/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 A piece of wood is 0.600 m long,... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A piece of wood is 0.600 m long, 0.250 m wide, and 0.080 m thick. Its density is 700 kg/m\(^3\). What volume of lead must be fastened underneath it to sink the wood in calm water so that its top is just even with the water level? What is the mass of this volume of lead?

Short Answer

Expert verified
3.6 kg of lead is needed, and its volume is approximately 0.000317 m³.

Step by step solution

01

Calculate the Volume of the Wood

The volume of the wood can be calculated using the formula for the volume of a rectangular prism:\[ V_{wood} = ext{length} \times ext{width} \times ext{thickness} \]Substituting in the values given:\[ V_{wood} = 0.600 \, \text{m} \times 0.250 \, \text{m} \times 0.080 \, \text{m} = 0.012 \, \text{m}^3 \]
02

Calculate the Mass of the Wood

The mass of the wood can be calculated using its density and volume:\[ m_{wood} = \rho_{wood} \times V_{wood} \]Where the density \( \rho_{wood} \) is 700 kg/m\(^3\) and \( V_{wood} \) is 0.012 m\(^3\):\[ m_{wood} = 700 \, \text{kg/m}^3 \times 0.012 \, \text{m}^3 = 8.4 \, \text{kg} \]
03

Calculate the Buoyant Force Needed

The buoyant force needed to keep the wood completely submerged with its top even with the water level is equal to the weight of the water displaced by the wood:\[ B = \text{density of water} \times \text{gravitational acceleration} \times V_{wood} \]In SI units, the density of water is 1000 kg/m\(^3\) and the gravitational acceleration is approximately 9.8 m/s\(^2\):\[ B = 1000 \, \text{kg/m}^3 \times 9.8 \, \text{m/s}^2 \times 0.012 \, \text{m}^3 = 117.6 \, \text{N} \]
04

Calculate the Required Mass of Lead

The buoyant force must equal the combined weight of the wood and the lead, when the system is just submerged. Using:\[ B = m_{total} \times g \]Where \( m_{total} = m_{wood} + m_{lead} \) and \( g = 9.8 \, \text{m/s}^2 \). Since \( B = 117.6 \, \text{N} \):\[ m_{wood} + m_{lead} = \frac{B}{g} \]\[ 8.4 \, \text{kg} + m_{lead} = \frac{117.6 \, \text{N}}{9.8 \, \text{m/s}^2} = 12 \, \text{kg} \]Solving for \( m_{lead} \):\[ m_{lead} = 12 \, \text{kg} - 8.4 \, \text{kg} = 3.6 \, \text{kg} \]
05

Calculate the Volume of Lead

The volume of lead can be found using its density. Let's denote lead's density as \( \rho_{lead} = 11340 \, \text{kg/m}^3 \):\[ V_{lead} = \frac{m_{lead}}{\rho_{lead}} \]\[ V_{lead} = \frac{3.6 \, \text{kg}}{11340 \, \text{kg/m}^3} \approx 0.000317 \, \text{m}^3 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density
Density is a crucial concept in physics and many other scientific areas. It describes how much mass a particular substance contains in a given volume. For example, in the problem of the wood floating on water, the wood's density is given as 700 kg/m³. This means if you have 1 cubic meter of this wood, its mass would be 700 kg.
Understanding density helps in comparing how substances differ in compactness or heaviness per unit volume.
For instance:
  • Higher density indicates that the matter's particles are closely packed together.
  • Lower density suggests the particles are further apart, making the material lighter for its size.
This property is particularly relevant when exploring buoyancy, as it determines whether an object will float or sink when placed in a fluid.
Volume Calculation
Calculating the volume of an object is determining how much space it occupies. It's vital to solve many physics problems, especially those involving buoyancy. The volume of an object is often determined by its shape and dimensions.
In this example, we calculate the volume of wood using the formula for the volume of a rectangular prism, which is:
  • Volume = Length × Width × Thickness
For the wood, with dimensions 0.600 m, 0.250 m, and 0.080 m, the volume comes out to be 0.012 m³.
Accurate volume calculation is key because it directly influences other calculations, such as determining the mass of a material or its buoyant force in a fluid. A mistake in measuring or computing volume can lead to errors in subsequent physics calculations.
Mass Calculation
Mass calculation involves using the density and volume of a substance to determine how much matter is present. From the example:
  • We know the volume of the wood is 0.012 m³
  • The density provided is 700 kg/m³
By multiplying these values, the mass of the wood is found using the formula:
  1. Mass = Density × Volume
This yields a mass of 8.4 kg for the wood.
Understanding how to calculate mass from density and volume is pivotal in physics, as it is a step that often interlinks with calculating forces like buoyant force in various physics problems.
Physics Problem Solving
Solving physics problems involves a structured approach where understanding the problem's physical nature is crucial. In this problem:
  • We started with the goal of finding how much lead needs to be added to sink the wood in water so that its top is just even with the water level.
  • This required calculating the buoyant force necessary, which equaled the combined weight of the wood and lead when just submerged.
  • We calculated the needed volume of lead by first finding the mass of lead using its given density.
Physics problem solving often involves multiple interconnected steps. For buoyancy problems, one often calculates forces, assesses volume and mass, and applies key concepts like Archimedes' principle in determining floating or sinking behavior.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A firehose must be able to shoot water to the top of a building 28.0 m tall when aimed straight up. Water enters this hose at a steady rate of 0.500 m\(^3\)/s and shoots out of a round nozzle. (a) What is the maximum diameter this nozzle can have? (b) If the only nozzle available has a diameter twice as great, what is the highest point the water can reach?

