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Adjacent antinodes of a standing wave on a string are 15.0 cm apart. A particle at an antinode oscillates in simple harmonic motion with amplitude 0.850 cm and period 0.0750 s. The string lies along the \(+x\)-axis and is fixed at \(x = 0\). (a) How far apart are the adjacent nodes? (b) What are the wavelength, amplitude, and speed of the two traveling waves that form this pattern? (c) Find the maximum and minimum transverse speeds of a point at an antinode. (d) What is the shortest distance along the string between a node and an antinode?

Short Answer

Expert verified
(a) 15.0 cm; (b) 30.0 cm, 0.850 cm, 4.00 m/s; (c) 0.711 m/s and 0; (d) 7.5 cm.

Step by step solution

01

Find Distance Between Adjacent Nodes

In a standing wave, adjacent nodes and antinodes are separated by a quarter of the wavelength, and adjacent antinodes are separated by half the wavelength. Given the distance between adjacent antinodes is 15.0 cm, the wavelength \(\lambda\) can be determined as:\[\lambda = 2 \times 15.0 \text{ cm} = 30.0 \text{ cm}\]The distance between adjacent nodes is half the wavelength:\[\text{Distance between nodes} = \frac{\lambda}{2} = \frac{30.0 \text{ cm}}{2} = 15.0 \text{ cm}\]
02

Calculate Wavelength, Amplitude, and Speed of Traveling Waves

We already found that the wavelength of the traveling waves is 30.0 cm. The amplitude of the traveling waves contributing to the standing wave is the same as the amplitude at an antinode:\[A = 0.850 \text{ cm}\]The speed \(v\) of the traveling waves is given by the formula:\[v = \frac{\lambda}{T}\]where \(\lambda = 0.30 \text{ m}\) and the period \(T = 0.0750 \text{ s}\), thus:\[v = \frac{0.30 \text{ m}}{0.0750 \text{ s}} = 4.00 \text{ m/s}\]
03

Determine Maximum and Minimum Transverse Speeds at an Antinode

The maximum transverse speed of a point undergoing simple harmonic motion is given by:\[v_{max} = A \cdot \omega = A \cdot \frac{2\pi}{T}\]where \(A = 0.00850 \text{ m}\) (converted from cm) and \(T = 0.0750 \text{ s}\):\[v_{max} = 0.00850 \text{ m} \times \frac{2\pi}{0.0750 \text{ s}} = 0.711 \text{ m/s}\]The minimum speed is zero, as at maximum displacement the velocity is zero.
04

