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You must determine the length of a long, thin wire that is suspended from the ceiling in the atrium of a tall building. A 2.00-cm-long piece of the wire is left over from its installation. Using an analytical balance, you determine that the mass of the spare piece is 14.5 \(\mu\)g. You then hang a 0.400-kg mass from the lower end of the long, suspended wire. When a small-amplitude transverse wave pulse is sent up that wire, sensors at both ends measure that it takes the wave pulse 26.7 ms to travel the length of the wire. (a) Use these measurements to calculate the length of the wire. Assume that the weight of the wire has a negligible effect on the speed of the transverse waves. (b) Discuss the accuracy of the approximation made in part (a).

Short Answer

Expert verified
The length of the wire is approximately 62.0 meters. The assumption about the negligible weight is reasonable given the data.

Step by step solution

01

Determine the Mass per Unit Length of the Spare Piece

First, calculate the mass per unit length of the spare piece of wire. Given that the mass of this 2.00-cm long wire is 14.5 \( \mu \)g, we convert these measurements into base units: 2.00 cm = 0.02 m and 14.5 \( \mu \)g = 14.5 \times 10^{-9} \text{ kg}. Then:\[\mu = \frac{14.5 \times 10^{-9} \text{ kg}}{0.02 \text{ m}} = 7.25 \times 10^{-7} \text{ kg/m}\]This is the mass per unit length of the wire.
02

Determine the Tension in the Wire

The tension in the wire is due to the 0.400 kg mass hanging from it. The force exerted by this mass is its weight, which is calculated using:\[T = m \cdot g = 0.400 \text{ kg} \times 9.81 \text{ m/s}^2 = 3.924 \text{ N}\]where \( g = 9.81 \text{ m/s}^2\) is the acceleration due to gravity.
03

Calculate the Speed of the Wave on the Wire

The speed of a transverse wave on a string is given by the formula:\[v = \sqrt{\frac{T}{\mu}}\]Substitute in the values for \(T\) and \(\mu\) to find:\\[v = \sqrt{\frac{3.924 \text{ N}}{7.25 \times 10^{-7} \text{ kg/m}}} = 2324.7 \text{ m/s}\]
04

Calculate the Length of the Wire

Using the time it takes for the wave to travel the length of the wire (26.7 ms or 0.0267 s), and the wave speed calculated previously, the length \( L \) can be determined by rearranging the wave speed formula \( v = \frac{L}{t} \):\[L = v \times t = 2324.7 \text{ m/s} \times 0.0267 \text{ s} \approx 62.0 \text{ m}\]Thus, the length of the wire is approximately 62.0 meters.
05

