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A liquid flowing from a vertical pipe has a definite shape as it flows from the pipe. To get the equation for this shape, assume that the liquid is in free fall once it leaves the pipe. Just as it leaves the pipe, the liquid has speed \(\upsilon$$_0\) and the radius of the stream of liquid is \({r_0}\). (a) Find an equation for the speed of the liquid as a function of the distance \(y\) it has fallen. Combining this with the equation of continuity, find an expression for the radius of the stream as a function of \(y\). (b) If water flows out of a vertical pipe at a speed of 1.20 m/s, how far below the outlet will the radius be one-half the original radius of the stream?

Short Answer

Expert verified
(b) Use the derived expressions to find that radius equals half the original radius at a distance below the outlet.

Step by step solution

01

Identify Initial Conditions and Formulae

Initially, the liquid has a velocity \(\upsilon_0\) and a radius \(r_0\). It is released from rest, and we must consider the effect of gravity as it falls through a distance \(y\). The equations to use are the kinematic equation for velocity under gravity and the equation of continuity.
02

Determine Velocity as a Function of Distance

The velocity \( \upsilon \) of the liquid as it falls is given by the kinematic equation: \[ \upsilon = \sqrt{\upsilon_0^2 + 2gy} \]where \( g \) is the acceleration due to gravity. This accounts for the initial velocity and the increase in velocity as it falls through a height \( y \).
03

Apply the Equation of Continuity

According to the equation of continuity, the flow rate is constant. Therefore, \[ A_0 \upsilon_0 = A \upsilon \]where \( A_0 = \pi r_0^2 \) and \( A = \pi r^2 \). Substituting for \( \upsilon \) gives: \[ \pi r_0^2 \upsilon_0 = \pi r^2 \sqrt{\upsilon_0^2 + 2gy} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematic Equations
Kinematic equations help us understand the motion of objects, whether they are moving at a constant speed or accelerating. In the context of fluid dynamics, these equations become crucial in analyzing the motion of liquids under the influence of gravity. When a liquid exits a pipe, it accelerates due to gravity, even if it began with a non-zero initial speed.To calculate the speed of the liquid at any point as it falls, we use one of the kinematic equations: \[ \upsilon = \sqrt{\upsilon_0^2 + 2gy} \]This equation tells us how velocity increases as the liquid falls through a height \( y \). Here, \( \upsilon_0 \) is the initial speed right as the liquid exits the pipe, and \( g \) is the acceleration due to gravity.
  • The initial speed \( \upsilon_0 \) and the gravitational acceleration \( g \) together determine how fast the liquid speeds up as it falls.
  • This formula is derived from basic principles of motion under constant acceleration.

This step is central to finding how the stream’s speed changes with height, a key part in understanding the behavior of falling fluids.
Equation of Continuity
The equation of continuity is fundamental in fluid dynamics, ensuring mass conservation within a flow. It states that the mass flow rate must be constant from one cross-section of a pipe to another, assuming no addition or loss of fluid.Mathematically, this can be expressed by the equation:\[ A_0 \upsilon_0 = A \upsilon \] where \( A_0 = \pi r_0^2 \) is the initial cross-sectional area of the stream, \( \upsilon_0 \) is the initial velocity, \( A = \pi r^2 \) is the area at some other point, and \( \upsilon \) is the velocity at that point.
  • This relationship shows that as the speed of the liquid increases, its cross-sectional area must decrease to maintain a constant flow rate.
  • By combining this with the previously determined velocity expression, you can solve for the radius at any point:
\[ \pi r_0^2 \upsilon_0 = \pi r^2 \sqrt{\upsilon_0^2 + 2gy} \]This equation allows us to find the radius \( r \) at any distance \( y \) below the pipe outlet, crucial for applications such as predicting spray patterns and jet flows.
Gravitational Acceleration
Gravitational acceleration, denoted by \( g \), is a constant that reflects the force of gravity acting on objects on Earth's surface. It has a standard value of approximately 9.81 m/s². In the context of fluid dynamics, \( g \) plays a significant role by influencing how liquids accelerate as they fall.When liquids are in free fall, such as when exiting a pipe vertically, they experience an increase in speed due to this gravitational pull. This phenomenon is essential when calculating the dynamics of the liquid's flow, in conjunction with both kinematic equations and the continuity equation discussed above.
  • Gravitational acceleration is the driving force that changes the velocity of the liquid over distance.
  • It is critical for predicting how fast a liquid accelerates once it leaves a container or conduit.

In our scenario, understanding \( g \) allows us to connect the dots between velocity changes and the continuity of flow, thus offering a comprehensive insight into fluid behavior. Gravitational acceleration is therefore a cornerstone concept in analyzing and predicting fluid dynamics in a variety of settings.

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