/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 67 At the end of a ride at a winter... [FREE SOLUTION] | 91Ó°ÊÓ

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At the end of a ride at a winter-theme amusement park, a sleigh with mass 250 kg (including two passengers) slides without friction along a horizontal, snow-covered surface. The sleigh hits one end of a light horizontal spring that obeys Hooke's law and has its other end attached to a wall. The sleigh latches onto the end of the spring and subsequently moves back and forth in SHM on the end of the spring until a braking mechanism is engaged, which brings the sleigh to rest. The frequency of the SHM is 0.225 Hz, and the amplitude is 0.950 m. (a) What was the speed of the sleigh just before it hit the end of the spring? (b) What is the maximum magnitude of the sleigh's acceleration during its SHM?

Short Answer

Expert verified
Speed before hitting spring: 1.343 m/s. Maximum acceleration: 1.895 m/s².

Step by step solution

01

Understanding the Problem

We must find the speed of the sleigh before it compresses the spring, and the maximum acceleration during its simple harmonic motion (SHM). We'll use the frequency of oscillation, the amplitude, and the mass of the sleigh.
02

Find Spring Constant Using Frequency

The frequency of SHM is given by the formula \( f = \frac{1}{2\pi}\sqrt{\frac{k}{m}} \), where \( f = 0.225 \, \text{Hz} \) and \( m = 250 \, \text{kg} \). Rearrange this formula to solve for \( k \):\[ k = (2\pi f)^2 m \]. Substituting the known values: \[ k = (2\pi \times 0.225)^2 \times 250 \approx 50.21 \, \text{N/m} \].
03

Calculate Maximum Speed

The maximum speed \( v_{max} \) in simple harmonic motion is given by \( v_{max} = \omega A \), where \( \omega = 2\pi f \) and \( A = 0.950 \, \text{m} \). First, calculate angular frequency: \[ \omega = 2\pi \times 0.225 = 1.414 \, \text{rad/s} \]. Now substitute to find \( v_{max} \): \( v_{max} = 1.414 \times 0.950 \approx 1.343 \, \text{m/s} \). Hence, the speed of the sleigh just before hitting the spring is 1.343 m/s.
04

Find Maximum Acceleration

The maximum acceleration \( a_{max} \) in simple harmonic motion is given by \( a_{max} = \omega^2 A \). Using \( \omega = 1.414 \, \text{rad/s} \) and \( A = 0.950 \, \text{m} \): \[ a_{max} = (1.414)^2 \times 0.950 \approx 1.895 \, \text{m/s}^2 \]. The maximum acceleration during SHM is 1.895 m/s².

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spring Constant
The spring constant, denoted as \( k \), is a measure of a spring's stiffness. It tells us how much force is needed to compress or extend the spring by a certain amount. The higher the spring constant, the stiffer the spring. In the context of simple harmonic motion (SHM), understanding the spring constant is crucial as it influences the oscillation behavior.
To find the spring constant from given frequency, the relationship used is:
  • \( f = \frac{1}{2\pi} \sqrt{\frac{k}{m}} \)
Here, \( f \) is the frequency, and \( m \) is the mass of the oscillating object. By rearranging the formula, we can solve for \( k \):
  • \( k = (2\pi f)^2 m \)
In the sleigh example, substituting in the values \( f = 0.225 \, \text{Hz} \) and \( m = 250 \, \text{kg} \) gives a spring constant of approximately \( 50.21 \, \text{N/m} \). This value indicates how strong the spring's pulling force is within this system.
Angular Frequency
Angular frequency, denoted by \( \omega \), describes how quickly an object completes a cycle of motion in SHM, measured in radians per second. It provides a different perspective than regular frequency, focusing more on the rotational aspects of motion, even in linear systems like the sleigh.
To compute angular frequency, the formula involved is:
  • \( \omega = 2\pi f \)
Using the given frequency \( f = 0.225 \, \text{Hz} \), we calculate \( \omega \) as:
  • \( \omega = 2\pi \times 0.225 \approx 1.414 \, \text{rad/s} \)
With angular frequency, we can then determine other motion characteristics, like maximum speed and acceleration during SHM. Angular frequency is essential for linking the periodic nature of oscillatory motion with its measurement in radians.
Maximum Acceleration
Maximum acceleration in the context of SHM indicates the largest magnitude of acceleration that an object can experience during its back-and-forth motion. It occurs at the extremes of motion when the object changes direction. In this scenario, maximum acceleration is synonymous with the force exerted being highest, due to its dependence on both the angular frequency and amplitude.
The formula to determine maximum acceleration \( a_{max} \) is:
  • \( a_{max} = \omega^2 A \)
Here, \( \omega \) is the angular frequency, and \( A \) is the amplitude of motion. Using \( \omega = 1.414 \, \text{rad/s} \) and \( A = 0.950 \, \text{m} \), the maximum acceleration is:
  • \( a_{max} = (1.414)^2 \times 0.950 \approx 1.895 \, \text{m/s}^2 \)
Understanding maximum acceleration is crucial in designing systems to ensure they can handle such forces without failure or loss of performance.