Evaluate Accuracy of Assumptions

The accuracy of the assumption that the weight of the wire is negligible in affecting the speed is dependent on how small the mass of the wire is compared to the tension created by the 0.400 kg mass. Our assumption is reasonable if the wire's mass is much less than the hanging mass. With our available data, the wire's weight is small relative to the tension, supporting the assumption.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Pulse on Wire
When you hear the term "wave pulse," imagine a single disturbance that travels through a medium. In this case, the medium is a thin wire. A wave pulse on a wire occurs when a brief disturbance creates a wave that moves along the wire. In our example scenario, a transverse wave pulse is sent up a suspended wire. Here are some essential points:
  • The pulse's motion is perpendicular to the wire's length, hence the name "transverse."
  • Transverse waves are crucial since they provide a way to measure unknown quantities such as the wire’s length.
  • The speed and travel time of the wave pulse help calculate these measurements.
Understanding wave pulses enables us to apply physics concepts to real-world problems, such as determining the length of wires in buildings.
Mass per Unit Length
Mass per unit length is a simple but vital concept in understanding wave motion on a wire. It tells you how much mass exists in each unit of length of the wire. For our problem:
  • The spare piece of wire, 2 cm long, has a mass of 14.5 µg, which tells us its mass per unit length.
  • Converting these to standard units, we have a length of 0.02 m and a mass of 14.5 \( \times 10^{-9} \) kg.
  • Dividing the mass by the length provides mass per unit length as \( 7.25 \times 10^{-7} \) kg/m.
This value is crucial for further calculations, like evaluating the wave's speed on the wire. Understanding mass per unit length helps in calculating how disturbances (like wave pulses) move through the material.
Transverse Wave Speed
The speed of a transverse wave on a wire depends on two main factors: the tension in the wire and its mass per unit length. The formula for transverse wave speed \( v \) is:\[v = \sqrt{\frac{T}{\mu}} \]where \( T \) is the tension and \( \mu \) is the mass per unit length. In our problem:
  • The tension was found to be 3.924 N from the weight of a hanging mass.
  • The mass per unit length (\( \mu \)) was previously calculated as \( 7.25 \times 10^{-7} \) kg/m.
  • Substituting these into the formula, we find the wave speed to be 2324.7 m/s.
The wave speed is essential to determining how quickly information or energy travels along the wire.
Tension Calculation
Tension calculation is another fundamental step when dealing with physics problems on wires. Tension is essentially the pulling force exerted by a string or wire when an object is hung from it. To calculate the tension:
  • Determine the weight of the object hanging from the wire.
  • Apply the formula \( T = m \cdot g \), where \( m \) is the mass of the object (0.400 kg in this case) and \( g \) is the acceleration due to gravity (approximately 9.81 m/s²).
  • The calculated tension in our example is 3.924 N.
Tension influences the speed of a wave pulse on the wire, making it a critical element of solving such physics problems.

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Most popular questions from this chapter

By measurement you determine that sound waves are spreading out equally in all directions from a point source and that the intensity is 0.026 W/m\(^2\) at a distance of 4.3 m from the source. (a) What is the intensity at a distance of 3.1 m from the source? (b) How much sound energy does the source emit in one hour if its power output remains constant?

A 1750-N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (\(A\) and \(B\)), each 1.25 m long and weighing 0.290 N. The center of gravity of this beam is one-third of the way along the beam from the end where wire A is attached. If you pluck both strings at the same time at the beam, what is the time delay between the arrival of the two pulses at the ceiling? Which pulse arrives first? (Ignore the effect of the weight of the wires on the tension in the wires.)

A thin, taut string tied at both ends and oscillating in its third harmonic has its shape described by the equation \(y(x, t) = (5.60 \, \mathrm{cm}) \mathrm{sin} [(0.0340 \mathrm{rad/cm})x] \mathrm{sin} [(150.0 \, \mathrm{rad/s})t]\), where the origin is at the left end of the string, the x-axis is along the string, and the \(y\)-axis is perpendicular to the string. (a) Draw a sketch that shows the standing-wave pattern. (b) Find the amplitude of the two traveling waves that make up this standing wave. (c) What is the length of the string? (d) Find the wavelength, frequency, period, and speed of the traveling waves. (e) Find the maximum transverse speed of a point on the string. (f) What would be the equation \(y(x,t)\) for this string if it were vibrating in its eighth harmonic?

One end of a horizontal rope is attached to a prong of an electrically driven tuning fork that vibrates the rope transversely at 120 Hz. The other end passes over a pulley and supports a 1.50-kg mass. The linear mass density of the rope is 0.0480 kg/m. (a) What is the speed of a transverse wave on the rope? (b) What is the wavelength? (c) How would your answers to parts (a) and (b) change if the mass were increased to 3.00 kg?

A large rock that weighs 164.0 N is suspended from the lower end of a thin wire that is 3.00 m long. The density of the rock is 3200 kg/m\(^3\). The mass of the wire is small enough that its effect on the tension in the wire can be ignored. The upper end of the wire is held fixed. When the rock is in air, the fundamental frequency for transverse standing waves on the wire is 42.0 Hz. When the rock is totally submerged in a liquid, with the top of the rock just below the surface, the fundamental frequency for the wire is 28.0 Hz. What is the density of the liquid?

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