Chapter 9: Problem 23
A flywheel with a radius of 0.300 \(\mathrm{m}\) starts from rest and accelerates with a constant angular acceleration of 0.600 \(\mathrm{rad} / \mathrm{s}^{2}\) . Compute the magnitude of the tangential acceleration, the radial acceleration, and the resultant acceleration of a point on its rim (a) at the start; (b) after it has turned through \(60.0^{\circ} ;(\mathrm{c})\) after it has turned through \(120.0^{\circ} .\)
Short Answer
Step by step solution
Identify Tangential Acceleration
Calculate Radial Acceleration at the Start
Calculate Resultant Acceleration at the Start
Determine Angular Velocity after 60° Turn
Calculate Radial Acceleration after 60° Turn
Calculate Resultant Acceleration after 60° Turn
Determine Angular Velocity after 120° Turn
Calculate Radial Acceleration after 120° Turn
Calculate Resultant Acceleration after 120° Turn
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Angular Acceleration
In our exercise, the flywheel begins at rest and is subjected to a constant angular acceleration of \(0.600 \, \mathrm{rad/s^2}\). This means that the rotational speed is steadily increasing as time passes.
- To find tangential acceleration from angular acceleration, we multiply it by the radius of rotation (\( r \)).
- This gives a consistent tangential acceleration \( a_t = r \times \alpha = 0.300 \times 0.600 = 0.180 \, \mathrm{m/s^2} \) for any point on the rim of the flywheel.
Tangential Acceleration
It's calculated by the simple product of radius and angular acceleration: \( a_t = r \times \alpha \). With a constant angular acceleration and known radius, tangential acceleration, for the flywheel, remains constant at \(0.180 \, \mathrm{m/s^2}\).
This value is key for any point on a rotating object since it contributes directly to the 'feeling' of acceleration, or how fast that point seems to travel circularly.
- Even when the flywheel's angular velocity increases, the tangential acceleration remains the same, since it depends only on the constant angular acceleration and the radius.
- In rotational systems, tangential acceleration helps in calculating the necessary forces to achieve desired motion.
Radial Acceleration
Mathematically, radial acceleration is given by \( a_r = r \cdot \omega^2 \), where \( \omega \) is the angular velocity.
Initially, at the start, because the flywheel just starts rotating and \( \omega = 0 \), the radial acceleration is zero. As the flywheel turns \(60^\circ\) and later \(120^\circ\), \( \omega \) increases and consequently so does \( a_r \):
- After \(60^\circ\), \( a_r = 0.602 \, \mathrm{m/s^2} \).
- After \(120^\circ\), \( a_r = 0.962 \, \mathrm{m/s^2} \).