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An airplane propeller is rotating at 1900 rpm (rev/min). (a) Compute the propeller's angular velocity in rad/s. (b) How many seconds does it take for the propeller to turn through \(35^{\circ} ?\)

Short Answer

Expert verified
(a) 199.50 rad/s; (b) 0.00314 seconds.

Step by step solution

01

Convert RPM to Radians per Second

To convert the angular velocity from rpm (revolutions per minute) to rad/s (radians per second), we use the fact that one revolution is equal to \(2\pi\) radians and there are 60 seconds in a minute. Therefore, the conversion factor is \(\frac{2\pi}{60}\). The angular velocity in rad/s is given by: \[ \omega = 1900 \times \frac{2\pi}{60} \] Calculate the value to find the angular velocity in rad/s.
02

Calculate the Angular Velocity

Perform the multiplication to find the angular velocity:\[ \omega = 1900 \times \frac{2\pi}{60} = 1900 \times \frac{\pi}{30} = \frac{1900\pi}{30} \] Simplify to get: \[ \omega \approx 199.50 \text{ rad/s} \] So, the angular velocity of the propeller is approximately \(199.50 \text{ rad/s}\).
03

Convert Degrees to Radians

To find out how many seconds it takes for the propeller to turn through \(35^{\circ}\), first convert degrees to radians using the conversion factor \(\frac{\pi}{180}\). Thus, \[ 35^{\circ} = 35 \times \frac{\pi}{180} \] Perform the multiplication to calculate this value.
04

Calculate the Angle in Radians

Calculate the angle in radians:\[ 35 \times \frac{\pi}{180} = \frac{35\pi}{180} = \frac{7\pi}{36} \] Thus, the angle is \(\frac{7\pi}{36} \) radians.
05

Use Angular Velocity to Find Time

Using the formula \(\theta = \omega t\) where \(\theta\) is the angle in radians and \(\omega\) is the angular velocity, solve for time \(t\):\[ t = \frac{\theta}{\omega} = \frac{\frac{7\pi}{36}}{199.50} \] Calculate \(t\) to find the time it takes for the propeller to rotate through \(35^{\circ}\).
06

Calculate the Time for Rotation

Perform the calculation for time:\[ t = \frac{\frac{7\pi}{36}}{199.50} \approx 0.00314 \text{ seconds} \] Thus, it takes approximately 0.00314 seconds for the propeller to turn through \(35^{\circ}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radians per Second
When discussing angular velocity, you'll often encounter the term "radians per second." This is a way to measure how quickly something, like a propeller, rotates. Angular velocity tells us how fast an object spins in terms of radians, rather than full revolutions or degrees.
To convert any given speed in revolutions per minute (rpm) to radians per second, we need to remember a couple of key points:
  • One complete revolution is equal to \(2\pi\) radians.
  • There are 60 seconds in a minute.
Therefore, the conversion from rpm to radians per second is done using the formula:\[\omega = \text{rpm} \times \frac{2\pi}{60}\]This formula allows you to change the unit of speed from a count of full rotations every minute to a more precise measurement that fits within the context of angles and circular motion.
Degrees to Radians Conversion
Converting degrees to radians is a fundamental concept when dealing with circular motion. In many problems, you might find angles given in degrees, but since many formulas in physics require radians, a conversion is necessary.
Here’s what you need to know about this conversion:
  • A full circle is \(360^{\circ}\), which is equivalent to \(2\pi\) radians.
  • The conversion factor is \(\frac{\pi}{180}\).
To convert an angle in degrees to radians, multiply the degree measure by \(\frac{\pi}{180}\). For example, to convert \(35^{\circ}\) to radians, you calculate:\[35^{\circ} \times \frac{\pi}{180} = \frac{35\pi}{180}\]This gives you the angle in radians, essential for calculations involving angular velocity or displacement.
Angular Displacement
Angular displacement refers to the angle through which a point, line, or body has been rotated in a specified sense about a specified axis. It's often measured in radians.
When you're trying to find out how long it takes for something like a propeller to turn through a specific angle, you’re dealing with angular displacement.
Here’s how angular displacement ties into other concepts:
  • The formula \(\theta = \omega t\) helps you find the time \(t\) it takes for a given angular displacement \(\theta\) when you know the angular velocity \(\omega\).
  • This formula can be rearranged to find any of the three variables if the other two are known.
For example, when you know the propeller’s angular velocity is approximately \(199.50 \text{ rad/s}\) and the angle it turns through is \(35^{\circ}\) (converted to radians), you can solve for the time it takes to make that rotation. This insight helps in understanding both the motion and the time involved.

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Most popular questions from this chapter

A cylinder with radius \(R\) and mass \(M\) has density that increases linearly with distance \(r\) from the cylinder axis, \(\rho=\alpha r\) where \(\alpha\) is a positive constant. (a) Calculate the moment of inertia of the cylinder about a longitudinal axis through its center in terms of \(M\) and \(R .\) (b) Is your answer greater or smaller than the moment of inertia of a cylinder of the same mass and radius but of uniform density? Explain why this result makes qualitative sense.

The flywheel of a gasoline engine is required to give up 500 \(\mathrm{J}\) of kinetic energy while its angular velocity decreases from 650 \(\mathrm{rev} / \mathrm{min}\) to 520 \(\mathrm{rev} / \mathrm{min}\) . What moment of inertia is required?

A thin, rectangular sheet of metal has mass \(M\) and sides of length \(a\) and \(b .\) Use the parallel-axis theorem to calculate the moment of inertia of the sheet for an axis that is perpendicular to the plane of the sheet and that passes through one corner of the sheet.

A vacuum cleaner belt is looped over a shaft of radius 0.45 \(\mathrm{cm}\) and a wheel of radius 1.80 \(\mathrm{cm} .\) The arrangement of the belt, shaft, and wheel is similar to that of the chain and sprockets in Fig. \(Q 9.4 .\) The motor turns the shaft at 60.0 \(\mathrm{rev} / \mathrm{s}\) and the moving belt turns the wheel, which in turn is connected by another shaft to the roller that beats the dirt out of the rug being vacuumed. Assume that the belt doesn't slip on either the shaft or the wheel. (a) What is the speed of a point on the belt? (b) What is the angular velocity of the wheel, in rad/s?

A slender rod with length \(L\) has a mass per unit length that varies with distance from the left end, where \(x=0\) , according to \(d m / d x=\gamma x,\) where \(\gamma\) has units of \(\mathrm{kg} / \mathrm{m}^{2}\) . (a) Calculate the total mass of the rod in terms of \(\gamma\) and \(L .\) (b) Use Eq. \((9.20)\) to calculate the moment of inertia of the rod for an axis at the left end, perpendicular to the rod. Use the expression you derived in part (a) to express \(I\) in terms of \(M\) and \(L .\) How does your result compare to that for a uniform rod? Explain this comparison. (c) Repeat part (b) for an axis at the right end of the rod. How do the results for parts (b) and (c) compare? Explain this result.

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