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Modern vacuum pumps make it easy to attain pressures of the order of 10\({^-}{^1}{^3}\) atm in the laboratory. Consider a volume of air and treat the air as an ideal gas. (a) At a pressure of 9.00\(\times\) 10\({^-}{^1}{^4}\) atm and an ordinary temperature of 300.0 K, how many molecules are present in a volume of 1.00 cm\(^3\)? (b) How many molecules would be present at the same temperature but at 1.00 atm instead?

Short Answer

Expert verified
(a) 2.20脳10鹿鈦 molecules; (b) 2.45脳10鹿鈦 molecules.

Step by step solution

01

Understand the Ideal Gas Law

The ideal gas law is given by the equation \( PV = nRT \), where \( P \) is the pressure, \( V \) is the volume, \( n \) is the number of moles, \( R \) is the gas constant (0.0821 L路atm/mol路K), and \( T \) is the temperature.
02

Convert Units to Liters

Since the volume of air given is in cubic centimeters (cm鲁), and the ideal gas law uses liters (L), we must convert 1.00 cm鲁 to liters: 1.00 cm鲁 = 1.00 脳 10鈦宦 L.
03

Calculate Number of Moles at Low Pressure

Use the ideal gas law to find the number of moles, \( n \), at 9.00 脳 10鈦烩伌 atm:\[ PV = nRT \implies n = \frac{PV}{RT} \]Substituting the values, \( P = 9.00 \times 10^{-4} \) atm, \( V = 1.00 \times 10^{-3} \) L, \( R = 0.0821 \) L路atm/mol路K, and \( T = 300 \) K, \[ n = \frac{9.00 \times 10^{-4} \times 1.00 \times 10^{-3}}{0.0821 \times 300} \approx 3.65 \times 10^{-8} \] moles.
04

Convert Moles to Molecules at Low Pressure

Use Avogadro's number \( 6.022 \times 10^{23} \) molecules/mole to convert moles to molecules:Number of molecules \( = n \times 6.022 \times 10^{23} \approx 3.65 \times 10^{-8} \times 6.022 \times 10^{23} \approx 2.20 \times 10^{16} \) molecules.
05

Calculate Number of Moles at 1.00 atm

Repeat the calculation for 1.00 atm pressure using the same ideal gas law equation:\[ n = \frac{1.00 \times 1.00 \times 10^{-3}}{0.0821 \times 300} \approx 4.06 \times 10^{-5} \] moles.
06

Convert Moles to Molecules at 1.00 atm

Now convert the moles at 1.00 atm to molecules using Avogadro's number:Number of molecules \( = 4.06 \times 10^{-5} \times 6.022 \times 10^{23} \approx 2.45 \times 10^{19} \) molecules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vacuum Pumps in Laboratory
In a laboratory setting, vacuum pumps are essential tools for creating low-pressure environments, crucial for many scientific experiments. These powerful devices reduce the pressure in a closed system by removing air and other gases. This process is measured in terms of atmospheric pressure (atm), where 1 atm is the standard pressure at sea level on Earth.
Modern vacuum pumps can achieve pressures as low as 10 {^-}{^1}{^3} atm. Such reduced pressure environments are useful for a variety of experiments, particularly those involving reactions sensitive to the presence of air or moisture. By lowering the pressure, scientists can also manipulate the behavior of gases, aligning them closer to the ideal gas assumptions, which simplifies the calculations involved in experiments.
In practical terms, vacuum pumps enable precise control over experimental conditions. This control is important when using the ideal gas law to predict and evaluate system behaviors, as it ensures that external variables remain constant.
Molecule Calculation
Understanding how to calculate the number of molecules in a gas using the ideal gas law is crucial. The ideal gas law, expressed by the equation \( PV = nRT \), relates pressure (\( P \)), volume (\( V \)), number of moles (\( n \)), the gas constant (\( R = 0.0821 \, \text{L}\cdot\text{atm/mol}\cdot\text{K} \)), and temperature (\( T \)).
To find the number of molecules, you first need to determine the number of moles of the gas in question. For example, given a pressure and volume, we rearrange the equation to solve for \( n \):
\[ n = \frac{PV}{RT} \]
Once the number of moles is calculated, you can convert moles into molecules using Avogadro's number. Multiplying the number of moles by Avogadro's number gives the number of molecules:
Number of molecules = \( n \times 6.022 \times 10^{23} \)
This step is crucial for understanding the microscopic scale of reactions and behaviors in various gases, providing deep insight into molecular numbers under different conditions.
Avogadro's Number
Avogadro's number is a fundamental constant in chemistry that equates to \( 6.022 \times 10^{23} \) molecules/mole. It is the bridge between the mass of a substance and the amount of substance in moles. This number represents the number of atoms, molecules, or particles in one mole of a substance.
Why is Avogadro's number so significant? It helps us link macroscopic measurements to their microscopic counterparts. For example, by knowing the number of molecules in a given sample, scientists can make accurate predictions about chemical reactions and behaviors.
  • In practical applications, Avogadro's number allows chemists to convert moles into number of molecules or atoms easily, making it an essential tool for calculations in stoichiometry and molecular chemistry.
  • Avogadro's number doesn't just tell us the scale of molecules, it also connects to the larger scope of molecular theory, helping us understand how gases and molecules interact in a defined volume at given conditions.
Its consistent use in calculations reaffirms its crucial role in chemistry, providing accurate and reliable results time after time.

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Most popular questions from this chapter

You have several identical balloons. You experimentally determine that a balloon will break if its volume exceeds 0.900 L. The pressure of the gas inside the balloon equals air pressure (1.00 atm). (a) If the air inside the balloon is at a constant 22.0\(^\circ\)C and behaves as an ideal gas, what mass of air can you blow into one of the balloons before it bursts? (b) Repeat part (a) if the gas is helium rather than air.

A cylinder 1.00 m tall with inside diameter 0.120 m is used to hold propane gas (molar mass 44.1 g/mol) for use in a barbecue. It is initially filled with gas until the gauge pressure is 1.30 \(\times\) 10\(^6\) Pa at 22.0\(^\circ\)C. The temperature of the gas remains constant as it is partially emptied out of the tank, until the gauge pressure is 3.40 \(\times\) 10\(^5\) Pa. Calculate the mass of propane that has been used.

A vertical cylindrical tank contains 1.80 mol of an ideal gas under a pressure of 0.300 atm at 20.0\(^\circ\)C. The round part of the tank has a radius of 10.0 cm, and the gas is supporting a piston that can move up and down in the cylinder without friction. There is a vacuum above the piston. (a) What is the mass of this piston? (b) How tall is the column of gas that is supporting the piston?

How many moles are in a 1.00-kg bottle of water? How many molecules? The molar mass of water is 18.0 g/mol.

A person at rest inhales 0.50 L of air with each breath at a pressure of 1.00 atm and a temperature of 20.0\(^\circ\)C. The inhaled air is 21.0% oxygen. (a) How many oxygen molecules does this person inhale with each breath? (b) Suppose this person is now resting at an elevation of 2000 m but the temperature is still 20.0\(^\circ\)C. Assuming that the oxygen percentage and volume per inhalation are the same as stated above, how many oxygen molecules does this person now inhale with each breath? (c) Given that the body still requires the same number of oxygen molecules per second as at sea level to maintain its functions, explain why some people report 'shortness of breath' at high elevations.

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