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A 0.60 -kg book slides on a horizonal table. The kinetic friction force on the book has magnitude 1.2 \(\mathrm{N}\) . (a) How much work is done on the book by friction during a displacement of 3.0 \(\mathrm{m}\) to the left? (b) The book now slides 3.0 \(\mathrm{m}\) to the right, returning to its starting point. During this second 3.0 -m displacement, how much work is done on the book by friction? (c) What is the total work done on the book by friction during the complete round trip? (d) On the basis of your answer to part \((c),\) would you say that the friction force is conservative or nonconservative?Explain.

Short Answer

Expert verified
(a) -3.6 J, (b) -3.6 J, (c) -7.2 J, (d) Friction is nonconservative.

Step by step solution

01

- Understand Work Done by Friction

The work done by a force is given by the formula: \[ W = F_d \cdot d \cdot \cos(\theta) \]where \( W \) is the work done, \( F_d \) is the magnitude of force, \( d \) is the displacement, and \( \theta \) is the angle between the force and displacement directions. Since friction opposes the direction of displacement, \( \theta = 180^\circ \), and thus \( \cos(180^\circ) = -1 \).
02

- Calculate Work Done (a)

For the first part, the book is displaced 3.0 m to the left under the influence of friction. Using the work formula:\[ W = 1.2 \text{ N} \cdot 3.0 \text{ m} \cdot \cos(180^\circ) = 1.2 \text{ N} \times 3.0 \text{ m} \times (-1) = -3.6 \text{ J} \]So, the work done by friction is \(-3.6 \text{ J}\).
03

- Calculate Work Done (b)

Now, the book slides 3.0 m to the right. The force of friction still acts to the left, opposing the motion:\[ W = 1.2 \text{ N} \cdot 3.0 \text{ m} \cdot \cos(180^\circ) = 1.2 \text{ N} \times 3.0 \text{ m} \times (-1) = -3.6 \text{ J} \]Again, the work done by friction is \(-3.6 \text{ J}\).
04

- Total Work Done (c)

The total work done during the round trip is the sum of work done in both directions:\[ W_{\text{total}} = (-3.6 \text{ J}) + (-3.6 \text{ J}) = -7.2 \text{ J} \]
05

- Determine Conservative Nature (d)

A force is considered conservative if the total work done by the force around a closed path is zero. In this case, the total work done by friction over the round trip is \(-7.2 \text{ J}\), which is not zero. Therefore, friction is a nonconservative force.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nonconservative Forces
When we talk about forces in physics, we encounter two main types: conservative and nonconservative forces. Nonconservative forces, like friction, are forces in which the total work done depends on the path taken. In the problem, we identified friction as a nonconservative force because it does not return any energy back to the system. When work is done by a nonconservative force like friction, this energy is typically transformed into other forms, such as thermal energy.

Conservative forces, in contrast, keep energy within the system, like gravitational force. For example, if you lift a book and put it back down, the gravitational force does zero net work on the book, leaving the total mechanical energy unchanged. However, in our example with friction, after the complete round trip, the total work done on the book is -7.2 J. This non-zero work indicates that energy has been dissipated, distinguishing friction as nonconservative.

In summary, nonconservative forces:
  • Depend on the path taken rather than just the initial and final points.
  • Convert mechanical energy into other forms like heat.
  • Are exemplified by forces such as friction and air resistance.
Kinetic Friction
Kinetic friction is a type of friction that occurs when two surfaces slide past each other. Unlike static friction, which acts when objects are not moving relative to each other, kinetic friction only comes into play during active movement.

This frictional force always opposes the direction of motion and is governed by the formula:\[ f_k = \, \mu_k \, N \]where:
  • \( f_k \) is the kinetic frictional force,
  • \( \mu_k \) is the coefficient of kinetic friction, representing how rough or smooth the surfaces are, and
  • \( N \) is the normal force, which is the force perpendicular to the surfaces in contact.
In our example, the coefficient and normal force are consolidated into the given magnitude of 1.2 N.

Understanding kinetic friction helps explain why it consistently opposes motion, thus doing negative work (as shown by the calculation \(-3.6 \, \text{J}\)).

Overall, kinetic friction is important in mechanics:
  • It's essential in analyzing the work done in sliding movements.
  • It provides a counteracting force ensuring objects come to a stop.
  • Analyzing kinetic friction helps in efficiently designing systems involving moving parts.
Mechanics Problems
Mechanics problems involve analyzing physical entities under forces to predict their future motion. They are a fundamental part of physics. Understanding how work, energy, and forces operate gives insights into everyday phenomena and more complex systems like machinery.

The problem in the original exercise is a classic mechanics scenario involving friction, helping us engage with important physics concepts like work, force, and direction. The book's movement and the work done by friction illustrate how nonconservative forces impact energy transformations.

Such mechanics problems allow us to:
  • Apply formulas to real-world situations and find insights into energy conservation or dissipation.
  • Understand fundamental forces like friction and how they affect motion.
  • Predict outcomes based on our calculated understanding of physics.
By mastering these problems, students learn to simplify complex real-world systems and make informed predictions, especially useful in engineering and technology fields.

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Most popular questions from this chapter

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