/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 The surface pressure on Venus is... [FREE SOLUTION] | 91Ó°ÊÓ

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The surface pressure on Venus is 92 atm, and the acceleration due to gravity there is 0.894g. In a future exploratory mission, an upright cylindrical tank of benzene is sealed at the top but still pressurized at 92 atm just above the benzene. The tank has a diameter of 1.72 m, and the benzene column is 11.50 m tall. Ignore any effects due to the very high temperature on Venus. (a) What total force is exerted on the inside surface of the bottom of the tank? (b) What force does the Venusian atmosphere exert on the outside surface of the bottom of the tank? (c) What total inward force does the atmosphere exert on the vertical walls of the tank?

Short Answer

Expert verified
(a) 21632832 N; (b) 21632832 N; (c) 579546675 N.

Step by step solution

01

Calculate the total force exerted on the bottom inside surface of the tank

To find the total force exerted on the bottom inside surface of the tank, we need to consider both the force due to the pressure of benzene and the pressure from the gas inside at 92 atm. First, calculate the area of the bottom of the tank:\[ A = \pi \left(\frac{d}{2}\right)^2 = \pi \left(\frac{1.72}{2}\right)^2 \approx 2.32 \, \text{m}^2 \]The pressure inside is 92 atm. Convert this to Pascals:\[ 1 \, \text{atm} = 101325 \, \text{Pa}, \, \text{so} \, 92 \, \text{atm} = 92 \times 101325 \, \text{Pa} = 9317100 \, \text{Pa} \]Calculate the force from this pressure:\[ F_{\text{inside}} = P_{\text{inside}} \times A = 9317100 \, \text{Pa} \times 2.32 \, \text{m}^2 \approx 21632832 \, \text{N} \]
02

Calculate the force exerted by the Venusian atmosphere on the outside surface

The pressure from the Venusian atmosphere is 92 atm, which we've already converted to Pascals in the previous step. This atmospheric pressure acts on the bottom outside of the tank with the same area:\[ F_{\text{outside\_atm}} = P_{\text{atm}} \times A = 9317100 \, \text{Pa} \times 2.32 \, \text{m}^2 \approx 21632832 \, \text{N} \]Thus, the force exerted by the outside atmospheric pressure on the tank's bottom is also 21632832 N.
03

Calculate the total inward force exerted by the atmosphere on the vertical walls

The vertical walls have pressure exerted by the atmosphere around them at all heights. To find the total force, consider the pressure times the surface area of the sides of the cylinder:First, calculate the lateral surface area of the cylinder (excluding top and bottom):\[ A_{\text{vertical}} = \text{circumference} \times \text{height} = \pi \times d \times h = \pi \times 1.72 \, \text{m} \times 11.50 \, \text{m} \approx 62.19 \, \text{m}^2 \]Calculate the force from the atmospheric pressure on this area:\[ F_{\text{vertical}} = P_{\text{atm}} \times A_{\text{vertical}} = 9317100 \, \text{Pa} \times 62.19 \, \text{m}^2 \approx 579546675 \, \text{N} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Surface Pressure
Surface pressure is an important concept in fluid mechanics, especially when considering atmospheric conditions on different planets. It refers to the force exerted by the atmosphere on a surface per unit area. On Venus, the surface pressure is about 92 atm, substantially higher than Earth's average of 1 atm. This high pressure affects the force calculations on structures built on Venus.
Pressure, often measured in atmospheres (atm) or Pascals (Pa), is fundamental in determining the forces experienced by submerged or exposed surfaces. The higher the pressure, the more force exerted. In our exercise, surface pressure plays a critical role as it determines the forces exerted on the walls and bottom of the cylindrical tank both internally and externally.
To convert atmospheric pressure to a more commonly used unit like Pascals, remember that 1 atm is equivalent to 101,325 Pa. This conversion is crucial for calculating forces when using standard SI units.
Cylindrical Tank
A cylindrical tank is a common structure used for storing liquids, typically characterized by its circular base and uniform height. In problems involving fluid mechanics, it is crucial to determine the dimensions and surface areas involved.
To find the force exerted on or by the tank, you need to calculate the area of its surfaces. For the bottom, the area is \(A = \pi\left(\frac{d}{2}\right)^2\), where \(d\) is the diameter. For the vertical walls, the lateral surface area is calculated as \(A_{vertical} = \pi \times d \times h\), where \(h\) is the height of the cylinder.
Understanding these calculations helps in assessing how pressures applied both inside and outside the tank affect its structural integrity. The forces calculated are essential for ensuring that the tank can withstand the internal liquid pressure as well as external atmospheric forces.
Venusian Atmosphere
The Venusian atmosphere is uniquely challenging due to its extreme conditions, including a very high surface pressure of about 92 atmospheres. This thick atmosphere, composed mostly of carbon dioxide, exerts significant force on any exposed object, making engineering tasks on the planet complex.
When designing missions or equipment for Venus, understanding this pressure is vital for calculating how much force the atmosphere places on objects. This helps in determining whether materials can withstand the substantial pressures without deforming.
For any tank like in our exercise, both internal and external pressure calculations are influenced by the Venusian atmospheric conditions. This highlights the need for robust engineering approaches for successful operations in such alien environments.
Acceleration due to Gravity
Acceleration due to gravity on a planet affects how the weight of a fluid translates to force on a surface. On Venus, this acceleration is 0.894 times that of Earth's gravity (where \(g = 9.81 \, \text{m/s}^2\)).
Understanding gravity's effect is crucial in solving problems related to fluids and forces. It informs the calculations for the weight of the liquid column within the tank. The weight of the fluid contributes to the total force experienced by the bottom of the tank.
This concept also intertwines with pressure calculations because the gravitational force affects the overall pressure exerted by a fluid column. Grasping this relationship is critical for accurate predictions and for beginning to understand the dynamics of operating on different planetary bodies like Venus.

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Most popular questions from this chapter

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