucial component in this process. When these ions enter an axon rapidly, they cause localized changes in the electric potential, representing the nerve signal being transmitted. This change in charge is essentially the movement of electrical energy along the neuron. Understanding how charges move within neurons is central to deciphering how brains process information.
By modeling portions of the axon as point charges, electrophysiology connects micro-level electrochemical events to larger phenomena like nerve impulses, illustrating the complex interaction between biology and electric fields.
Detection of Electric Fields by Sharks
Sharks possess a remarkable sensory ability known as electroreception, which allows them to detect electric fields in their environment. This trait is facilitated by specialized organs called the ampullae of Lorenzini, which can sense minute electric field changes produced by other organisms.
This sensitivity plays a critical role in their hunting behavior, enabling sharks to locate prey even when it is hidden or camouflaged. In relation to axon discharge, sharks could theoretically detect the weak electric fields generated when ions enter a neuron, if they are close enough.
Research has shown that sharks can perceive electric fields as weak as \( 1.0 \, \mu N/C \). The theoretical exercise shows that a shark could detect an axon's electric field from about 8.97 cm away. This insight into how sharks and other species use electric fields highlights the fascinating intersection between biology and physics.

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Most popular questions from this chapter

A small sphere with mass \(m\) carries a positive charge \(q\) and is attached to one end of a silk fiber of length \(L\). The other end of the fiber is attached to a large vertical insulating sheet that has a positive surface charge density \(\sigma\). Show that when the sphere is in equilibrium, the fiber makes an angle equal to arctan (\(q\sigma/2mg\epsilon_0\)) with the vertical sheet.

Lightning occurs when there is a flow of electric charge (principally electrons) between the ground and a thundercloud. The maximum rate of charge flow in a lightning bolt is about 20,000 C\(/\)s; this lasts for 100 \(\mu\)s or less. How much charge flows between the ground and the cloud in this time? How many electrons flow during this time?

Two small aluminum spheres, each having mass 0.0250 kg, are separated by 80.0 cm. (a) How many electrons does each sphere contain? (The atomic mass of aluminum is 26.982 g\(/\)mol, and its atomic number is 13.) (b) How many electrons would have to be removed from one sphere and added to the other to cause an attractive force between the spheres of magnitude 1.00 \(\times\) 10\(^4\) N (roughly 1 ton)? Assume that the spheres may be treated as point charges. (c) What fraction of all the electrons in each sphere does this represent?

(a) An electron is moving east in a uniform electric field of 1.50 N\(/\)C directed to the west. At point \(A\), the velocity of the electron is 4.50 \(\times 10^5\) m\(/\)s toward the east. What is the speed of the electron when it reaches point B, 0.375 m east of point A? (b) A proton is moving in the uniform electric field of part (a). At point \(A\), the velocity of the proton is 1.90 \(\times 10^4\) m\(/\)s, east. What is the speed of the proton at point \(B\)?

You have a pure (24-karat) gold ring of mass 10.8 g. Gold has an atomic mass of 197 g\(/\)mol and an atomic number of 79. (a) How many protons are in the ring, and what is their total positive charge? (b) If the ring carries no net charge, how many electrons are in it?

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