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A 1.80-kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. The period for small-angle oscillations is 0.940 s. (a) What is the moment of inertia of the wrench about an axis through the pivot? (b) If the wrench is initially displaced 0.400 rad from its equilibrium position, what is the angular speed of the wrench as it passes through the equilibrium position?

Short Answer

Expert verified
(a) The moment of inertia is 0.0434 kg·m². (b) The angular speed as it passes through equilibrium is approximately 4.03 rad/s.

Step by step solution

01

Identify the Known Values and Formulas

We know the formula for the period of a physical pendulum is \( T = 2\pi \sqrt{\frac{I}{mgd}} \), where \( I \) is the moment of inertia, \( m = 1.80 \text{ kg} \) is the mass of the wrench, \( g = 9.81 \text{ m/s}^2 \) is the acceleration due to gravity, \( d = 0.250 \text{ m} \) is the distance from the pivot to the center of mass, and \( T = 0.940 \text{ s} \) is the period of oscillation.
02

Solve for the Moment of Inertia

Rearrange the formula to solve for \( I \):\[ I = \left( \frac{T^2 \cdot mgd}{4\pi^2} \right) \]Substitute the known values:\[ I = \left( \frac{0.940^2 \times 1.80 \times 9.81 \times 0.250}{4\pi^2} \right) = 0.0434 \text{ kg} \cdot \text{m}^2 \]
03

Using Energy Conservation for Angular Speed

When the wrench is displaced to \( \theta = 0.400 \text{ rad} \) from equilibrium, it has potential energy given by \( U_i = mgh \) where \( h = d(1 - \cos\theta) \).As it swings down to the equilibrium position, this potential energy is converted into rotational kinetic energy: \( K_f = \frac{1}{2}I\omega^2 \).We have: \( mgh = \frac{1}{2}I\omega^2 \).
04

Calculate the Initial Potential Energy

Calculate the height using \( h = d(1 - \cos(\theta)) \):\[ h = 0.250(1 - \cos(0.400)) = 0.250(1 - 0.921) = 0.0198 \text{ m} \]Thus, the potential energy is:\[ U_i = mgh = 1.80 \times 9.81 \times 0.0198 = 0.350 \text{ J} \]
05

Calculate the Angular Speed

Using energy conservation, set the initial potential energy equal to the final kinetic energy:\[ 0.350 = \frac{1}{2}(0.0434) \omega^2 \]Solving for \( \omega \), we get:\[ \omega = \sqrt{\frac{2 \times 0.350}{0.0434}} \approx 4.026 \text{ rad/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Moment of Inertia
To comprehend the movement of a physical pendulum like our monkey wrench, we need to understand the concept of 'moment of inertia', which measures an object's resistance to rotational motion.
In this exercise, we specifically investigated the moment of inertia about the pivot point.
The moment of inertia (I) is influenced by three main factors:
  • The object's mass (m), which in our example is 1.80 kg.
  • The distribution of this mass, more technically, how far this mass is spread from the axis of rotation.
  • The distance from the pivot to the center of mass (d), which is 0.250 m here.
To solve for the moment of inertia, use the pendulum's period formula: \( T = 2\pi \sqrt{\frac{I}{mgd}} \).
This equation is rearranged to solve \( I \) using the known values, resulting in \( I = 0.0434 \text{ kg} \cdot \text{m}^2 \).
Think of the moment of inertia as the rotational equivalent of mass. The larger the \( I \), the harder it is to change the object's rotational speed.
Calculating Angular Speed
Angular speed (\omega) is a measure of how quickly something spins around an axis. In our pendulum problem, we are interested in how fast the wrench spins as it passes through its equilibrium position.
When the wrench is displaced by 0.400 rad from equilibrium, it has stored energy due to its height change relative to the equilibrium position. As it swings back down, this potential energy turns into rotational kinetic energy.
Here's how to calculate the angular speed:
  • Firstly, find the potential energy at the maximum displacement: \( U_i = mgh \), where \( h = d(1 - \cos(\theta)) \).
  • Then, use the principle of energy conservation: \( mgh = \frac{1}{2}I\omega^2 \), expressing the transition from potential to kinetic energy.
Solving for \( \omega \) gives approximately 4.026 rad/s. This speed provides insight into how rapidly the pendulum passes the center point during its swing.
Understanding angular speed not only helps predict the dynamics of the pendulum but also applies broadly to any rotating systems.
Embracing Energy Conservation
Energy conservation is a powerful principle that states energy within a closed system remains constant, even if it changes forms. In our pendulum problem, this principle explains how potential energy morphs into kinetic energy.
Let's break it down:
  • Initially, when the wrench is elevated, it has maximum potential energy (\( U_i \)) and zero kinetic energy because it hasn't begun to move yet.
  • As the wrench swings towards equilibrium, its height decreases, converting potential energy into kinetic energy, which pays off as increased angular speed.
  • At the equilibrium position, all initial potential energy has become kinetic (\( K_f \)), peaking the wrench's velocity.
This transition shows how energy principles guide the pendulum's motion.
By applying these concepts, we can analyze not only pendulums but various dynamics in physics where energy transformation is key.

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Most popular questions from this chapter

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