(a) As you can tell by watching them in an aquarium, fish are able to remain at any depth in water with no effort. What does this ability tell you about their density? (b) Fish are able to inflate themselves using a sac (called the \(swim\) \(bladder\)) located under their spinal column. These sacs can be filled with an oxygen\(-\)nitrogen mixture that comes from the blood. If a 2.75-kg fish in freshwater inflates itself and increases its volume by 10%, find the \(net\) force that the \(water\) exerts on it. (c) What is the net \(external\) force on it? Does the fish go up or down when it inflates itself?

Assume that crude oil from a supertanker has density 750 kg/m\(^3\). The tanker runs aground on a sandbar. To refloat the tanker, its oil cargo is pumped out into steel barrels, each of which has a mass of 15.0 kg when empty and holds 0.120 m\(^3\) of oil. You can ignore the volume occupied by the steel from which the barrel is made. (a) If a salvage worker accidentally drops a filled, sealed barrel overboard, will it float or sink in the seawater? (b) If the barrel floats, what fraction of its volume will be above the water surface? If it sinks, what minimum tension would have to be exerted by a rope to haul the barrel up from the ocean floor? (c) Repeat parts (a) and (b) if the density of the oil is 910 kg/m\(^3\) and the mass of each empty barrel is 32.0 kg.

The Environmental Protection Agency is investigating an abandoned chemical plant. A large, closed cylindrical tank contains an unknown liquid. You must determine the liquid's density and the height of the liquid in the tank (the vertical distance from the surface of the liquid to the bottom of the tank). To maintain various values of the gauge pressure in the air that is above the liquid in the tank, you can use compressed air. You make a small hole at the bottom of the side of the tank, which is on a concrete platform\(-\)so the hole is 50.0 cm above the ground. The table gives your measurements of the horizontal distance \(R\) that the initially horizontal stream of liquid pouring out of the tank travels before it strikes the ground and the gauge pressure \({p_g}\) of the air in the tank. (a) Graph \({R^2}\) as a function of \({p_g}\). Explain why the data points fall close to a straight line. Find the slope and intercept of that line. (b) Use the slope and intercept found in part (a) to calculate the height \(h\) (in meters) of the liquid in the tank and the density of the liquid (in kg/m\(^3\)). Use \(g\) \(=\) 9.80 m/s\(^2\). Assume that the liquid is nonviscous and that the hole is small enough compared to the tank's diameter so that the change in h during the measurements is very small.

Black smokers are hot volcanic vents that emit smoke deep in the ocean floor. Many of them teem with exotic creatures, and some biologists think that life on earth may have begun around such vents. The vents range in depth from about 1500 m to 3200 m below the surface. What is the gauge pressure at a 3200-m deep vent, assuming that the density of water does not vary? Express your answer in pascals and atmospheres.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.