Calculate Shortest Distance Between a Node and an Antinode

The shortest distance between a node and an adjacent antinode in a standing wave is a quarter of the wavelength \(\lambda\). Since \(\lambda = 30.0 \text{ cm}\):\[\text{Distance} = \frac{30.0 \text{ cm}}{4} = 7.5 \text{ cm}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simple Harmonic Motion
Simple harmonic motion (SHM) is a type of periodic motion where an object moves back and forth over the same path. The movement can be likened to the motion of a pendulum or a mass on a spring. In the context of a standing wave, the particles at the antinodes exhibit this form of motion. The defining qualities of SHM include:
  • **Amplitude**: This is the maximum distance a particle moves from its rest, or equilibrium, position. In our example, the amplitude is 0.850 cm.
  • **Period**: The period of oscillation is how long it takes for a particle to complete a full cycle of motion. For the particle at an antinode, this period is 0.0750 seconds.
  • **Frequency**: It is the inverse of the period, i.e., the number of cycles per unit time. Frequency is often denoted by the symbol \( f \) and calculated using \( f = \frac{1}{T} \), where \( T \) is the period.
Particles at the antinodes oscillate faster than those nearer to the nodes, displaying SHM characteristics as they speed up and slow down through their path of motion.
Wave Speed
Wave speed is the speed at which a wave travels through a medium. For a wave along a string, this speed can be calculated if we know the wavelength and the period. Simply put, the wave speed \( v \) is determined by the formula:\[ v = \frac{ \lambda }{ T } \]where \( \lambda \) is the wavelength and \( T \) is the period. In this scenario, the wave speed is given as 4.00 m/s. It’s important to understand that this speed indicates how quickly the overall wave pattern moves along the string. In a standing wave, this is reflected as waves traveling in both directions, with the result being a fixed interference pattern where particular points, called nodes and antinodes, remain stationary.The speed of a wave depends on the properties of the medium and the tension of the string, but not on the amplitude or frequency of the wave. Understanding wave speed helps in analyzing situations where waves interact with structures, like bridges or buildings, by considering their natural frequencies.
Wave Amplitude
Amplitude in waves is a measure of the wave's height from the center line to the peak (or trough). This concept is crucial when analyzing standing waves, as it provides insight into the energy carried by the wave. In our example, the wave amplitude at an antinode is 0.850 cm, meaning that each particle at an antinode moves 0.850 cm from its equilibrium position in simple harmonic motion. When discussing amplitude:
  • An increase in amplitude results in a greater energy transfer, which can affect how a wave interacts with its environment.
  • Amplitude is related directly to the wave’s energy; greater amplitude signifies higher energy waves.
  • In a standing wave, the amplitude varies along the length, being maximum at antinodes and zero at nodes.
Amplitude does remain constant if no energy is lost to the environment, underlining its importance when evaluating wave phenomena and their practical implications in fields like acoustics, optics, or even quantum mechanics.
Wavelength
Wavelength is a fundamental property of a wave. It describes the distance between identical points on consecutive waves, such as from peak to peak or trough to trough.In this standing wave problem, the wavelength \( \lambda \) is determined to be 30.0 cm. This was calculated from the known distance between adjacent antinodes, which is half the wavelength. Some key points about wavelengths include:
  • **Relationship to Frequency**: Wavelength is inversely related to frequency when the wave speed is constant. Thus, \( v = f \lambda \) helps calculate either parameter if the other is known, along with speed.
  • **Separation in Standing Waves**: Within a standing wave on a string, nodes and antinodes are tactically placed. The distance between adjacent nodes or antinodes is half of the total wavelength.
  • **Wave Propagation**: In physical terms, longer wavelengths are associated with lower frequencies and vice versa, impacting how waves behave as they move through different media.
Wavelength is crucial when examining how waves bend, or diffract, around obstacles, a key consideration in engineering and scientific fields concerned with wave dynamics.

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Most popular questions from this chapter

A piano wire with mass 3.00 g and length 80.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and amplitude 1.6 mm travels along the wire. (a) Calculate the average power carried by the wave. (b) What happens to the average power if the wave amplitude is halved?

A string with both ends held fixed is vibrating in its third harmonic. The waves have a speed of 192 m/s and a frequency of 240 Hz. The amplitude of the standing wave at an antinode is 0.400 cm. (a) Calculate the amplitude at points on the string a distance of (i) 40.0 cm; (ii) 20.0 cm; and (iii) 10.0 cm from the left end of the string. (b) At each point in part (a), how much time does it take the string to go from its largest upward displacement to its largest downward displacement? (c) Calculate the maximum transverse velocity and the maximum transverse acceleration of the string at each of the points in part (a).

The speed of sound in air at 20\(^\circ\)C is 344 m/s. (a) What is the wavelength of a sound wave with a frequency of 784 Hz, corresponding to the note G\(_5\) on a piano, and how many milliseconds does each vibration take? (b) What is the wavelength of a sound wave one octave higher (twice the frequency) than the note in part (a)?

You are exploring a newly discovered planet. The radius of the planet is \(7.20 \times 10^7\) m. You suspend a lead weight from the lower end of a light string that is 4.00 m long and has mass 0.0280 kg. You measure that it takes 0.0685 s for a transverse pulse to travel from the lower end to the upper end of the string. On the earth, for the same string and lead weight, it takes 0.0390 s for a transverse pulse to travel the length of the string. The weight of the string is small enough that you ignore its effect on the tension in the string. Assuming that the mass of the planet is distributed with spherical symmetry, what is its mass?

A thin, taut string tied at both ends and oscillating in its third harmonic has its shape described by the equation \(y(x, t) = (5.60 \, \mathrm{cm}) \mathrm{sin} [(0.0340 \mathrm{rad/cm})x] \mathrm{sin} [(150.0 \, \mathrm{rad/s})t]\), where the origin is at the left end of the string, the x-axis is along the string, and the \(y\)-axis is perpendicular to the string. (a) Draw a sketch that shows the standing-wave pattern. (b) Find the amplitude of the two traveling waves that make up this standing wave. (c) What is the length of the string? (d) Find the wavelength, frequency, period, and speed of the traveling waves. (e) Find the maximum transverse speed of a point on the string. (f) What would be the equation \(y(x,t)\) for this string if it were vibrating in its eighth harmonic?

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