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On a horizontal surface, a crate with mass 50.0 \(\mathrm{kg}\) is placed against a spring that stores 360 \(\mathrm{J}\) of energy. The spring is released, and the crate slides 5.60 \(\mathrm{m}\) before coming to rest. What is the speed of the crate when it is 2.00 \(\mathrm{m}\) from its initial position?

Short Answer

Expert verified
The speed of the crate at 2.00 m is calculated using energy conservation principles and friction work.

Step by step solution

01

Understand the Situation

A crate placed against a compressed spring has mass 50.0 kg, and once the spring is released, the crate slides on a surface. The spring has stored 360 J of potential energy, and after a total distance of 5.60 m, the crate comes to rest. We need to determine its speed 2.00 m from the initial position.
02

Define Known Values

We know the following values: mass of crate, \( m = 50.0 \, \mathrm{kg} \), spring energy \( E = 360 \, \mathrm{J} \), sliding distance \( d = 5.60 \, \mathrm{m} \), and distance to find speed \( x = 2.00 \, \mathrm{m} \).
03

Calculate Work Done by Friction

Since the crate comes to rest after 5.60 meters, all the spring's energy is used to overcome friction. So, the work done by friction \( W_f \) is equal to the initial potential energy: \( W_f = 360 \, \mathrm{J} \).
04

Calculate Friction Force

The work done by friction is equal to the friction force times the distance: \( W_f = f \cdot 5.60 \, \mathrm{m} \). Hence, the friction force \( f = \frac{360}{5.60} \, \mathrm{N} \).
05

Calculate Work Done by Friction Over 2.00 m

Using the friction force calculated, find the work done over 2.00 meters: \( W_{f, 2.00} = f \cdot 2.00 \, \mathrm{m} \).
06

Calculate Remaining Energy at 2.00 m

The remaining energy at 2.00 m is the initial energy minus the work done by friction over 2.00 m: \( E_{rem} = 360 \, \mathrm{J} - W_{f, 2.00} \).
07

Use Energy to Find Speed

The remaining energy is now in the form of kinetic energy: \( \frac{1}{2} m v^2 = E_{rem} \). Solve for \( v \), the speed of the crate after 2.00 meters: \( v = \sqrt{\frac{2 E_{rem}}{m}} \). Substitute the known values and solve for \( v \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy possessed by an object due to its motion. In this scenario, as the crate moves from the compressed spring, it gains kinetic energy. The kinetic energy can be expressed using the formula:
  • \( KE = \frac{1}{2} m v^2 \)
where \( m \) is mass, and \( v \) is velocity.
The speed of the crate is crucial because it helps us determine how the energy transforms as the crate moves. At 2.00 meters from the initial position, the crate transfers a portion of the spring's potential energy into kinetic energy. This speed quantifies how quickly the crate moves and thus how much kinetic energy it holds.
At this point, understanding kinetic energy involves calculating how much of the initial energy is still being used for movement at specific distances, like the 2.00 meters mentioned.
Potential Energy
Potential energy, in this context, is the energy stored in the spring when it is compressed. This energy is a form of mechanical energy and is often referred to as elastic potential energy. Before the spring is released, the potential energy is at its maximum.
The concept of potential energy is key here because it represents the total amount of energy available to be converted into other forms as the crate moves. With the spring's stored energy calculated as 360 Joules, this figure sets the initial energy level of the system.
When the spring releases, some of this potential energy converts into kinetic energy as the crate starts moving, increasing its speed, until other forces, like friction, counteract and reduce the motion.
Friction Force
As the crate slides on a horizontal surface, friction plays a significant role in energy transformation. Friction is the resistive force that opposes motion, converting kinetic and potential energy into thermal energy, resulting in a loss of energy usable for motion.
The work done by friction, \( W_f \), is calculated over the entire path of motion, being directly proportional to the distance the crate slides:
  • \( W_f = f \cdot d \)
Where \( f \) is the friction force and \( d \) is the distance.
In our problem, the frictional force is calculated by equating the total work done by friction over the slide's entire distance to the initial energy stored in the spring. This determines how much of the initial energy is lost due to friction over specific intervals of motion, like 2.00 meters.
Spring Energy
Spring energy, or elastic potential energy, is the primary source of the crate's motion energy. When compressed, a spring stores energy that can be rapidly released to do work, as illustrated in this scenario.
The stored spring energy is calculated when the spring is compressed and is given in our exercise as 360 Joules. This represents the total energy that could potentially be converted into kinetic energy, moving the crate and overcoming friction.
Understanding spring energy involves recognizing how it begins fully as potential energy. It diminishes as it transforms into kinetic energy, with some being "consumed" to counteract friction. The conversion efficiency dictates how far and fast an object can move when relying on stored spring energy.

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Most popular questions from this chapter

An empty crate is given an initial push down a ramp, starting with speed \(v_{0,}\) and reaches the bottom with speed \(v\) and kinetic energy \(K .\) Some books are now placed in the crate, so that the total mass is quadrupled. The coefficient of kinetic friction is constant and air resistance is negligible. Starting again with \(v_{0}\) at the top of the ramp, what are the speed and kinetic energy at the bottom? Explain the reasoning behind your answers.

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