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A 0.800-m-long string with linear mass density \(\mu = 7.50\) g/m is stretched between two supports. The string has tension \(F\) and a standing-wave pattern (not the fundamental) of frequency 624 Hz. With the same tension, the next higher standing-wave frequency is 780 Hz. (a) What are the frequency and wavelength of the fundamental standing wave for this string? (b) What is the value of \(F\)?

Short Answer

Expert verified
(a) Fundamental frequency is 156 Hz and wavelength is 1.6 m. (b) Tension \( F \approx 467.6 \text{ N} \).

Step by step solution

01

Understand the Problem

We have a string with a given length and mass density, and we need to find the fundamental frequency and tension based on the two provided frequencies of the standing waves. The key is to use the relationship between the modes of vibration and given frequencies.
02

Identify Standing Wave Orders

Given two consecutive frequencies, we identify these as the second ( -1) and third ( ) harmonic standing wave frequencies. These are given as 624 Hz and 780 Hz, respectively.
03

Calculate the Fundamental Frequency

The fundamental frequency ( _1) can be found from the relationship between consecutive harmonics: _n = _(n-1) + _1. Here, 780 = 624 + _1. Solving gives us _1 = 156 Hz for the fundamental frequency.
04

Calculate Wavelength of Fundamental Frequency

The wavelength (\( \lambda \)) of a standing wave on the string is given by \( \lambda = \frac{2L}{n} \). For the fundamental frequency (n=1), \( \lambda_1 = 2 \times 0.800 \, m = 1.6 \, m \).
05

Using Frequency to Determine Tension

The speed of a wave on a string \( v \) is related to its frequency and wavelength by \( v = f \cdot \lambda \). For the fundamental frequency, \( v = 156 \, Hz \times 1.6 \, m = 249.6 \, m/s \). This speed is also related to tension by \( v = \sqrt{\frac{F}{\mu}} \).
06

Solve for Tension F

Substitute the speed and linear mass density into the tension formula: \( 249.6 = \sqrt{\frac{F}{0.0075}} \). Squaring both sides, we find \( 249.6^2 = \frac{F}{0.0075} \). Solving for \( F \) gives \( F \approx 467.6 \text{ N} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Mass Density
Linear mass density, often represented by the symbol \( \mu \), is a measure of how much mass is distributed along a unit length of an object such as a string. It's expressed in units like grams per meter (g/m). In simple terms, it tells us how heavy the string is for every meter of length. This is a crucial concept because it directly affects how waves travel along the string.

To calculate it, you use the formula:
  • \( \mu = \frac{m}{L} \)
where \( m \) is the mass of the string and \( L \) is its length.

In our problem, the string has a linear mass density of 7.50 g/m, meaning for every meter of this string, it has a mass of 7.50 grams. This plays a key role in determining the speed of waves on the string, as well as the tension needed to achieve certain wave patterns.
Fundamental Frequency
The fundamental frequency is the lowest frequency at which a system like a string can vibrate. It results in the simplest form of standing wave pattern with only two nodes (the ends of the string) and one antinode (the peak in the middle).

This frequency is important because all other possible frequencies, or harmonics, are multiples of this fundamental. For example, the second harmonic is twice the fundamental frequency, the third harmonic is three times, and so on. It forms the foundation for understanding more complex vibrational patterns.

In the given problem, we calculated the fundamental frequency to be 156 Hz, using the relationship between the consecutive harmonics that are given (624 Hz and 780 Hz). It shows how knowing higher-order harmonics can help us deduce the most basic vibration characteristic of the system.
Wave Speed
Wave speed on a string is the speed at which disturbances or waves move along the string. It's determined by both the string's tension and its linear mass density. The relationship of wave speed \( v \) with frequency \( f \) and wavelength \( \lambda \) is given by the formula:
  • \( v = f \cdot \lambda \)
Wave speed is crucial for understanding how quickly a wave will travel and is used to link frequency and wavelength of the standing waves.

In the exercise, we calculated the wave speed for the fundamental frequency as 249.6 m/s using the fundamental frequency (156 Hz) and wavelength (1.6 m). This helps in setting up the formula needed to solve for the tension in the string, showing the interplay between these properties in wave dynamics.
String Tension
String tension, represented by \( F \), is the force exerted along a string, holding it taut. It plays a critical role in determining how fast waves can travel along the string. In a sense, higher tension generally allows waves to move faster.

The relation between wave speed \( v \), tension \( F \), and linear mass density \( \mu \) is expressed as:
  • \( v = \sqrt{\frac{F}{\mu}} \)
This formula helps to understand how tension affects wave motion and, combined with wave speed, allows us to calculate the required tension for a given wave speed.

In our solution, we solved for the tension by substituting the wave speed (249.6 m/s) and linear mass density (0.0075 kg/m). By isolating \( F \) in our equation, we found it to be approximately 467.6 N. This highlights the deep link between physical properties of the string and its vibrational characteristics.

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Most popular questions from this chapter

Provided the amplitude is sufficiently great, the human ear can respond to longitudinal waves over a range of frequencies from about 20.0 Hz to about 20.0 kHz. (a) If you were to mark the beginning of each complete wave pattern with a red dot for the long-wavelength sound and a blue dot for the short- wavelength sound, how far apart would the red dots be, and how far apart would the blue dots be? (b) In reality would adjacent dots in each set be far enough apart for you to easily measure their separation with a meter stick? (c) Suppose you repeated part (a) in water, where sound travels at 1480 m/s. How far apart would the dots be in each set? Could you readily measure their separation with a meter stick?

An ant with mass m is standing peacefully on top of a horizontal, stretched rope. The rope has mass per unit length \(\mu\) and is under tension \(F\). Without warning, Cousin Throckmorton starts a sinusoidal transverse wave of wavelength \(\lambda\) propagating along the rope. The motion of the rope is in a vertical plane. What minimum wave amplitude will make the ant become momentarily weightless? Assume that \(m\) is so small that the presence of the ant has no effect on the propagation of the wave.

A jet plane at takeoff can produce sound of intensity 10.0 W/m\(^2\) at 30.0 m away. But you prefer the tranquil sound of normal conversation, which is 1.0 \(\mu\)W/m\(^2\). Assume that the plane behaves like a point source of sound. (a) What is the closest distance you should live from the airport runway to preserve your peace of mind? (b) What intensity from the jet does your friend experience if she lives twice as far from the runway as you do? (c) What power of sound does the jet produce at takeoff?

A 1750-N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (\(A\) and \(B\)), each 1.25 m long and weighing 0.290 N. The center of gravity of this beam is one-third of the way along the beam from the end where wire A is attached. If you pluck both strings at the same time at the beam, what is the time delay between the arrival of the two pulses at the ceiling? Which pulse arrives first? (Ignore the effect of the weight of the wires on the tension in the wires.)

A strong string of mass 3.00 g and length 2.20 m is tied to supports at each end and is vibrating in its fundamental mode. The maximum transverse speed of a point at the middle of the string is 9.00 m/s. The tension in the string is 330 N. (a) What is the amplitude of the standing wave at its antinode? (b) What is the magnitude of the maximum transverse acceleration of a point at the antinode?

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