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An ideal Carnot engine operates between 500\(^\circ\)C and 100\(^\circ\)C with a heat input of 250 J per cycle. (a) How much heat is delivered to the cold reservoir in each cycle? (b) What minimum number of cycles is necessary for the engine to lift a 500-kg rock through a height of 100 m?

Short Answer

Expert verified
(a) 120.75 J; (b) At least 3797 cycles.

Step by step solution

01

Convert Temperatures from Celsius to Kelvin

The temperatures given in the problem need to be converted from Celsius to Kelvin because temperature calculations must be in Kelvin. The conversion formula is \( T(K) = T(°C) + 273.15 \). So, for 500°C, \( T_1 = 500 + 273.15 = 773.15 \) K. For 100°C, \( T_2 = 100 + 273.15 = 373.15 \) K.
02

Calculate Efficiency of Carnot Engine

The efficiency of a Carnot engine is given by \( \eta = 1 - \frac{T_2}{T_1} \), where \( T_1 \) and \( T_2 \) are the temperatures of the hot and cold reservoir, respectively. Substituting the temperatures: \( \eta = 1 - \frac{373.15}{773.15} \approx 0.517 \).
03

Calculate Work Done by the Engine

The work done \( W \) by the engine can be calculated using the formula \( W = Q_1 \times \eta \), where \( Q_1 \) is the heat input. Given \( Q_1 = 250 \) J and \( \eta \approx 0.517 \), we find \( W = 250 \times 0.517 \approx 129.25 \) J.
04

Calculate Heat Delivered to Cold Reservoir

The heat delivered to the cold reservoir \( Q_2 \) can be found using the relation \( Q_1 = W + Q_2 \). Rearranging gives \( Q_2 = Q_1 - W \). Therefore, \( Q_2 = 250 - 129.25 \approx 120.75 \) J.
05

Calculate Work Required to Lift a Rock

The work required to lift a rock is calculated using the formula \( W = mgh \), where \( m \) is the mass of the rock, \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)) and \( h \) is the height. Here, \( m = 500 \) kg and \( h = 100 \) m, so \( W = 500 \times 9.81 \times 100 = 490500 \) J.
06

Calculate Number of Cycles Required

To find the number of cycles needed to do 490500 J of work, divide the total work by the work per cycle. Using the previously calculated work per cycle (129.25 J), the number of cycles \( n \) is \( n = \frac{490500}{129.25} \approx 3796.5 \). Thus, at least 3797 cycles are required, since we count partial cycles as full.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamic Efficiency
The concept of thermodynamic efficiency relates to how well a Carnot engine converts heat into work. For an ideal Carnot engine, this efficiency is given by the equation \( \eta = 1 - \frac{T_2}{T_1} \), where \( T_1 \) and \( T_2 \) are the absolute temperatures of the hot and cold reservoirs, respectively.
This efficiency equation highlights a key principle: the efficiency of a Carnot engine depends directly on the temperature difference between the two reservoirs.
The larger this temperature difference, the higher the potential efficiency. However, it's worth noting that even with perfect, theoretical conditions, no engine can achieve 100% efficiency due to the second law of thermodynamics. The Carnot cycle represents the maximum possible efficiency any engine operating between two temperatures can achieve.
Heat Transfer
Heat transfer is a fundamental concept in thermodynamics, playing a crucial role in the operation of heat engines like the Carnot engine. In the context of the exercise, heat transfer occurs primarily between the heat source (hot reservoir) and the cold reservoir.
In each cycle of the Carnot engine described, a certain amount of heat, \( Q_1 = 250 \) J, is absorbed from the hot reservoir. This heat serves as the engine's input.
The engine converts part of this heat into work, with the rest being transferred to the cold reservoir. The heat delivered to the cold reservoir can be calculated using \( Q_2 = Q_1 - W \), where \( W \) is the work done.
  • A well-designed engine maximizes \( W \), trying to keep \( Q_2 \) as low as practically possible.
  • Effective heat transfer is essential for maintaining efficiency.
This balance between input heat, work conversion, and residual heat transfer illustrates the constraints an ideal engine faces.
Work and Energy
In the context of a Carnot engine, work and energy are interconnected concepts that describe the engine's purpose and operation. The energy provided as heat is transformed into work across each cycle of the engine.
The engine's job is to perform useful work, such as lifting a weight, as described in the exercise. This is calculated by the formula \( W = mgh \), where \( m \) is the mass of the object, \( g \) is gravitational acceleration, and \( h \) is the height lifted.
In the exercise, the engine must perform a substantial amount of work, 490,500 J, to lift a rock. To accomplish this, the Carnot engine must undergo several cycles, each contributing a portion of the necessary energy.
  • The total energy required depends on the mass of the object and the height it is lifted.
  • The number of cycles required is determined by dividing the total energy by the work output per cycle.
In an ideal situation, balancing the conversion of heat into work dictates how efficiently energy is used in performing tasks.

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Most popular questions from this chapter

You decide to take a nice hot bath but discover that your thoughtless roommate has used up most of the hot water. You fill the tub with 195 kg of 30.0\(^\circ\)C water and attempt to warm it further by pouring in 5.00 kg of boiling water from the stove. (a) Is this a reversible or an irreversible process? Use physical reasoning to explain. (b) Calculate the final temperature of the bath water. (c) Calculate the net change in entropy of the system (bath water + boiling water), assuming no heat exchange with the air or the tub itself.

A Carnot engine is operated between two heat reservoirs at temperatures of 520 \(K\) and 300 \(K\). (a) If the engine receives 6.45 \(kJ\) of heat energy from the reservoir at 520 \(K\) in each cycle, how many joules per cycle does it discard to the reservoir at 300 \(K\)? (b) How much mechanical work is performed by the engine during each cycle? (c) What is the thermal efficiency of the engine?

If the proposed plant is built and produces 10 \(MW\) but the rate at which waste heat is exhausted to the cold water is 165 \(MW\), what is the plant's actual efficiency? (a) 5.7%; (b) 6.1%; (c) 6.5%; (d) 16.5%.

As a budding mechanical engineer, you are called upon to design a Carnot engine that has 2.00 mol of a monatomic ideal gas as its working substance and operates from a high temperature reservoir at 500\(^\circ\)C. The engine is to lift a 15.0-kg weight 2.00 m per cycle, using 500 J of heat input. The gas in the engine chamber can have a minimum volume of 5.00 \(L\) during the cycle. (a) Draw a \(pV\)-diagram for this cycle. Show in your diagram where heat enters and leaves the gas. (b) What must be the temperature of the cold reservoir? (c) What is the thermal efficiency of the engine? (d) How much heat energy does this engine waste per cycle? (e) What is the maximum pressure that the gas chamber will have to withstand?

A gasoline engine takes in 1.61 \(\times\) 10\(^4\) J of heat and delivers 3700 J of work per cycle. The heat is obtained by burning gasoline with a heat of combustion of 4.60 \(\times\) 10\(^4\) J/g. (a) What is the thermal efficiency? (b) How much heat is discarded in each cycle? (c) What mass of fuel is burned in each cycle? (d) If the engine goes through 60.0 cycles per second, what is its power output in kilowatts? In horsepower?

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