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When an open-faced boat has a mass of 5750 kg, including its cargo and passengers, it floats with the water just up to the top of its gunwales (sides) on a freshwater lake. (a) What is the volume of this boat? (b) The captain decides that it is too dangerous to float with his boat on the verge of sinking, so he decides to throw some cargo overboard so that 20% of the boat's volume will be above water. How much mass should he throw out?

Short Answer

Expert verified
(a) Boat's volume is 5.75 m³. (b) Throw 1150 kg of mass overboard.

Step by step solution

01

Understand the Problem

We have an open-faced boat of mass 5750 kg, floating on a freshwater lake. Our task is to find the volume of the boat when it is just about to sink and then calculate the mass that needs to be thrown overboard to have 20% of the boat's volume above the water.
02

Apply Archimedes' Principle to Find Volume

According to Archimedes' Principle, the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. For the boat, when it floats at gunwale level, the weight of the water displaced is equal to the weight of the boat. Hence, we have:\[ \text{Weight of boat} = \text{Weight of water displaced} \]Given that the density of freshwater is \(1000 \text{ kg/m}^3\),\[ 5750 \text{ kg} = V \times 1000 \text{ kg/m}^3 \]Solving for \(V\) (Volume of the boat):\[ V = \frac{5750}{1000} \text{ m}^3 = 5.75 \text{ m}^3 \]
03

Determine New Buoyant Volume for Stability

We want 20% of the boat's volume to be above water. Thus, 80% of the boat's volume should be submerged to maintain stability at the new condition.\[ V_{\text{new sub}} = 0.8 \times V = 0.8 \times 5.75 \text{ m}^3 \]\[ V_{\text{new sub}} = 4.6 \text{ m}^3 \]
04

Calculate Mass to Throw Overboard

To find out how much mass should be thrown out, we equate the new submerged volume to the weight of displaced water:\[ \text{Mass}_{\text{new}} = V_{\text{new sub}} \times 1000 \text{ kg/m}^3 \]\[ \text{Mass}_{\text{new}} = 4.6 \text{ m}^3 \times 1000 \text{ kg/m}^3 = 4600 \text{ kg} \]The initial mass was 5750 kg, and we want the new effective mass to be 4600 kg. Therefore, the mass that needs to be thrown overboard is:\[ \Delta m = 5750 \text{ kg} - 4600 \text{ kg} = 1150 \text{ kg} \]
05

Verify the Results

Review the calculations to ensure they are consistent with the principles of buoyancy and constraints provided in the problem. The volume calculations and mass throw calculation should align correctly according to Archimedes' Principle and the percentage of submerged volume.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Buoyancy
When we talk about objects floating in fluids, Archimedes' Principle is fundamental to understanding the concept of buoyancy. This principle states that "the buoyant force exerted on a body immersed in a fluid is equal to the weight of the fluid the body displaces." When the boat mentioned in the exercise floats, it means that the upward buoyant force from the water equals the downward gravitational force (the weight of the boat). The boat floats up to its gunwales because the weight of the water displaced equals the boat's total mass. This flotation point signifies an equilibrium where the buoyant force is perfectly balanced with the boat's weight.
  • A boat will rise or submerge depending on how the buoyant force compares with gravitational force.
  • Adding cargo increases the boat's mass, while removing cargo decreases it, altering its buoyancy.
  • The boat's design, such as its shape and volume, plays a crucial role in determining its buoyancy characteristics.
Displacement
Displacement in fluid dynamics refers to the volume or mass of fluid a submerged or floating object displaces. For our boat, initially weighing 5750 kg, it displaces an equivalent weight of water when it's floating. Displacement volume is directly linked to the boat's weight in this context.
To calculate the volume displaced by the boat, we equate it to the weight of the water that this boat displaces. This means:
  • Weight of displaced water = Weight of the boat
  • With freshwater having a known density (1000 kg/m³), it's straightforward to calculate the volume displaced.
  • This gives the volume of water equal to the boat's weight, further helping in determining necessary buoyancy adjustments.
These displacement principles help in designing stable vessels that remain afloat for various cargo and passenger loads.
Volume Calculation
The volume calculation for the boat is integral for determining its flotation level and stability in the water. In the given exercise, the boat's volume is found using the density of water and the weight of the boat. Since the density of freshwater is constant, it allows us to use the formula:
\[\text{Volume}_{\text{boat}} = \frac{\text{Weight of boat}}{\text{Density of water}} = \frac{5750 \text{ kg}}{1000 \text{ kg/m}^3} = 5.75 \text{ m}^3\]This tells us that the boat displaces 5.75 cubic meters of water when it is fully loaded. The volume plays a crucial role when the captain wants more of the boat above water—specifically 20%. Calculating 80% of this volume helps determine how much of the boat should remain submerged to ensure safety.
  • A system for calculation: determine the boat's submerged volume to achieve balance.
  • The known values help ensure that buoyancy is optimized for various operational conditions.
Fluid Mechanics
Fluid mechanics is the branch of physics concerned with the behavior of fluids and the forces on them. In the context of the exercise, it includes understanding how the boat interacts with water and why it floats or sinks. Archimedes' Principle is a specific application of fluid mechanics principles.
Several factors from fluid mechanics play crucial roles:
  • **Density**: The density of water affects the displacement directly. The boat floats efficiently when the displaced water's weight equals the boat's weight, which is determined by the water density.
  • **Pressure**: Fluid pressure plays a part in buoyancy, as it changes with depth and helps determine how much water exerts force on the boat's hull.
  • **Equilibrium**: The stable equilibrium that lets the boat float right up to its gunwales without sinking.
Overall, fluid mechanics underpin every aspect of the design and operation of floating vessels, ensuring they are both efficient and safe for use.

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