/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 A solid ball is released from re... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A solid ball is released from rest and slides down a hillside that slopes downward at 65.0\(^\circ\) from the horizontal. (a) What minimum value must the coefficient of static friction between the hill and ball surfaces have for no slipping to occur? (b) Would the coefficient of friction calculated in part (a) be sufficient to prevent a hollow ball (such as a soccer ball) from slipping? Justify your answer. (c) In part (a), why did we use the coefficient of static friction and not the coefficient of kinetic friction?

Short Answer

Expert verified
(a) \( \mu_s \approx 0.65 \); (b) No, a higher friction coefficient is needed; (c) Static friction prevents slipping.

Step by step solution

01

Understand the Forces Acting on the Ball

A solid ball is experiencing gravitational force and frictional force when sliding down the hill. We need to consider these forces to determine whether the ball will slip or not.
02

Determine the Condition for No Slipping

For the ball to roll without slipping, the torque caused by static friction needs to provide enough rotational acceleration. We use this condition to find the minimum coefficient of static friction: \( f_s = mg \sin(\theta) - ma \), where \( a \) is the linear acceleration and \( \theta = 65.0^\circ \).
03

Apply the Rotational Motion Equations

The torque due to static friction is \( \tau = f_s R = I \alpha \), where \( I = \frac{2}{5}mR^2 \) is the moment of inertia of a solid sphere, \( R \) is radius, and \( \alpha \) is the angular acceleration related to linear acceleration as \( a = R \alpha \).
04

Relate Linear and Angular Acceleration

Since \( a = R \alpha \), substitute in previous step: \( f_s = \frac{2}{5}mg \sin(\theta) \). Set this equal to the gravitational force component to solve for \( \mu_s \): \( \mu_s = \frac{f_s}{mg \cos(\theta)} \).
05

Compute the Minimum Coefficient of Static Friction

Calculate \( \mu_s \): \( \mu_s = \frac{1}{3}\tan(\theta) = \frac{1}{3} \tan(65.0^\circ) \approx 0.65 \). This is the minimum coefficient required for no slipping (Part a).
06

Consider a Hollow Ball

For a hollow sphere, the moment of inertia is different \( I = \frac{2}{3}mR^2 \), which increases the required static friction. With the same \( \mu_s = 0.65 \), the torque condition will cause slipping (Part b).
07

Explain the Use of Static Friction

Static friction is used because it's applicable when surfaces are not moving relative to each other. It prevents initial slipping (Part c).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Motion
Rotational motion is an integral part of understanding how objects move when they roll down a surface without slipping. When an object such as a ball rotates, it moves around its own axis while simultaneously progressing along a path. In the context of a ball rolling down a hill, its motion is a combination of translation (movement down the slope) and rotation (spinning around its center).
Rotational motion in our exercise also involves different types of forces:
  • Gravitational Force: Pulls the ball down the slope towards the Earth's center.
  • Frictional Force: Acts opposite to the direction of sliding, allowing rotation instead of slipping.
  • Torque: A measure of the rotational force applied to the ball due to friction.
Understanding these elements helps us grasp why the ball can potentially roll without slipping. The friction needs to be sufficiently strong to create the torque necessary to drive this rotational motion. This sets up conditions that allow us to use rotational motion equations to solve for the required coefficient of static friction.
Moment of Inertia
The moment of inertia is crucial when discussing objects in rotational motion. It represents the distribution of mass in relation to the rotational axis, affecting how easily an object can be spun around that axis. For a solid sphere, such as the solid ball in our exercise, the moment of inertia is given by the formula:\[ I = \frac{2}{5}mR^2 \]Here, \( m \) is the mass and \( R \) is the radius.
When dealing with a different object shape, like a hollow sphere (e.g., a soccer ball), the moment of inertia changes to:\[ I = \frac{2}{3}mR^2 \]This higher value indicates that a hollow sphere has more mass distributed further from its axis, requiring more torque to achieve the same angular acceleration.
Understanding how the moment of inertia affects rolling motion allows us to compare different objects. It explains why the hollow ball needs a higher static friction coefficient to avoid slipping, illustrating the impact of moment of inertia on rotational dynamics.
Linear Acceleration
Linear acceleration refers to the rate of change of velocity of an object moving along a straight path. In the scenario where a ball rolls down a hill, it includes both the acceleration due to gravity along the slope and the effects of rotational motion. The linear acceleration \( a \) is tied to the angular acceleration \( \alpha \) through the radius of the ball:\[ a = R \alpha \]This relationship shows how rotational and linear motions are interdependent.
While gravity imparts an acceleration component along the slope, it is friction that dictates how much of that gravitational acceleration is converted into rotational motion instead of just sliding down. The equation used to describe this relationship \( f_s = mg \sin(\theta) - ma \) helps us determine under which conditions rolling without slipping occurs. This calculation hinges on establishing equilibrium between the forces involved to ensure that the static friction is sufficient to allow for combined linear and rotational acceleration without loss of traction.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Under some circumstances, a star can collapse into an extremely dense object made mostly of neutrons and called a \(neutron star\). The density of a neutron star is roughly 10\(^{14}\) times as great as that of ordinary solid matter. Suppose we represent the star as a uniform, solid, rigid sphere, both before and after the collapse. The star's initial radius was 7.0 \(\times 10^5\) km (comparable to our sun); its final radius is 16 km. If the original star rotated once in 30 days, find the angular speed of the neutron star.

A 55-kg runner runs around the edge of a horizontal turntable mounted on a vertical, frictionless axis through its center. The runner's velocity relative to the earth has magnitude 2.8 m/s. The turntable is rotating in the opposite direction with an angular velocity of magnitude 0.20 rad/s relative to the earth. The radius of the turntable is 3.0 m, and its moment of inertia about the axis of rotation is 80 kg \(\cdot\) m\(^2\). Find the final angular velocity of the system if the runner comes to rest relative to the turntable. (You can model the runner as a particle.)

A 15.0-kg bucket of water is suspended by a very light rope wrapped around a solid uniform cylinder 0.300 m in diameter with mass 12.0 kg. The cylinder pivots on a frictionless axle through its center. The bucket is released from rest at the top of a well and falls 10.0 m to the water. (a) What is the tension in the rope while the bucket is falling? (b) With what speed does the bucket strike the water? (c) What is the time of fall? (d) While the bucket is falling, what is the force exerted on the cylinder by the axle?

A hollow, spherical shell with mass 2.00 kg rolls without slipping down a 38.0\(^\circ\) slope. (a) Find the acceleration, the friction force, and the minimum coefficient of friction needed to prevent slipping. (b) How would your answers to part (a) change if the mass were doubled to 4.00 kg?

A diver comes off a board with arms straight up and legs straight down, giving her a moment of inertia about her rotation axis of 18 kg \(\cdot\) m\(^2\). She then tucks into a small ball, decreasing this moment of inertia to 3.6 kg \(\cdot\) m\(^2\). While tucked, she makes two complete revolutions in 1.0 s. If she hadn't tucked at all, how many revolutions would she have made in the 1.5 s from board to water?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.