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Most popular questions from this chapter

The tip of a tuning fork goes through 440 complete vibrations in 0.500 s. Find the angular frequency and the period of the motion.

A 10.0-kg mass is traveling to the right with a speed of 2.00 m/s on a smooth horizontal surface when it collides with and sticks to a second 10.0-kg mass that is initially at rest but is attached to a light spring with force constant 170.0 N/m. (a) Find the frequency, amplitude, and period of the subsequent oscillations. (b) How long does it take the system to return the first time to the position it had immediately after the collision?

You hang various masses \(m\) from the end of a vertical, 0.250-kg spring that obeys Hooke's law and is tapered, which means the diameter changes along the length of the spring. Since the mass of the spring is not negligible, you must replace \(m\) in the equation \(T =\) 2\(\pi\sqrt{ m/k }\) with \(m + m_\mathrm{eff}\), where \(m_\mathrm{eff}\) is the effective mass of the oscillating spring. (See Challenge Problem 14.93.) You vary the mass m and measure the time for 10 complete oscillations, obtaining these data: (a) Graph the square of the period \(T\) versus the mass suspended from the spring, and find the straight line of best fit. (b) From the slope of that line, determine the force constant of the spring. (c) From the vertical intercept of the line, determine the spring's effective mass. (d) What fraction is \(m_\mathrm{eff}\) of the spring's mass? (e) If a 0.450-kg mass oscillates on the end of the spring, find its period, frequency, and angular frequency.

A 0.0200-kg bolt moves with SHM that has an amplitude of 0.240 m and a period of 1.500 s. The displacement of the bolt is \(+\)0.240 m when \(t =\) 0. Compute (a) the displacement of the bolt when \(t =\) 0.500 s; (b) the magnitude and direction of the force acting on the bolt when \(t =\) 0.500 s; (c) the minimum time required for the bolt to move from its initial position to the point where \(x = -\)0.180 m; (d) the speed of the bolt when \(x = -\)0.180 m.

(a) \(\textbf{Music}\). When a person sings, his or her vocal cords vibrate in a repetitive pattern that has the same frequency as the note that is sung. If someone sings the note B flat, which has a frequency of 466 Hz, how much time does it take the person's vocal cords to vibrate through one complete cycle, and what is the angular frequency of the cords? (b) \(\textbf{Hearing}\). When sound waves strike the eardrum, this membrane vibrates with the same frequency as the sound. The highest pitch that young humans can hear has a period of 50.0 \(\mu\)s. What are the frequency and angular frequency of the vibrating eardrum for this sound? (c) \(\textbf{Vision}\). When light having vibrations with angular frequency ranging from 2.7 \(\times\) 10\(^{15}\) rad/s to 4.7 \(\times\) 10\(^{15}\) rad/s strikes the retina of the eye, it stimulates the receptor cells there and is perceived as visible light. What are the limits of the period and frequency of this light? (d) \(\textbf{Ultrasound}\). High frequency sound waves (ultrasound) are used to probe the interior of the body, much as x rays do. To detect small objects such as tumors, a frequency of around 5.0 MHz is used. What are the period and angular frequency of the molecular vibrations caused by this pulse of sound?

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