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Electric Drill. According to the shop manual, when drilling a 12.7 -mm- diameter hole in wood, plastic, or aluminum, a drill should have a speed of 1250 rev/min. For a 12.7 -mm diameter drill bit turning at a constant 1250 \(\mathrm{rev} / \mathrm{min}\) , find (a) the maximum linear speed of any part of the bit and (b) the maximum radial acceleration of any part of the bit.

Short Answer

Expert verified
Maximum speed: 0.831 m/s; maximum acceleration: 108.8 m/s².

Step by step solution

01

Understand the Problem

We need to find the maximum linear speed and maximum radial acceleration of a drill bit with a diameter of 12.7 mm rotating at 1250 revolutions per minute.
02

Convert Diameter to Radius

The radius of the drill bit is half of the diameter. Since the diameter is 12.7 mm, the radius is \( \frac{12.7}{2} = 6.35 \ \text{mm} \). Convert this to meters by dividing by 1000, giving us \( 0.00635 \ \text{m} \).
03

Calculate Linear Speed

The linear speed \( v \) is calculated using \( v = \omega r \), where \( \omega \) is the angular speed in rad/s. First, convert the rotation speed from rev/min to rad/s: \( \omega = 1250 \times \frac{2\pi}{60} \approx 130.9 \ \text{rad/s} \). Then, \( v = 130.9 \times 0.00635 = 0.831 \ \text{m/s} \).
04

Calculate Radial Acceleration

The radial (centripetal) acceleration \( a_c \) is calculated using \( a_c = \omega^2 r \). Using \( \omega = 130.9 \ \text{rad/s} \) and \( r = 0.00635 \ \text{m} \), \( a_c = 130.9^2 \times 0.00635 \approx 108.8 \ \text{m/s}^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Speed
Linear speed is an important concept when dealing with rotating objects. It refers to the actual speed that a point on the object travels as it moves along its circular path. In the context of a drill bit, linear speed describes how fast the edge of the drill bit travels as it rotates. This is crucial because it affects how efficiently the drill can cut through materials.

To find the linear speed (\(v\)), you use the formula:
  • \[ v = \omega \times r \]
where \(\omega\) is the angular speed in radians per second, and \(r\) is the radius of the circle made by the rotating bit. First, the conversion of angular speed from revolutions per minute (rev/min) to radians per second (rad/s) is necessary, which involves multiplying by \(2\pi\) and dividing by 60. For instance, if a drill spins at 1250 rev/min, this translates to approximately 130.9 rad/s.

Next, calculate the linear speed by multiplying this angular speed by the radius of the drill bit. If the radius is 0.00635 meters, the linear speed is \(0.831 \text{ m/s}\). This value indicates how fast the outermost point of the drill bit is cutting through the material.
Radial Acceleration
Radial acceleration, also known as centripetal acceleration, is the acceleration that points towards the center of the circle of motion. It is essential in keeping the rotating object on its circular path. For a drill bit, understanding radial acceleration helps in knowing the forces involved in keeping each part of the drill bit moving in a circle.

This acceleration can be calculated using the formula:
  • \[ a_c = \omega^2 \times r \]
where \(a_c\) is the radial acceleration, \(\omega\) is the angular speed, and \(r\) is the radius. Using the same angular speed of 130.9 rad/s and a radius of 0.00635 meters, the radial acceleration of the drill is calculated as approximately \(108.8 \text{ m/s}^2\).

This high acceleration indicates a strong inward force keeping the drill bit in a circular path as it rotates, which is fundamental for ensuring stability and effective drilling operations.
Centripetal Force
Centripetal force is the net force acting on an object to make it move in a curved path, like a circle. Even though the term 'centripetal force' wasn't directly calculated in the exercise, it’s closely related to both linear speed and radial acceleration by maintaining the circular motion.

The force is directed towards the center of the circle around which the object is moving. For any rotating object, including a drill bit, the centripetal force is crucial for ensuring that all parts of the object remain on their path.

While the specific calculation of this force wasn't covered directly, the formula used relates to mass and radial acceleration:
  • \[ F_c = m \times a_c \]
where \(F_c\) is the centripetal force, \(m\) is the mass of the object, and \(a_c\) is the radial acceleration. Although the exercise doesn’t provide the mass, this formula outlines how centripetal force ensures the proper motion of the drill bit. As the radial acceleration increases, a greater force is required to maintain the circular motion, which is kept in balance by the centripetal force exerted by the drill mechanism on the bit.

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