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The fastest measured pitched baseball left the pitcher's hand at a speed of 45.0 m/s. If the pitcher was in contact with the ball over a distance of 1.50 m and produced constant acceleration, (a) what acceleration did he give the ball, and (b) how much time did it take him to pitch it?

Short Answer

Expert verified
Acceleration: 675 m/s², Time: 0.067 seconds.

Step by step solution

01

Identify Known Values

First, let's list all the known values from the problem:- Final velocity, \( v = 45.0 \text{ m/s} \)- Initial velocity, \( u = 0 \text{ m/s} \) (since the ball was initially at rest)- Distance, \( s = 1.50 \text{ m} \)
02

Use Kinematic Equation for Acceleration

To find the acceleration, we can use the kinematic equation:\[ v^2 = u^2 + 2as \]Plugging in the known values:\[ (45.0)^2 = (0)^2 + 2a(1.50) \]which simplifies to:\[ 2025 = 3a \]
03

Solve for Acceleration

Now, solve for the acceleration \( a \):\[ a = \frac{2025}{3} = 675 \text{ m/s}^2 \]
04

Use Kinematic Equation for Time

Next, we will use another kinematic equation to find the time:\[ v = u + at \]Plugging in the known values:\[ 45.0 = 0 + 675t \]
05

Solve for Time

Solve the equation for time \( t \):\[ t = \frac{45.0}{675} = 0.0667 \text{ seconds} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant Acceleration
Constant acceleration occurs when an object's velocity changes at a steady rate over time. In other words, the acceleration remains the same throughout the motion. For instance, in the baseball pitching scenario, the ball moves from rest to a speed of 45.0 m/s with the same rate of acceleration.
This simplifies calculations, since we don't have to worry about changing acceleration. We apply specific kinematic equations that use this principle. With constant acceleration, we can easily determine other properties of motion, like distance and time.
  • Acceleration is the rate of change of velocity. In this case, it leads to the ball reaching its top speed at 45.0 m/s.
  • We assume the initial velocity was 0 m/s because the ball was at rest before being pitched.
  • This consistency in acceleration allows us to apply the simple kinematic equations discussed below.
Understanding constant acceleration is key to solving motion problems where the rate of speed change doesn't vary. It's a fundamental concept in kinematics that simplifies many real-world scenarios.
Kinematic Equations
Kinematic equations are mathematical formulas used to describe the motion of objects under constant acceleration. They connect variables like velocity, acceleration, distance, and time, allowing us to solve problems when certain values are known.
In our exercise, we're using two kinematic equations:
  • The first equation, \( v^2 = u^2 + 2as \), allows us to find acceleration. Here, \( v \) is the final velocity, \( u \) is the initial velocity, \( a \) is the acceleration, and \( s \) is the distance.
  • The second equation, \( v = u + at \), helps in calculating the time it took to achieve that velocity.
Let's break down how to use them:
- For the baseball problem, since the initial velocity \( u = 0 \), the equation \( v^2 = 2as \) simplifies to find \( a \) directly.
- Next, with the known acceleration from the first equation, \( v = at \) calculates the time.
The utility of kinematic equations lies in their capacity to relate motion elements systematically and predict other unknown parameters effectively.
Velocity Calculations
Velocity calculations help determine how fast an object moves and are crucial in understanding kinematics. Velocity is a vector quantity, meaning it has both magnitude and direction.
Here, we find the final velocity of the baseball from rest to be 45.0 m/s. Given the acceleration, it's important to realize:
- Initial velocity \( (u) \) is 0 m/s, setting the foundation for all following calculations.
- The equation \( v = u + at \) is utilized here to find the time of flight accurately, once acceleration is known.
- Rearranging this formula gives the time as \( t = \frac{v}{a} \).
This breakdown indicates how time is calculated solely from velocity and acceleration, without needing direct measurements. It showcases how understanding the start and end speeds, along with constant acceleration, unravels the time component of the pitch.

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