/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 A slingshot will shoot a 10 -g p... [FREE SOLUTION] | 91Ó°ÊÓ

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A slingshot will shoot a 10 -g pebble 22.0 \(\mathrm{m}\) straight up. (a) How much potential energy is stored in the slingshot's rubberband? (b) With the same potential energy stored in the rubber band, how high can the slingshot shoot a \(25-\) g pebble? (c) What physical effects did you ignore in solving this problem?

Short Answer

Expert verified
(a) 2.156 J, (b) 8.8 m, (c) Ignored air resistance and energy losses.

Step by step solution

01

Analyze the Problem

In this exercise, we will use energy conservation principles to find out the potential energy stored in the slingshot's rubber band and the height a different pebble can achieve when shot with the same energy. Assume air resistance and friction are negligible.
02

Define Variables and Constants

First, note the following data: - Mass of the 10 g pebble: \( m_1 = 0.010 \text{ kg} \).- Height achieved by the 10 g pebble: \( h_1 = 22.0 \text{ m} \).- The gravitational acceleration is \( g = 9.8 \text{ m/s}^2 \).- Mass of the 25 g pebble: \( m_2 = 0.025 \text{ kg} \).
03

Calculate the Potential Energy Stored for the 10 g Pebble

The gravitational potential energy (PE) is given by the formula: \[ PE = mgh \]For the 10 g pebble, we have: \[ PE_1 = m_1 \times g \times h_1 = 0.010 \times 9.8 \times 22.0 \text{ J} \]Calculate this value to determine how much energy is stored in the rubber band.
04

Calculate Maximum Height for the 25 g Pebble

The potential energy stored in the rubber band is the same for both pebbles. Given the energy, calculate the maximum height \( h_2 \) for the 25 g pebble:\[ PE_2 = m_2 \times g \times h_2 = 2.156 \text{ J} \](since \( PE_1 = PE_2 \)).Solve for \( h_2 \) using: \[ 2.156 = 0.025 \times 9.8 \times h_2 \] Find \( h_2 \) by dividing \( PE_2 \) by \( m_2 \times g \).
05

Consider Ignored Effects

In solving this problem, we have ignored air resistance, friction in the rubber band, and any energy conversion losses such as sound or heat produced during the launch of the pebbles.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Potential Energy
Gravitational potential energy is the energy an object possesses due to its position relative to the Earth. When you lift an object, it gains potential energy which can be calculated using the formula \( PE = mgh \), where \( m \) is the mass of the object, \( g \) is the acceleration due to gravity, and \( h \) is the height above the ground. In the given physics problem, the slingshot imparts potential energy to the pebbles, enabling them to reach a certain height. Understanding this concept is crucial, as it allows you to determine how much energy is stored when an object is raised to a certain height. This energy can later be converted into other forms, such as kinetic energy, during the object's motion.
Kinetic Energy Conversion
Kinetic energy is the energy of motion. When potential energy is converted to kinetic energy, an object accelerates. The pebbles in the problem start stationary and gain kinetic energy as they ascend, reaching their highest point when all of the originally stored gravitational potential energy is converted. This conversion of energy exemplifies the law of conservation of energy: energy cannot be created or destroyed, only transformed from one form to another. Thus, understanding how potential energy converts to kinetic energy helps in solving problems where objects move, change speed, or alter their height. As you work with such problems, remember:
  • Energy is always conserved.
  • Potential energy at the start equals the kinetic energy at any point along the motion.
  • Higher objects possess more potential energy, providing more energy for kinetic conversion.
Negligible Air Resistance
Air resistance, also known as drag, is the force that opposes an object's movement through the air. However, in many physics problems, this factor is considered negligible to simplify calculations. In this exercise, ignoring air resistance allows us to focus on the core concepts of energy conservation without complicating the math. Although we assume air resistance is negligible, it's a significant factor in the real world, affecting fast-moving or lightweight objects considerably. By overlooking air resistance, students can better understand the foundational principles of energy transfer and gain clearer insights into how energy works in ideal, controlled scenarios.
Physics Problem-Solving
Solving physics problems involves a systematic approach. This helps in understanding the fundamental principles and applying them effectively. Here's a guide to approach physics problems like the one in this exercise:
  • Understand the Problem: Break down the question. Identify what is known and what needs to be solved.
  • List Given Information: Noting all relevant data such as mass, height, or any other constants.
  • Use Appropriate Equations: Select the formula that best applies. In this case, the potential energy formula \( PE = mgh \) is key.
  • Ignore Nonessential Factors: Like air resistance if specified, to simplify calculations and focus on vital components.
  • Solve Step-by-Step: Break the problem into manageable parts. This structured approach minimizes errors.
Mastering these steps enriches your problem-solving skills, a crucial ability in understanding and demystifying complex physics concepts.

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Most popular questions from this chapter

A system of two paint buckets connected by a lightweight rope is released from rest with the 12.0 -kg bucket 2.00 \(\mathrm{m}\) above the floor (Fig. \(\mathrm{P} 7.55 ) .\) Use the principle of conservation of energy to find the speed with which this bucket strikes the floor. You can ignore friction and the mass of the pulley.

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